Trig sub completing the square: complete square before substitution. Integrate 1/sqrt(x^2+4x-12).

[@robertkimgetich2875]

I love your explanation

[@ZaksLab]

Thanks! -- Zak

[@essayprometheus]

This was very helpful, thank you!

[@ZaksLab]

My pleasure. Glad I could help!

[@JollyAZ]

Just wat i needed thank u

[@ZaksLab]

you're welcome! - z

[@abdikadirsalad1572]

Thanks a lot ❤

[@ZaksLab]

you're welcome! z

[@AlexanderGrier-yf6fj]

thank you i love you

[@ZaksLab]

you're welcome! -- zak

[@austin7843]

Thanks King

[@ZaksLab]

you're welcome -z

[@darcash1738]

What is the point of Euler’s substitution? Is it ever faster than trig sub? I learned how to do it recently but I’m finding they’re interchangeable so far..😅

[@ZaksLab]

I never heard of Euler's substitution until just now! It would be interesting to dig into the history of it, the range of application, comparison to trig based methods etc. Thanks -- z

[@darcash1738]

@@ZaksLab yeah man I’m gonna have to look at more examples of it. But for now I think the main situation where it works out better is cases like this where it’s not just a simple tan, sin, or sec identity to cancel the root. Saves a bit of time to go down the Euler sub root.

[@MathZoneKH]

Very nice !help me a lot

[@ZaksLab]

thanks! -- Zak

[@its.vivian6secondaccount749]

Thank you so much

[@ZaksLab]

you're welcome! z

[@Brekstahkid]

Dislike because you're doing an easy example.

[@ZaksLab]

So no easy examples allowed? There are several other completing the square trig. sub examples in my trig sub integral playlist if you want to look for a better one . . . I know there's at least one where the linear coefficient isn't a perfect square, and at least one where the quadratic coefficient is negative, if that's the sort of complications you are looking for. Playlist: ruclips.net/video/cf7HhPFV0WM/видео.html