Professor Rogers makes the complex really simple, he is a "teacher" like few are in the university system which is plaged with professors with highly developed skills to do research but little aptitude for teaching, good on you Professor Peter Rogers !
Hi sir, i just subscribed your channel because you delivered very informative topic. Now, if you can do another example such as 6 lift station in different elevation and it will be discharge to the wastewater Treatment plant. Is it the same calculation using 2 point elevation? What about the pipe elevation the other lift station? Thank you.
Very nice explanation, flowrate should not be put in the list like "given" , it's the theoretical demand for that specific scenario, given term sounds like it's a reading from the design
He is writing on glass with his right hand and the video has been mirrored. Unless he has a very unusual shirt pocket, buttons and wears a watch on his left hand.
The vertical distance between fluid surface and pump intake is sometimes called suction head. So don't you also need to know the elevation of the pump intake to make sure your pump suction head is sufficient? Thanks.
Not sure how the friction factor 0.003 was calculated, but this value seems to be the Fanning friction factor based on my estimation. If this is the case, the head loss should times 4 as the friction in the equation should be the Darcy friction factor.
@7:18 you state "16.9m of friction loss"... should be 13.9m of friction loss and 3.0m to account for fluid velocity dynamic head..." that the pump has to overcome :)
Nice video. But this only dealt with the head of the pump. This did not deal with the length of the pipe that the pump has to flow the water through. How can we include the length of the pipe as well.
I think there is a mistake in the static head calculation. If you take the datum point at pump line, 150 m will be minus and 200 is positive, total static head will be 350 m.
How the f.ck did you come of with that flow required value? Really my client is going to ask he needs a pump that can do 0.244003522 m3/sec? Seriously.
I hate how they always start with given information and then jumps into calculation. Why not to make it real life and start with a scenario, explain the situation and then start calculation like you would do in real life. I have seen similar examples through out 4 years of schooling, in real life they are garbage... zero value.
Professor Rogers makes the complex really simple, he is a "teacher" like few are in the university system which is plaged with professors with highly developed skills to do research but little aptitude for teaching, good on you Professor Peter Rogers !
Short, to the point, yet an explanation that is crux of the entire fluid mechanics. Good Job!
Very well explained. Clear and simple - I was able to follow up. yay!
Magnific! What a lesson, I think I just mastered this subject because of how good this video is, well done!
Perfect. Nothing more to say. Thank you!
He sounds like Mr. Mackey with the mmmkay. I love it!
Thanks for the explanation.
outstanding ever explanation. from Ethiopia
I fuckin love you. Graduated with mech eng and needed this in my job!
This was great, please do more.
It helped me a lot,
greetings from brazil,
mechanical engineering
Thank you, great video
Great video, very informative
Hi sir, i just subscribed your channel because you delivered very informative topic. Now, if you can do another example such as 6 lift station in different elevation and it will be discharge to the wastewater Treatment plant. Is it the same calculation using 2 point elevation? What about the pipe elevation the other lift station? Thank you.
Very nice explanation, flowrate should not be put in the list like "given" , it's the theoretical demand for that specific scenario, given term sounds like it's a reading from the design
Thank you sir.
Does anyone wanna point out HE’S ACTUALLY WRITING MIRRORRED!!
Was viciously scrolling to see if anyone noticed lol
He is writing on glass with his right hand and the video has been mirrored. Unless he has a very unusual shirt pocket, buttons and wears a watch on his left hand.
Hi Prof
Why did you multiply the specific weight of oil with that of water in the power equation.
The vertical distance between fluid surface and pump intake is sometimes called suction head. So don't you also need to know the elevation of the pump intake to make sure your pump suction head is sufficient? Thanks.
Good example, excellent explanation but i barely see what you wrote on that mirror
So where does the value 9810 comes from and what is the specific weight ?
7m/s velocity for oil is insane
Excellent example.
Not sure how the friction factor 0.003 was calculated, but this value seems to be the Fanning friction factor based on my estimation. If this is the case, the head loss should times 4 as the friction in the equation should be the Darcy friction factor.
Thanks. Good explanation
Amazing video
what about the vapour of the liquid inside the pump, why that term has not been added
Excellent work
Hi, does the pump elevation matters? Or are we assuming the pump is installed at 150m ish? But 300m away from the pool?
Most of the time you can ignore suction height because when you're dealing with altitudes in the 100s of meters, a few cm really don't amount to much.
@7:18 you state "16.9m of friction loss"... should be 13.9m of friction loss and 3.0m to account for fluid velocity dynamic head..." that the pump has to overcome :)
thanks
Can I have the question of this answer please
I thought the pump should move the oil from a head of 150m up to a head of 200m. Making the total pump head to be 350m.?? A bit confused now.
where is the consideration of the limits of velocity and pressure drop
Thanks!
Good
Nice video. But this only dealt with the head of the pump. This did not deal with the length of the pipe that the pump has to flow the water through.
How can we include the length of the pipe as well.
the friction factor
Elevation at suction is 150M, Elevation at Discharge is 200M, Length of the pipe is 300M ???
Good work, minor mistake at the start where the diameter was squared instead of the radius to calculate the area
he used pi/4 so its correct to square the diameter. Area=(pi/4)(d^2) or Area= pi*r^2😊 Agree?
The diameter of pipe looks too small for that required flow since the calculated velocity is too high!
The pump should be rated by horsepower units!! HP
wtf how do u write mirrored
Dude this selection seems to be humongous for the given job..need some rechecking in my opinion 175 kw is huge size..
It could be Video is mirrored
@@fayazmohd1017 Well, for that head and power, something not right? but look have never done pumps for oil.
I think there is a mistake in the static head calculation. If you take the datum point at pump line, 150 m will be minus and 200 is positive, total static head will be 350 m.
No
no
How the f.ck did you come of with that flow required value? Really my client is going to ask he needs a pump that can do 0.244003522 m3/sec? Seriously.
I hate how they always start with given information and then jumps into calculation. Why not to make it real life and start with a scenario, explain the situation and then start calculation like you would do in real life. I have seen similar examples through out 4 years of schooling, in real life they are garbage... zero value.
This! I'm looking for real life problems. Not this perfect shit right here🙌
++