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Great problem because it shows me that a very efficient technique for circles is to draw lines connecting centers to points of tangencies and to look for similar, congruent, or as in this problem, right triangles.Thanks a lot! 🙂
my pleasure. thank you bro😊
a= 2cm, b= 4cm, R=3cmPytagorean theorem twice:R² - r² = r² + [½(b-a)]²2r² = R² - 1² = 3²-1 = 8r= 2cm ; d= 4cm ( Solved √)
clear! thank you.
Great problem because it shows me that a very efficient technique for circles is to draw lines connecting centers to points of tangencies and to look for similar, congruent, or as in this problem, right triangles.
Thanks a lot! 🙂
my pleasure. thank you bro😊
a= 2cm, b= 4cm, R=3cm
Pytagorean theorem twice:
R² - r² = r² + [½(b-a)]²
2r² = R² - 1² = 3²-1 = 8
r= 2cm ; d= 4cm ( Solved √)
clear! thank you.