AOA Sir very well explained MashAllah jazak Allah ho khaira. The answer to given Assignment is Function is Continuous at 1,2,3,4 because every open set of Tx(related to respective points 1,2,3,4 )has subset in open set in Ty (related to respective points a,b,d).Thanks
Sir I am very much impressed by your method of teaching . Love 💞 😘 u so much . lots of my mcs mathematics concepts are clear due to your loving and interactive method of teaching
Excuse me sir you explain this topic very well but you should use word "open set" instead of "subset" bcs there's a requirement of open set not subset.
I always watch your lectures and learn many things ...your teaching method is so impressive ...but one thing is ..screen should be clear so that we can also see white board clearly...thanks ❤
Assignment: Function is Continuous at 1 and 2 Function is Discontinuous at 3 because : f({1,2,3}={a,b} is not subset of {b}. Function is Discontiouous at 4 because : f(X)={a,b,d} is not subset of {b,c,d}.
AOA Sir very well explained MashAllah jazak Allah ho khaira.
The answer to given Assignment is Function is Continuous at 1,2,3,4 because every open set of Tx(related to respective points 1,2,3,4 )has subset in open set in Ty (related to respective points a,b,d).Thanks
Sir , Your learning method is outstanding.
Sir I am very much impressed by your method of teaching . Love 💞 😘 u so much . lots of my mcs mathematics concepts are clear due to your loving and interactive method of teaching
Sir your lectures👏👍or lectures leny m b maza ata h
A.o.a
sir 9:12 pr dekain k a and b ka subset to a b c d d b bn rha hai na?
MashAllah Boht Acha smjta Ha ap,,, sir kindly BS calculas par mazeed videos bnay
MashAllah MashAllah sir g ❤❤❤❤❤❤❤❤
Bhai osam boht acha explain kia h
Outstanding 💯
Great method
Vvvvv nice lectures sir plzzzz jaldi agy lectures uodate kr diya krain
Your way of Teaching is very nice
No words to thank you
Sir you make the maths very easy
Sir g good krdia yar... ❤️❤️❤️❤️❤️
❤❤❤😊😊😊 Thanku
Continuous at all points ❤
Assalam o Alikum!
Sir continuous function k theorems ka link send krden.
Thank you sir
You explained very well MashaAllah
Very well explained
Sir, your way of teaching was nice kindly explain the concepts in English
Those are helpful to us
Icmy kia issue ara?
@@m.k.f.amathematicsknowledg1668 don't know hindi sir
Then how you understand the lecture if you can't understand urdu or hindi language 😊
Add the vedio on separable spaces
Very informative video sir
Sir the answer of given assignment is function is continuous at 2,3 and 4
Sir hmmy project ml gya ha compactness and connectness wally topic p koii help kr skty ha ap kia?
is m hm n 1,3 1,4 kion nai lia....????
un dono m b 1 contained ho rha ha
Excuse me sir you explain this topic very well but you should use word "open set" instead of "subset" bcs there's a requirement of open set not subset.
Sir all points per continuous ho tu phir function bhi continuous hoga
G
🌹🌹🌹🥀
The function is continuous on all points.123&4
Sir the function is continuous at every point of X
Sir mera to 1,2,3,4 points pr continuos aarha ha kindly aap bata de yh continuos ha ya nai
Very precise and awesome solution ❤
Homeomorphism Waly lecture plzzzzz share kr dy
Easy to ha gor sa definition example ko samjo
Assalam o alakium sir .sir ap ny koi fundamental theorem of calculus PR video bnai ha to kindly us ka link send kr dy.
ruclips.net/video/sDn_JK71UIo/видео.html
Thanks sir
sir lecture is not visible
Suoer sir
Well explained
I always watch your lectures and learn many things ...your teaching method is so impressive ...but one thing is ..screen should be clear so that we can also see white board clearly...thanks ❤
Ok dear
Sir plz Principal ideal py video bna dyn
Assignment:
Function is Continuous at 1 and 2
Function is Discontinuous at 3 because : f({1,2,3}={a,b} is not subset of {b}.
Function is Discontiouous at 4 because : f(X)={a,b,d} is not subset of {b,c,d}.
Sare hi points continuous hain
It is continuous on all points
Hhhh i am sorry to say that it is a discontinuous function..
??
👌👌
❤👍
Well explained sir
👍👍
Very well🤍
Thanku sooo much sir g ❣️❣️🔥
Sir kindly apna number dain Mai AP ko assignment bhj don plzz sir❣️
Sir plzz ap apna number send kr dy
03097918745
Thank you sir
Thank you sir