Synchronous Generator || Example 5.3 || EM 5.8 (Urdu/Hindi) (Chapman)

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  • Опубликовано: 15 дек 2024

Комментарии • 13

  • @NinjagoEditz289
    @NinjagoEditz289 7 месяцев назад

    at 14:35 why we wrote sin 36.87 and not sin(-36.87) as its lagging?

    • @ElectricalEngineeringAcademy
      @ElectricalEngineeringAcademy  7 месяцев назад

      watch carefully from time 14:00. Here we are not using the angle of the lagging current, rather we are using the angle of impedance (right hand side triangle, where theta is positive.

  • @yumnamuneer1107
    @yumnamuneer1107 4 месяца назад

    why didn't you use the Vφ=EA+ j+XsIA formula for calculation?

  • @nayemhossain3409
    @nayemhossain3409 2 года назад

    How to ohmega value 125.7 plz explain sir? & Details

    • @ElectricalEngineeringAcademy
      @ElectricalEngineeringAcademy  2 года назад +4

      To me there is an error in the question. The frequency should be 60 Hz in first line also. At 60 Hz , the speed is 1200 rpm and omega-m will be 125.7 in part (a) also.

    • @nayemhossain3409
      @nayemhossain3409 2 года назад

      Thank you so much sir ❤️❤️❤️❤️

    • @yasirali2618
      @yasirali2618 Год назад

      @@ElectricalEngineeringAcademy can a generator works on both frequencies i mean 50 hz as well as 60 hz?and how these two frequencies are given in everybook?kindly sir explain this issue?

    • @ElectricalEngineeringAcademy
      @ElectricalEngineeringAcademy  Год назад

      @@yasirali2618 Generator Frequency (f) = Number of revolutions per minute of the engine (N) * Number of magnetic poles (P) / 120. Since in a particular generator, the poles are fixed during manufacturing, so only by varying speed, the frequency can be changed.

  • @iftekharulazim6673
    @iftekharulazim6673 2 года назад

    What is the book name?