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Sir jo que tha(32^32^32)/7 .. ko 32^4/7 ko 2^20/7 likhne ke bad.. 20, 4 se pura divide ho jata h so 2^4/7 = 2 remender aarha h but ans 4 h esa kyo ho rha h muje smj nhi aarha Pls explain🙏🏻
@@anuragagarwal8675 mene power reduce krne wala video nhi dekha bt sayad last term ki power ho to reduce nhi krte kyuki sir ne phle bhi 1 -2 example me last term pr reduce nhi kiya ..
1st . 5 2nd . 2, 4, 0 3rd . If we put 10 then it will satisfy the given condition and hence remainder will be 4 If we put 24 then it will also satisfy condition and hence remainder will be 1 So I think CND will be the answer for that question
असफलता और सफलता दोनों ही अवस्थाओं में लोग तुम्हारी बातें करेंगे, सफल होने पर प्रेरणा के रूप में और असफल होने पर सीख के रूप में । All the best friends n thank you sahil sir
In the last question, if we assume the numbers 23,53, 83, 113 and so on.... all these numbers are satisfying the condition given in the question. But on dividing by 7 the remainder obtained is 2, 4, 6, 1... and so on... so i think the question has all the answers from 1 to 6.
THANKS SIR Aap bhut Acha pdate hai Agar Aap pdate hai or kisi ko smj me nhi Aata hai to Ise pta Chalta ki wh kuch nhi Janta kitna best pdate ho sir thankyou sir
Hello Sir........ Nyc method to solve all problem related aptitude........ above vedio is one year old but help me now because i m fresher to this.......u'r vedio very helpful to me ..nd i m like the way of your teaching techniques........very easily understanding........ Thanks you so much 🙏
Sir Am from southindia I can't understand hindi but watching ur session is very fruitful.please explain anyone in 2nd question how can say CND answer...
Not be determine ho hi nhi skta sir, kuchh to sesfal jarur bachega chahe 0 hi ku n ho, aur yadi ap bolte ki bhajak me dusre bhajak purn bhag lgna chahiye tabhi hm sesfal nikal skte hai dusre bhajak se bhag dekar to ye to hme bilkul bhi smjh se bahar hai Aesa ho hi nhi skta hai ki kisi purn sankhya ko ek purn sankhya se divide krne pr sesfal determine nhi kr skte hai
last wale hw question mai...0,1,3 ye sab remainders aa saktey hai...a^2+3 ke form main ayengey remainders where a is positive integer..eg if a=1 then remainder comes as 4...and again if a is 2 then remainder is 7/6 ie 1.and so on...so no answer can be determined for that i think...
Sir ye aap sahi bata rahe per sir pahle aap bataiye ki kisi sankhayamain 4 se bhag dene per 1 sheshfal aya per 5se bhag dene per 4 kaise sheshfal aya sir
Sir Mera ek doubt hamlog aisa bhi kar skate hein na divisor ko remainder mein add karkar other divisor se divide kare to find remainder jaisa ki homework question 899) 962(1 ------- 63 -------- 29) 962(33 Remainder is 5
@@gautam9269 4. 5. 6 |+\*|+\*|+ 2. 1. 1 Multiply kroge [{(6+1)*5}+1}*4]+2=146 146/6 to 24 times jayega aur Rem 2 bachega 24/5 to 4 times jayega aur Rem 4 4/4 Rem zero(0) Ayega 2, 4,0
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Sir jo que tha(32^32^32)/7 .. ko 32^4/7 ko 2^20/7 likhne ke bad.. 20, 4 se pura divide ho jata h so 2^4/7 = 2 remender aarha h but ans 4 h esa kyo ho rha h muje smj nhi aarha
Pls explain🙏🏻
Sir kis trh online set purchase kr skte h
@@anuragagarwal8675 2^20 aane pr power reduce nhi krenge bt 2^3 =8 k roop me bnayenge to remainder 4 aayga
@@nidhigupta4809 ha vo to me smj gya but power reduce krne wala method yha kyo nhi lga jbki yh method 2,3,7,8 pr lg jata h
@@anuragagarwal8675 mene power reduce krne wala video nhi dekha bt sayad last term ki power ho to reduce nhi krte kyuki sir ne phle bhi 1 -2 example me last term pr reduce nhi kiya ..
1st . 5
2nd . 2, 4, 0
3rd . If we put 10 then it will satisfy the given condition and hence remainder will be 4
If we put 24 then it will also satisfy condition and hence remainder will be 1
So I think CND will be the answer for that question
असफलता और सफलता दोनों ही अवस्थाओं में लोग तुम्हारी बातें करेंगे, सफल होने पर प्रेरणा के रूप में और असफल होने पर सीख के रूप में ।
All the best friends n thank you sahil sir
Thank you sir love you sir ap hum loge ke liye itne mehnat karte hai to Ek like to banti hai ap Bahut acche se samjhate hai maja a raha hai...........
Radhe Radhe sir Ji
Nice session
Sir mujhe apki vedio bhut accha lagti ha
Think you sir
In the last question, if we assume the numbers 23,53, 83, 113 and so on.... all these numbers are satisfying the condition given in the question. But on dividing by 7 the remainder obtained is 2, 4, 6, 1... and so on... so i think the question has all the answers from 1 to 6.
Question say minimum number so minimum no is 23 so correct answer is 2 remainder
Thank you sir Aap bahut achhi reading karate ho lot of love
Sir aap bhut accha padate h
1) 5
2) 2,4,0
3) Not Done..Try Kiya..but alag aa raha he..
Thanks sir 👍
4 hoga ans bhai
homework ans Q1 B 5
Q2 A 2,4,0
Q3 B 1 thanks sir 🙏🙏 awesome session
THANKS SIR Aap bhut Acha pdate hai Agar Aap pdate hai or kisi ko smj me nhi Aata hai to Ise pta Chalta ki wh kuch nhi Janta kitna best pdate ho sir thankyou sir
East and West---Sahil is best
Q1=5
Q2=2,4,0
Q3=1
Sir you r teaching so much better than other teachers sir apne bsc, msc kia hai ya btec mtec
Hello Sir........
Nyc method to solve all problem related aptitude........ above vedio is one year old but help me now because i m fresher to this.......u'r vedio very helpful to me ..nd i m like the way of your teaching techniques........very easily understanding........ Thanks you so much 🙏
❤️
Very nice class sir ap bahut aacha samghate ho
Thanks sir
WiFi study ki Shan aur hmari educational Life ki Jaan ho aap , love you sir and God bless you 😘😘😘😘
ऐसे गैर मर्द को love यु मत बोलिये फतवा आ जायेगा
Fatwa😂
I don't know What is Fatwa... If that's sounds something wrong... Then u are a son of Bitch... 😂😂😂
Fatva ,, Jari Hua🤣😁🤣😁🤣
Or kya Abbu manege 🤣😁🤣😁
24 multiply by 6gives144thaht means it gives remander of minuska2👍👍👍😀😀😀😀😀😎😎
sir practice k liye book suggest kijiye na
Sir aap bhut ache s smjhate h.thank you sir
Sir sach mai aap dil se padate ho..
sir aap bahot mehenat karte ho.main aapse bahot kuch sikh raha hu.aap ki bate lajawab.
Sir ap bahut mst padate ho but negative comment ko ignore kiya kro kr sir plzz jb ap khus rahte ho tbhi padne me bhi mza aata h
Love you sir
Sir thanks mera garibi ke life me ak asha ke kiran aap ke kaaran aae hai
Homework
1. 5
2. 2,4,0
3. 1
But q(3) is my doubt
Let take the number 10 when it is devided by 7= 3
Both are right but we have to go with respect to options by selecting various values of n= 1, 2.....
You are best teacher of the world
Sir Am from southindia I can't understand hindi but watching ur session is very fruitful.please explain anyone in 2nd question how can say CND answer...
899/29=31
63/29=1 remainder 5
Ans B is right sir
Thanks Guruji,,🙏💐 sab bahut acche se samhjh me aata h Guruji.
Sir classes lagane ki jarurat hi nahi aap bhut aache padhate ho thank you sir
H.w. Ans.
1. 5 (B)
2. 2 4 0 (A)
3. CND
Thanks sir ji to teach me
Sb smjh me aaya poori trh
Superb..... Superb..... Superb..... Excellent....Sir....!
H.w. Ans. 1. 5 2. 2,4,0 3. 0
Bahut khub...🙏🙏🙏🙏
Not be determine ho hi nhi skta sir, kuchh to sesfal jarur bachega chahe 0 hi ku n ho, aur yadi ap bolte ki bhajak me dusre bhajak purn bhag lgna chahiye tabhi hm sesfal nikal skte hai dusre bhajak se bhag dekar to ye to hme bilkul bhi smjh se bahar hai
Aesa ho hi nhi skta hai ki kisi purn sankhya ko ek purn sankhya se divide krne pr sesfal determine nhi kr skte hai
Bahut gajab sir maza aarha Hai pdhne me
Sir aapki class dekhi Bhaut achha laga love you sir.....
Sir Aap bahut Accha padate ho excellent sir
Dear sir, you teach same as Sandeep maheswri give us knowledge.thanks sir to help my preparation......
last wale hw question mai...0,1,3 ye sab remainders aa saktey hai...a^2+3 ke form main ayengey remainders where a is positive integer..eg if a=1 then remainder comes as 4...and again if a is 2 then remainder is 7/6 ie 1.and so on...so no answer can be determined for that i think...
#20:47 NICE trick sir..thank youuuuuuuuuuuuu
Thank u Sahil sir,
Hw ans.
1)5
2)2,4,0
Did u understood that tricky question...
18:05 one?
Thanku sir aapse pdne k bad maths me maja hi aa gya
Thank you sir bohat accha ❤
Sir ye aap sahi bata rahe per sir pahle aap bataiye ki kisi sankhayamain 4 se bhag dene per 1 sheshfal aya per 5se bhag dene per 4 kaise sheshfal aya sir
Sir aap bahut hi badiya study karte h
सच मे मस्त क्लास
Sir tussi great Ho 👍👍👍
Thanks sir
Aap padate rahe samaj aa raha h
Aap great ho sir
Best class sahil. Sir love you
Answer _5
Q2_1anser
Super guru ji best tarika
Jay shree radhey Krishna 🙏🙏
sir plzz practice k liye book recommend kijiye na
Awsmm sir
Sahil sir jaisa koi nahi padha sakta in the world.
Bhut khoob sir
Thnx Sir aaj tk math se dr lgta tha bt dheere Dheere sb smjh aane lga u r god for ME thnx sir
10:01
Samajhne wali bat h ki kya samjhna h
😂😂😂😂
Sir jab mai padhte padhte bor ho jati hu to aapka sayari wala video dekhleti hu and mind mast ho jata hai
Khudh se ho dear
Hw..1) 5
2) 2,4,0
3) cnd
Sir maaza aa gaya. Such me sir🙏
Q1-5. Q2-2,4,0... Q3-4
Sandar concept ka sat TV sir
Sir 25:19 par ans 2 hoga
Sir bahut badhiya
Q1-5
Q2-2,4,0
Q3-3( not confirmed about method)and [1]by other method
5 nd 2,4,0 nd 3 (sol)
Sir Mera ek doubt hamlog aisa bhi kar skate hein na divisor ko remainder mein add karkar other divisor se divide kare to find remainder jaisa ki homework question 899) 962(1
-------
63
--------
29) 962(33
Remainder is 5
Apne jo 5va ka shaval bataya h usme 142 ka bhagh karne per mera 196 aa raha hai
Bhai 37 mein jab 4 se divide karoge to remainder 1 aayega naa kii 3
Thankyou very much sahil sir
HW ANS 1-5 ANS2-2,4,0 ANS3-4
Thanku so much sir to clear my this topic❤❤
37 sbse choti sankhya kaise hui ??
Yes
Ans - 1=5
2=2,4,0
Hw
1-ans 5
2-ans 2,4,0
1st-5
2nd- 2,4,0
3rd- 3
Sir lekin aap phle bataye the ki jb divide pura n jaye to ans .0 aata h fir aap bole ki and hota h
Sir agar hma koi cheez na samag aha to aap hr bar kah data ho ki aap late aaya ho
Sir request hai aap us cheez ko dubara smza dizia
I can not understand your Language however ,I will understood your teaching
Dil se wishes niklti h aapke liye sir.
Thanks alot sir
Option B i.e 5 Ans
❤️❤️❤️
H.w ans are ..
1)5
2)2,4,0
2nd ka Kaise aya answer
ANS Q.1_ 5,Q.2_ 2,4,0. Q.3- 3
Accha padhya sir
1-5
2-(2,4,0)
3-3(not sure)
Thank you sir
hlo
भाई 19 :00 मे जो क्वेश्चन लाये बिल्कुल समझ नई आया एकदम,
थोड़ा अच्छे से समझाइये pls
Qn1. 5
Qn2. 2,4,5
Qn 3 0
Sir sab mein o rakhe agar 10 guna ke Alawa ho
MAJA AAYA
Q1.-ans- 5
Q3-ans-3
1st -2,4,0
2nd -cnd
H/w
1.b
2.a
3.a
Thank you so much guru ji
🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Ans.
1-5
2-2,4,0
3-1
Nice session guru JI 👍👍👌👌
Love you too guru ji ❤❤❤❤❤
bhai 2nd....
@@gautam9269
4. 5. 6
|+\*|+\*|+
2. 1. 1
Multiply kroge
[{(6+1)*5}+1}*4]+2=146
146/6 to 24 times jayega aur Rem 2 bachega
24/5 to 4 times jayega aur Rem 4
4/4 Rem zero(0) Ayega
2, 4,0
@@gautam9269 agar samajh aya ho to like please
24/5 kase aya vha toh 146/5 ayega Na????
@@Yourrr-ajay thankuu bhai jaan...
Q1. 2, Q2. 2,1,1 as only the divisors are reverse
HW
1 - 5
2 - 2,4 & 0
3 - 0 {CND}
2nd Question ka answer 02 Hoga