The oxidation of rubidium is +1 and the oxidation for oxygen is -2 (but because there are 4 oxygens the total oxidation is -8); we are finding the oxidation of chlorine which is donated by x. RbClO3 is overall 0. Therefore the equation can be written as: +1 + x + (-8) = 0 X = 8-1 X = 7
hi why would it be rubidium chlorate +7 and not +9?
The oxidation of rubidium is +1 and the oxidation for oxygen is -2 (but because there are 4 oxygens the total oxidation is -8); we are finding the oxidation of chlorine which is donated by x. RbClO3 is overall 0. Therefore the equation can be written as:
+1 + x + (-8) = 0
X = 8-1
X = 7
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