Complete Functions | JEE 2023 |
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- Опубликовано: 10 окт 2024
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Vedantu Telugu brings you the JEE Maths session to prepare you for the upcoming JEE 2023 examination. Our Master Teacher Goutham sir will be discussing the Complete Functions - Kevalam 90 mins that will help you excel in your upcoming JEE 2023 exams.
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#jee2023 #jeemaths
Home work Answer is , x=+_√y/1+y
Then after y/1+y>=0 then using Wavy curve method That is (-infinity,-1)U[0, infinity)=R-[-1,0)
Perfect!
@@vedantutelugu @vedantutelugu
Thanks bro for giving hint
🎉
Akkada 0 ki enduku ')' ee bracket pertunnamu why not it can be '[ ' this pls clarify my doubt
Sir this is useful for 2024 preparing students
Obviously
Sir sorry to say that you have done a sum wrong at (20:11 ) you have taken square root condition but u not included logarithmic general condition ,inkoti sir manam chesthe answer radha ani dialogues veyyankandi manishi annaka thappu cheesthadu
Hi sir in 57:21 calculas method f`(x)>0 or f`(x)
@vedantu Telugu sir plzz chemistry Inka physics kuda elanti videos chesi playlist chesi petandi sir 😔😔😔plzz🙂🙂
Sir nice explaination really good but we want to hear some what clearly sir use karoo speaker sir gi
sir is this video helpfull for EAMCET also?
option : C R - [-1,0)
Jee mains syllabus cheppandi
Home work answer. C (_1,10)
SIR answer for this question is option c; R-[-1,0)
Home work question is option - c
Sir these lectures are enough to eamcet
Option c
Very good explanation 🎉
Sir this series include total jee syllabus ??
Sir 20 05 ki u have take square rootcondi tion but not included logarithmic general condition
home works question ans= C [-1,0}
Thank you sir ❤❤
Which reference books are best for jee mains
Try to avoid vedantu and try phy wallah
Happy National Mathematics day all of You ,The great Mathematician Srinivasa Ramanujan Birthday today .. 🔥🔥
It's shakuntala devi bday today
Sir can you tell differentiation
Pls sirr
Sir.. Plz don't start limits tmr.. Take one more class of functions to solve pyq plz sir to understand the chapter better... 🙏
Ilanti conceptual videos tho patu, PYQ videos kuda chestanu. Meru Rendu chuseyandi.
@@vedantutelugu SIR PLEASE ST IT FAST
WAITING FOR IT SIR
Sir meeru easy chapters chepparu kadha first aa classes cheppandi sir please
1:43:04 1:43:04
Sir f=(-2,1),(0,6),(2,-2) and g=(-2,4),(0,3),(2,8) then (2f/3g+3g/2f)(0)=?
Answer: 25/12 😅
Yes (or) no😅😅😅😊
Please tell 😢😢😢🎉
Option c
Conduct classes on eapcet and comedk entrance test in Karnataka
Super sir🎉🎉🎉🎉
What is the differentiation rule sir used in one-one function example problem
This will be help to emcet preparation plz reply Sir 🙏🙏
Sir plz do a video on integration also ...
Thank You Vedanthu ❤
f(x) =1/4-x^2+log10(x^3-x) =?
Trigonometric functions ki range cheppandi
Tq sir
Sir physics and chemistry classes kuda start cheyandi neet ki plzz sir
C
Second time differentiation cheyyavacha sir calculus method loo
c
please please Sir one more class for functions to do more problems
Sir pls 2024 mains kosam videos cheyara
40:50
Y = [ -1 , 0]
Sir please do video on permutations and combinatins
Tq sir❤❤
R-:(-1,0
Please cover all concepts
Sir malli ee topic ni fresh ga chepandi. Without skipping any point please
Sir, ami anukokapote wavy curve method explain cheyyara
Sir option (C) sir
Explain domain
Sir pls share the important questions in this chapter for practise
First ivvi cheyyamma thalli
Homework answer is option 3
Jee ki functions akkadidhi sets cheppandi bro 😑
A
Good morning sir
Sir deeniki sambandinchina objective questions appudu start chestaru
From next week.
Sir that class not useful for jee mains
Anna tell in one shot video one chapter eamcet and jee plzz don't make another video for eamcet only or jee mains only because I took eamcet if i listen eamcet then there is no time to waich again another video ABT that chapter only for jee so .. plzz tell anyone chapter tell eamcet and jee in one video only
sir plzz reply me is this videdo helpful for eamcet alsoo..?
Yes! But prepare according to the syllabus
B
Hi sir meeru relation topic cheppaledha sir
sir start btech classes also for atonomus ,it might be help ful for us
Me videos chudali ante freshers ki em ardam kavu sit
sir h.w answer option c R-[-1,0)
Perfect!
Sir odd function ki range enti
Sir meeru jee advance classes cheptara
Sir Physics and Chemistry faculty ni Hire chesi Videos Cheyandi sir...Time is very less and Time is Money.
Sir Questions cheyadam ravatlaa sir
Sir..mana hyd lo unnaya sir veedantu colleges😊❤🎉
Sir plzz keep time stamps
Mathematical induction chapadi please sirr
In map how c=2 sir
Sir plzz physics inka chemistry ki kuda elge video unte list chesi petandi
Hi sirrrr
Sir complete calculus kavali
C
Sir live chat open cheyandi doubt vosta adagadaniki bagundi
Sir ip kuda cover cheayandi sir
Sir ans for home work problem is option-c:R-[-1, 0)
Perfect!
Sir E class Pdf ni Telegram group lo upload cheyandi sir
Sir class 11 for jee advance questions solution for maths and physics and chemistry class
Please sir
Sir, These are the topics enough for mains examination.
Sir simple methods cheppandii sir please🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
😂😂😂😂😂😂
58:02 sir what sir 2 not sir that is 1 sir in differentiation sir d(const)is 0 sir😅
when a constant is multiplied with a variable u wont differentiate the constant instead you put the constant aside and differentiate the variable
Bro, d/dx(ax)=a
1:07:32.and1:20:36
Sir co-ordinate geometry
First need clear explain sir
1 k like
Phy sir
Oka cinema thiyyandi sir anthasepa
@vedantu Telugu
Conduct classes on eapcet and comedk entrance test in Karnataka
Option c
Tq sir❤
Tq sir
C
Option a
Conduct classes on eapcet and comedk entrance test in Karnataka