Aromatic, Antiaromatic, or Nonaromatic Practice Session #1
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- Опубликовано: 29 окт 2017
- This lesson examines multiple compounds to determine if they are aromatic, antiaromatic, or nonaromatic based on Huckel's Rule and other criteria.
How to Determine Aromaticity: • How to Determine Aroma...
Lone Pair sp2 Lecture: • Are Lone Pairs in Hybr...
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The AMOUNT OF CLARITY is insane!!!!! Thank you so much ❤
Wow after watching a bunch of videos, your video made the most sense. Thank you!!
Your explanation of the pi bond in the lone pairs 1 C away from a pi orbital just saved my exam grade lol
Best video on aromaticity. Made me understand it 100%.
at 12:23 it will be 3/2
👍🏼
Wonderfully explained! Cleared my concepts about aromaticity👌
highly recommend this video!!! I can do my homework problems now. Thank you
You are amazing !!! Final is on monday and you made this 10000 times easier. Thank u
5th compound n = 3/2
very very amazing and clear explanation
I was not able to understand what's the hybridisation of the charged carbon atoms but now I do thanks a lot
I can't explain how good your lectures are.❤❤
Thank you! I was super confused until I watched your videos.
Thank you so much for complete detailed information
great explanation !!
Thank you for the help.
wow thank you!! After the whole semester this finally makes sense before my final!!
Same situation
Great video!! on point❤
thank you very much it was really helpful and clear
BEST VIDEO !
thanks a lot for an easy explanation
Thank you!
thank you for this!
very helpful thank you !
Thank you
Thank youuuuu ❤ I’m finally cleared
Very helpful.... But sir we can also consider that delocalised lone pair are sp2 and localised lone pair sp3 and stays in hybrid orbital... So whenever we see any lone pair participating in resonance we can say it is sp2..
thanks so much! Hope you guys are able to push out more Orgo 2 videos haha
Good one
Nice video
Thanks
it was really helpful .Keep up ur momentum bro.
Thanks!
Thanks 🎉
You are literally one of the best organic chem teachers I've known
Thank you for the high compliment!
Big thanks for you, Sir.. Your videos help me a lot, especially for my lecture.. Once again thank you so much. :)
You are most welcome
I find that It's unnecessary to have it subtracted by 2 and find the n value. Simply check if the pi electron value is 4n or 4n+2. If it's the former then it's Antiaromatic, if it's latter then Aromatic. But very very helpful. Thanks!
Makes Sense
Thanks for this 🙏
No problem 👍
AMAZING
In furan how to jutch oxygen is sp2 hybridised ????
you're great
thank youuuu so much
You're welcome!
Great video, thanks a bunch. Quick question. My prof heavily emphasized planarity in his lecture on this topic. Any comments on planarity and it’s importance?
Hi Dominic, yes planarity is very important and required for aromaticity. The reason planar ring systems are so vital is that they allow for p-orbital overlap which leads to proper conjugation of pi electrons. When a ring fails to meet planar standards, it is classified as non-aromatic (not anti). An example of this is 1,3,5,7-Cyclooctatetraene. One would normally expect anti, but it is non-planar.
Good
good vid
please how do i easily know that a ring structure is going to be conjugated?
BLESS
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Organic is bussin
From what I’ve understood, wouldn’t the second to last molecule be non-aromatic since a molecule would rather remain non-aromatic rather than switch to anti-aromatic ?
that’s what i think too lol
We need part two on the,same topic with different structures. You are a GOD
4n=6 n=3/2
How the nitrogen atom is SP2 hybridized in last compound.
The lone pair is in resonance with the pi bonds. In order to participate in the delocalization of electrons, the nitrogen must keep a p-orbital for overlap purposes and therefore can only be sp2.
How know that aromatic is planar?
In last question how nitrogen is sp2 hybridised here ??plz clear confusion
The lone pair is in resonance with the pi bonds. In order to participate in the delocalization of electrons, the nitrogen must keep a p-orbital for overlap purposes and therefore can only be sp2.
I find your videos very helpful, but your intro music is very loud and hard on the ears especially with headphones on. Can you please consider changing it for future videos? Thanks for all your effort man!
You are using the same 4n + 2 formula for both aromatic and anti aromatic
4n +2 = Pi electrons is the formula for determining aromaticity (aromatic or anti)
algebra dude!
Why pyridine is marked not aromatic???
Pyridine is aromatic, it was also marked as such in the video!
Value of n in thio pyrane not correct