Algebraic topology: Introduction

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  • Опубликовано: 13 сен 2024

Комментарии • 65

  • @insising
    @insising 3 года назад +65

    Let's goooo! This is going to be epic!

    • @gregoriousmaths266
      @gregoriousmaths266 3 года назад +6

      indeed it is, mr quirky kirk 😳

    • @insising
      @insising 3 года назад +2

      @@gregoriousmaths266 GREG MAFFS

    • @Salmanul_
      @Salmanul_ 3 года назад +2

      @@gregoriousmaths266 GREG!

    • @incredulity
      @incredulity Год назад

      No, it's going go be monic 🤪

    • @insising
      @insising Год назад

      @@incredulity that's what I'm saying

  • @simplicjusz
    @simplicjusz 3 года назад +15

    The other day, I learnt combinatorics from Prof. Gowers, now, I am listening to Prof. Borcherds on algebraic topology. Who needs universities? Long live the lockdown!

    • @dimadima5298
      @dimadima5298 Год назад

      Hello ! I hope that you are doing well, do you know any other channel like thses

  • @Helmutandmoshe
    @Helmutandmoshe 2 года назад +13

    I am sure hoping that you will continue this series on Algebraic Topology. What a great gift these teachings are to the mathematical community... and eventually, through secondary contacts and so on, the rest of the world. Thank you.

  • @codatheseus5060
    @codatheseus5060 28 дней назад

    THANK YOU!! Ive spent years trying to understand a handful of things that just kept eluding me about complex functions and this lecture cleared them up!

  • @Jop_pop
    @Jop_pop 3 года назад +15

    This is incredibly perfect - was literally just looking for a course in algebraic topology and found Hatcher's book! Then this comes out the same day??

  • @melanthajezek2835
    @melanthajezek2835 3 года назад +19

    The lack of notification of your videos has been eating me up for days. I'm so relieved you uploaded! I got too used to these daily videos. I understand you must be working on something amazing right now hence the gaps. Good luck and thank you!

  • @tianyoumei450
    @tianyoumei450 3 года назад +19

    Excellent as always Dr. Borcherds!

  • @Lern2Read
    @Lern2Read 3 года назад +8

    Thanks Dr. Borcherds, very timely as well - I had just begun reading a bit more about algebraic topology and was hopelessly lost. Will look forward to more videos soon.

  • @GiacomoAakbr
    @GiacomoAakbr 3 года назад +17

    so excited about this series!!!

    • @hanzsoy5274
      @hanzsoy5274 3 года назад

      wtf this is the 3rd time i've encountered you on youtube haha

  • @robertschlesinger1342
    @robertschlesinger1342 3 года назад +8

    Excellent lecture. Very interesting, informative and worthwhile video. Many thanks.

  • @dontwannabefound
    @dontwannabefound Год назад +1

    Incredible Prof Borcherds, I should have taken some of your classes while I was at Berkeley!

  • @빵빵빵-m1o
    @빵빵빵-m1o 3 года назад +2

    I remember hearing about fundamental groups and such at topology2 class. The teacher was kind and good.

  • @danielplacido8746
    @danielplacido8746 3 года назад +4

    He just won't stop

  • @user-yb8xm3ve7x
    @user-yb8xm3ve7x 8 месяцев назад

    Thank you for providing this content and giving back to the mathematical community. 😊

  • @mrpotatohed4
    @mrpotatohed4 3 года назад +2

    been wanting a supplement for this topic, looking forward to more, thank you.

  • @Barbapippo
    @Barbapippo 3 года назад +3

    Thanks! I look forward to the next lectures, :)

  • @vijaykumarsharma5490
    @vijaykumarsharma5490 3 года назад +2

    Exciting ! We do it for the fun of it 🤘🏻 Thanks professor 😊

  • @kingarth0r
    @kingarth0r 3 года назад +5

    Bro you've been making so much!

  • @hannesstark5024
    @hannesstark5024 3 года назад +1

    I missed it. So glad the videos are back and better than ever!

  • @harisserdarevic4913
    @harisserdarevic4913 3 года назад +5

    Thank you for uploading this lecture! I'm currently a 3rd year undergraduate math student, what would be a good prerequisite for this class? I have strong experience in abstract algebra but not much topology background

    • @Ken-wr7zx
      @Ken-wr7zx 3 года назад +4

      The first four chapters of Topology, by James Munkres, would do it. If you are very comfortable with equivalence relations and the quotient topology, in particular, box diagrams and the associated constructions of the torus, cylindrical segment, Moebius band, and projective space, then you will be ready (at least from what I can tell by looking at the level of the first lecture).

    • @harisserdarevic4913
      @harisserdarevic4913 3 года назад +1

      @@Ken-wr7zx Thank you, I will try self studying that to try and even understand the following lectures! The material appears incredibly interesting but it feels so out of reach at the moment.

    • @rzhang3927
      @rzhang3927 3 года назад

      @@harisserdarevic4913 I would also recommend taking a look at Armstrong’s Basic Algebra. Armstrong included some basic Alg Topo in the second half of the book, after some essential basics of general topology.

    • @rzhang3927
      @rzhang3927 3 года назад

      Basic Topology*

  • @midnightposting
    @midnightposting 3 года назад +1

    this introduction was already amazing

  • @f5673-t1h
    @f5673-t1h 3 года назад +4

    I remember reading that the first homology group is the Abelianization of the fundamental group. (someone please correct me)

    • @BenSpitz
      @BenSpitz 3 года назад +3

      Correct! Well, we need to assume our space is path-connected (or else "the fundamental group" isn't well defined), but then it's true.
      More generally, if a space X is n-connected, then H_{n+1}(X) is the abelianization of π_{n+1}(X) -- this is called the Hurewicz theorem. The special case n=0 says precisely that the first homology of a path-connected space is the abelianization of its fundamental group.

    • @f5673-t1h
      @f5673-t1h 3 года назад

      @@BenSpitz what does n-connected mean?

    • @BenSpitz
      @BenSpitz 3 года назад +2

      @@f5673-t1h n-connected means π_k = 0 for all 0≤k≤n. So 0-connected just means π_0 = 0 (a.k.a. path connected), and 1-connected means 0-connected + π_1 = 0 (a.k.a. simply connected). 2-connected means 1-connected + π_2 = 0. The simplest examples are spheres: Sⁿ is n-connected (but not always n+1-connected).

    • @HilbertXVI
      @HilbertXVI 2 года назад +1

      @@BenSpitz The higher homotopy groups are abelian anyway

  • @ivanphi
    @ivanphi 3 года назад +3

    It would be great to see some discussion on spectral sequences :)

  • @MagicBoterham
    @MagicBoterham 3 года назад +3

    What's R/Z, real numbers with the integers removed?

    • @adityadwivedi4412
      @adityadwivedi4412 3 года назад +8

      That is more like equivalence classes, with x and y are in same equivalence class iff x-y is an integer

    • @lilylikesmarkies
      @lilylikesmarkies 3 года назад +1

      One defines an equivalence relation on R by saying x~y if x-y is an integer. The resulting set of equivalence classes is denoted by R/Z

    • @bagratmakhmutov4854
      @bagratmakhmutov4854 3 года назад +1

      It's a quotient group (also called factor group in some languages).

    • @Suav58
      @Suav58 3 года назад +5

      Let ω=2π and let z=cos(ω)+i sin(ω). Then we mapped a real line R to a unit circle in a complex plane C with every unit interval, like [0,1), or [29577,29578) covering the circle once. We mapped R onto S1, covering S1 Z times over. If we quotient our map by the integers Z, we get just one “abstract” instance of our map. We can “lift” our circle (by an “inverse” map) to any interval on the real line and an open set/interval on the circle will be lifted to an open interval on the unit segment of the real line of our choice. In both mappings we preserved the local topological structure of R and S1.
      The whole story started, more or less, with Fourier series and Fourier transform. If it is not so, I hope that @Richard E. Borcherds will be kind enough to correct me.
      This is not the only map from R to S1. The other standard one, covering the S1 only once, but in infinite time t is given i.a. in @Richard E. Borcherds’ introductory video to algebraic geometry.
      Btw. RUclips would do us a great favour incorporating LaTex in the comments, wouldn’t they?

    • @darryljohnson8516
      @darryljohnson8516 3 года назад +6

      Set difference is backslash, quotient is forward slash. Can be confusing sometimes.

  • @RalphDratman
    @RalphDratman 3 года назад

    This is really good!

  • @staj6236
    @staj6236 3 года назад +1

    K theory. So cool name.

  • @hassaannaeem4374
    @hassaannaeem4374 2 года назад

    awesome!

  • @brendawilliams8062
    @brendawilliams8062 3 года назад

    Thankyou

  • @AlessandroZir
    @AlessandroZir 2 года назад

    thanks! 🙏🙌

  • @f5673-t1h
    @f5673-t1h 3 года назад +9

    YEEEEEEEEEEEEEEEE

  • @pmcate2
    @pmcate2 3 года назад

    What is the difference between Z and the free group on a,b? It seems like they should be isomorphic since Z also has two generators.

    • @pmcate2
      @pmcate2 3 года назад +6

      Oh, I guess the free group is not abelian

    • @AdityaKumar-tj2dj
      @AdityaKumar-tj2dj 3 года назад

      @@pmcate2 yes you are right.

  • @allenamenwarenbezet
    @allenamenwarenbezet 3 года назад +1

    Instant classic

  • @sammyboy7094
    @sammyboy7094 3 года назад

    Yaaaay!!

  • @pairadeau
    @pairadeau 3 года назад

    yay!

  • @agnivobanerjee2864
    @agnivobanerjee2864 3 года назад

    Sir please do a lecture series on Arithmatic Geometry

  • @migarsormrapophis2755
    @migarsormrapophis2755 3 года назад +4

    yeeeeeeeeeeeeeeee

  • @DuyNguyen-qz9sp
    @DuyNguyen-qz9sp 3 года назад +3

    Hello :)

  • @jacobschmid2898
    @jacobschmid2898 3 года назад

    antioxidants deoxidize where the lungs are

  • @johnnyq4260
    @johnnyq4260 3 года назад

    The lack of motivation is unfortunate.

  • @bolloop
    @bolloop 3 года назад

    Rika: finally! A happy timeline 😁
    Satoko:
    👁👄👁
    ➖👄➖
    🔫🛑👄🛑