Calculus 3: Lecture 11.5 Lines and Planes in Space
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- Опубликовано: 26 авг 2024
- This is a real classroom lecture. This lecture covers section 11.5 which is on lines and planes in space. These lectures follow the book Calculus by Larson and Edwards. Here is the book amzn.to/472xvYc (affiliate link).
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Only 7 minutes in and I finally know SOMETHING about what my lesson was about. Already whizzing through my homework. Thanks!
you are a real good teacher who do not read textbook
great video! Helped me on my quiz. Hope you have a good day Professor.
Thanks, you too!
the best lecturer I have ever seen!
thank you!!
TOTALLY AGREE!
@@aaronpearson1400 He is the Best!!
LETS GOOOOOO first time watching a lecture of yours after watching many of your videos. I love your teaching style and would definitely vibe in your class
Hehe
👍
theres something very comfy and inspiring about the idea of teaching something you love and cherish to students in a community college lecture room
This lecture is solid . The overall points are covered in great detail. The video skips a little bit, please review the full tape. Mr. sorcerer thank you for your contribution to basic and advanced mathematics.
You’re probably way too busy for this, but have you considered doing a lecture series specifically covering spivak’s calculus, kind of like how the physics guy did a series on Serge Lang’s basic mathematics? I think it would get a ton of views compared to normal calculus lectures.
cool idea thank you:)
Great explanation, also thank you very much for publishing these lectures online.
Wow! Incredible teacher!! You make it so much easier than other teachers do.
This guy made me save calc 3
👍
1:17:25 "In general whenever you have 2 points on a plane, you can always find a vector on the plane. In other words whenever you have 2 points on a plane you can always find a parallel vector. That's useful, because if you have 2 parallel vectors you can always take the cross product and that will give you n and then you're done with the problem."
Surprised no one caught this. The cross product of two parallel vectors is zero yielding the null result for the equation of a plane. 3 points define a plane, not two. The above quote would be correct if the plane went through the origin as in the example given. Given 2 points, (0,0,0) would be the third point.
This make so much sense and can relate to it so much but do not understand alot from it maybe if I can get some of this program pre record it will help.
Hey , what book(s) are these lectures from? my professor is using Single and Multivariable 6th Edition
Larson's calculus book
which college do you work. your students must be happy as you are good teacher
when you say they are parallel you dont mean that they are also collinear right?
i mean at 6:13: when you do Q-P you get a vector that starts at point (0,0,0,), therefore it should be not just parallel but collinear to v?
Wait from 0:00 to 0:08, what about X=3, you have a line and a point but the slope is undefined.
yeah good catch, if the slope is undefined you just need the point, so like (3, 5) and undefined slope, must be x = 3
The last problem can I do (-2,8,6) - (4,2,1) instead? and when you do the cross product between 2 parallel vectors, is u x v same as v x u?
excellent
Thank you!
@@TheMathSorcerer i just purchased your calc 3 course on Udemy. You're much better than my college professor lol.
PLEASE IM BEGGING YOU PLEASE BE A TEACHER AT RUTGERS UNIVERSITY WE NEED YOU MY CALCULUS 3 TEACHER IS TRASH!!!!!!!
In example 13 of the planes in space part, how do you know that the vector that you get from the plane that they give you in the problem is perpendicular to that equation of the plane?
never mind...i figured it out
1+2 hahahha you're making me like calculus 3 my teacher is so bad .... thank you soo much you make me laugh
This is such a piece of cake literally, I am from india here the level of problems is just 10 times tougher in the entrance exam for bachelors in engineering!
Holy cow your class room size looks small
haha