finding the critical numbers of t^(3/4)-2t^(1/4)

[@ThomasJohnMolnga]

Honestly, I'm impressed with your explanations ❤

[@DepFromDiscord]

Neat! I knew of zeros of a function, but not critical numbers!

[@Borgia1492]

Thank you, this explained it very well

[@pooluch]

Now I love it even more!

[@KingGisInDaHouse]

Hey I was experimenting with finding cubic functions that satisfy two critical points.
So say the functions critical points are (1,-1) and (0,5).
So we know
y’=a(x-1)(x-0)=a(x-1)x=ax^2+ax
$y’ dx = $ (ax^2 + ax) dx
y= ax^3/3 + (ax^2)/2 + C.
You have two initial values given to you just plug in your x and y coordinates and you get a simple 2 variable system of equations to solve for a and C and you can’t change a around and have both of the critical points satisfy the equation I’ve already tried. So theoretically every cubic that has critical points is uniquely identified by its critical points. Can you prove or disprove this.

[@tbg-brawlstars]

Umm...do you mean critical *points* of a function by critical numbers ?

[@bprpcalculusbasics]

Those terms are interchangeable

[@tbg-brawlstars]

@@bprpcalculusbasics Hmm

[@umarfayziev5235]

im the log2(2)=x to comment

[@lih3391]

Hi, "the one to comment"

[@volodymyrgandzhuk361]

@@lih3391 not the one, the first

[@Alians0108]

@@volodymyrgandzhuk361 Hi, "the one to comment"

[@0w0-i4o]

@@Alians0108 not the one, the first

[@Gutagi]

@@0w0-i4o Hi, “the one to comment”