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Sir is this true, sir Lambda = M/L M --> L dm --> dx dm = M/L × dx I = Mx² --> derivative both sides dI = x²dm --> (I = integation of x²dm) (> means from - to) I = integration of x² × M/L dx I = M/L×(integration of x²dx)½ > -½ I = M/L [x³/3]½ to -½ M/3L [(L/2)³ - (L/2)³] = M/3L [2L³/8] I(ç.m) = ML²/12 Which is the required M.O.I of centre of mass of a thin rod.
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Weight = m×g, "g" is nothing but acceleration due to gravity, which is a type of acceleration And force = mass × acceleration Therefore, weight is a type of force.. Therefore, torque = force × perpendicular distance => torque = weight × perp. distance Hope this helped
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Eppudiki koda nenu me videos chustha sir please continue.... Reply sir🥰🥰😍😍
20:33 28ML^2/192 => 7ML^2/48
Thank u sir.....and I am so late sir for found ur channel..... really super explaination sir🙏🙏🙏👏👏👌👌
Sir your explanation is awesome sir iam enjoying your explanation and
Sir I got 7ML²/48
Superb explanation sir... Understood very well...
Sir plz do upload mechanical properties of fluids also sir.. Plz sir
20:33
Ans is 7ml^2/48
Nice bro
Very good keep it up👍👍👍
Correct
@@allinonetelugu3399 TQ bro for your valuable comment
Excellent and super explanation sir i really enjoy your videos
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Sir is this true, sir
Lambda = M/L
M --> L
dm --> dx
dm = M/L × dx
I = Mx² --> derivative both sides
dI = x²dm -->
(I = integation of x²dm) (> means from - to)
I = integration of x² × M/L dx
I = M/L×(integration of x²dx)½ > -½
I = M/L [x³/3]½ to -½
M/3L [(L/2)³ - (L/2)³]
= M/3L [2L³/8]
I(ç.m) = ML²/12
Which is the required M.O.I of centre of mass of a thin rod.
Correct.. keep it up
Thank you sir
Sir could you please do a video of best books for jee mains and advanced🙏🙏🙏
Finally i found a excellent sir for physics
20:24 the answer is 7ML*2/48 sir
Correct
Nice explanation sir i love your videos and also i like ur smile
Nice 👍👍👍👍👍👍 nice nice explanation sir
20:40 7 ml^2÷ 48
Correct
Correct
Sir excellent explanation....sir koni problem chepandi
Sure 👍
Next video
7L/48.....rod...❤️
Thank you sir👌👌
20:09( 7Ml^2)/48
sir ur explanation is very intellectual please do video on gravitation sir
Sure 👍
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Sir mi videos super sir.... Mains varaku manaki saripotaya sir.. Pls reply
These videos help to understand core concepts. practice more problems.
At 20:32.. ans is (7ML^2)/48
Excellent
Correct
7ML^2/48 answer sir
Sir plzz do vedio on gyration
Super explanation
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Nice explanation sir
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Answer is 7MLsquare/48 sir
22:03 ans.7ml^2/48
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Sir please do a video for problem based on parralal &perpendicular axes theorm
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I= 7ML^2/48 is answer 20:31
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I am already subscribed sir , your lecture are really assoomme
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Thank you so much sir .....!
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Super super super super super super super 🙏
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Sir... really mind blowing explaination sir 🔥🔥.. super explaination sir.....👌👌👌...👏👏👏👏
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@@kvskphysics o
Cq square not cq sir
7ML2/12
Mention time in the video to which you are answering so that I can review it
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Keep watching
7ml²/48
20:34 - 7ML^2/48 sir
Excellent correct
Keep it up
Sir at 20.34 i got 7ml square by 48
Correct
7ml^2/48
Excellent
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I=7ML²/48
20:39 ml²÷48
7 ml²/48
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7ML^2/48
7MLsquare by 48
Sir rolling motion meda video cheyandi sir .meru sasi lo work chesara
Yes
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Sasi lo work chesaru aa sir I know U
Meru naku telusu sir
20.32= MLsquare by 12
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Sir is the answer is correct
@@nikhlreddy3534
Answer is not correct
Go through just previous problem again to do it
apply parallel axis theorem as we did for L/2 problem
Sorry sir answer is
7mlsquare/48
😶
7ML*2/48
7ml2by 48
7ML square / 2
Excellent
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20: 33 the answer is 7ml square÷48. Is it correct sir 🤔 🤔 .
Excellent correct answer 👏
Keep practicing more problems
@@kvskphysics thank you sir 🙏
I got 100 % calrity sir tqu so much
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7ML²/48
Sir pls continue lectures sir
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ML^3.12/48
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@@kvskphysics I am already subscribe sir
Sir how torque =weight×perpenducular distance
Weight is nothing but a type of force
Weight = m×g,
"g" is nothing but acceleration due to gravity, which is a type of acceleration
And force = mass × acceleration
Therefore, weight is a type of force..
Therefore, torque = force × perpendicular distance
=> torque = weight × perp. distance
Hope this helped
🥰🥰🥰
20 min 7mlsquare/48 ok sir
Excellent
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7ml²/48 sir
Excellent
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7mlsquare /48
Excellent
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7ml2÷48
Answer is 8mlsquare/12
Nice explanation Sir
Thank you sir 🎉🎉🎉🎉
Sir please do video on gravitation sir
ruclips.net/p/PLSQJ6RDNxQ_Og_VA4S97J37GOlbiaS0pm
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7ML^2 / 48
7ml^2/48
7ML²/48
7mlsquare/48
Excellent
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7ML²/48
7ML^2/48
7ML^2/48