Lec 93 - RRB JE/NTPC - GENERAL SCIENCE - MOTION & EQUATIONS OF MOTION | PROBLEMS

[@jeyaramkrishnasamy5211]

mam mind blowing explanation ..

[@priyamano2376]

Tqq mam....

[@krishnakumar.s6872]

Telling 2 times on important points is very good😊 thanks!

[@ECAbeyaantrix]

Thank u so much. Keep watching & enjoy learning.

[@kar789thi]

thanks

[@ECAbeyaantrix]

My pleasure pa. Keep learning.

[@surekas749]

thanq so much for ur video mam

[@ECAbeyaantrix]

My pleasure ma. Keep learning.

[@Nivetha-tx9jb]

30:42 distance/time = speed or velocity???????

[@jagadeshjack3758]

2.96m
3.12m

[@vigneshp4287]

Akka can u pls explain 5th problem for s=ut+1/2at????

[@rahulbabugv1469]

1) 11065.27 km/hr 2) 96 m 3) 12 m right mam?

[@ECAbeyaantrix]

Perfect pa. Very good. Keep learning.

[@rahulbabugv1469]

Thank u mam

[@udhayakumar4009]

Super and thank u mam please ur material upload panunga

[@ECAbeyaantrix]

Thank u so much. Keep watching & enjoy learning.

[@crazyvijay6537]

A man covers a distance of 6 km at the rate 4kmphr and other 4 km at the rate 3kmphr.
His AVG SPEED is

[@ECAbeyaantrix]

Average speed = Total distance / total time taken.
So, Total distance = 6+4=10 km.
Total time taken = (6/4) hrs + ( 4/3)hrs = (17/6) hrs.
Avg speed = 10/(17/6) = 60/17 kmph = 3.53 kmph.

[@balachandar7880]

Put videos for jumbling reasoning I am searching you tube some one not explain in tamil.. so i am watching Telugu videos .. kindly noted

[@ECAbeyaantrix]

Sure Stay tuned

[@balachandar7880]

Next videos?