Discrete Math - 1.5.1 Nested Quantifiers and Negations

Поделиться
HTML-код
  • Опубликовано: 18 янв 2025

Комментарии • 53

  • @VALR1able
    @VALR1able 2 года назад +21

    This is an amazing instructor. Everyone can learn discrete mathematics from this instructor. May you continue to teach for another 100 years.

  • @lucascamarasa2081
    @lucascamarasa2081 Год назад +12

    Professor Brehm, I think you should get 50% of the tuition money I paid for my university because you've saved my life in Linear Algebra and now Discrete Maths! Thank you for these videos, I am forever grateful :))))

  • @wilbertcoandadiputra2487
    @wilbertcoandadiputra2487 3 года назад +48

    Im a college freshman majoring in CS and really struggling in Discrete Math rn. U just saved my life because this well-explained things right here. Thank you

  • @benh918
    @benh918 11 месяцев назад +3

    Yep! 3 weeks in and I finally decided to look for help on RUclips. Thank god I found your channel. Thank you so much, life saver.

  • @aleksey6151
    @aleksey6151 4 года назад +27

    Your new explanation of x/y = 1 is much better in this video. I hope your twins are doing well!

    • @mahihoque4598
      @mahihoque4598 2 года назад +3

      You are her real life student?

  • @chhangsrengp5360
    @chhangsrengp5360 2 года назад +9

    I have followed your playlist video for a while now and am currently on video 13th. I gotta say, your video are very easy to understand and teach me so much. I'm not at Uni yet, but will be after this summer break, and I'm watching this to prepare.

    • @SawFinMath
      @SawFinMath  2 года назад +3

      Awesome! You will be way ahead of the game!

  • @ham8088
    @ham8088 11 месяцев назад +1

    WHY ARE YOU SO GOOD AT EXPLAINING!!!! i wish you where my professor!

  • @yowreesesame1803
    @yowreesesame1803 Год назад +2

    this is well explained. Im currently a undergrad Computer Engineer and this video actually helps. Thanks!

  • @hydraim9833
    @hydraim9833 Год назад +1

    Hello, I am currently doing the discrete mathematics class in computer science and I just wanna say that your channel is a gem. Thanks a lot

  • @aditibose9143
    @aditibose9143 4 месяца назад +1

    The only videos on youtube I will watch happily with ads

  • @bhargavnayankumarkargatiya7162
    @bhargavnayankumarkargatiya7162 3 года назад +3

    You just blow my mind ! it's best tutorial that I ever seen

  • @khadijamalyk
    @khadijamalyk 4 года назад +6

    i finaaaally feel like my ass has been saved . thankyou so much for such fantastic explanation

  • @fourtress43
    @fourtress43 3 года назад +2

    This is so great it’s just like my class but I understand this version.

  • @aizenisplanning
    @aizenisplanning Год назад +2

    Thanks for this amazing course!

  • @Shahed4114
    @Shahed4114 3 года назад +2

    Finally I get this point, you are awesome thank you.

  • @TheBirdThatHeard
    @TheBirdThatHeard 2 года назад

    You are a much better Instructor compared to my prof

  • @mahimmarufuzzaman3588
    @mahimmarufuzzaman3588 4 года назад +3

    15:09 for the last example wouldn't it be false? because x and y could have both been 0 and 0/0 is not equal to 1.

    • @ObadiahHoss
      @ObadiahHoss 3 года назад +10

      The last statement is saying "there exists an x, where with a corresponding y, x/y=1". Because of this, you only need one example to deem the statement true.
      One example where a certain x and y value makes the equation incorrect doesn't make the overall statement false because of the "there exists" clause on both variables. As long as one example proves the equation true, nothing else matters, the statement is true.

    • @wilbertcoandadiputra2487
      @wilbertcoandadiputra2487 3 года назад +4

      @@ObadiahHoss thanks for ur explanation. So if there is two existensial on a variables, as long as we prove it true by one statement, so its true, eventhough we have a counter-example like the cases in the video.

  • @tanhnguyen2025
    @tanhnguyen2025 11 месяцев назад

    I kinda wonder at timestamp 11:15 statement number 3 where there's an existential and universal quantifiers nested together such that x*y=0. I think the statement should be false because the existential quantifier defines there exists at least one object in the domain that satisfies the conditions which is not true because there's only exactly one x which is equal 0 to satisfy that condition.

    • @pcake4603
      @pcake4603 7 месяцев назад

      "at least one" is satisfied even if there's exactly one. it's the same as saying that the amount of values that satisfies the condition is greater than or equal to 1.
      You would be right if the quantifier meant "there is more than 1," because that statement implies that one is unsatisfactory.

  • @red-sv2qf
    @red-sv2qf 10 месяцев назад

    In 14:05, why can Ey change for any number Ax when the opposite cant be done?

  • @silvo9460
    @silvo9460 7 месяцев назад

    your actuallt amazing. i love u

  • @mutumbakalumba
    @mutumbakalumba 11 месяцев назад

    for the negation question what would be the truth value for that question ?

  • @Ammarx1
    @Ammarx1 10 месяцев назад

    Thank you Thank you Thank you.

  • @snipzcomm7358
    @snipzcomm7358 3 года назад

    7:40 cant u let y = 5- x and then for any x it is true?

  • @robhul5950
    @robhul5950 5 месяцев назад

    Wouldn't it be more correct to use the uniqeuness quantifier for "Every real number has an additve inverse" since they each only have one?

  • @keeganafrica7783
    @keeganafrica7783 Год назад

    In the 2nd example you say the existential y value can change but I thought you are only suppose to use 1 value for "there exists" not change them to accommodate " all x's"... a bit confused about that 1

  • @ongjay9754
    @ongjay9754 2 года назад +1

    There exists a real number x such that for all real numbers y such that x is not equal to -y.
    This is FALSE because x=-3 , -y=-3
    -3=-3
    IS MY EXPLANATION CORRECT?

  • @JulianGutierrez-sz4hl
    @JulianGutierrez-sz4hl 10 месяцев назад

    For Example 1, would it be allowed to say that the P(x,y) is a tautological function? Since xy=yx is equivalent to 1=1, which is always true.

  • @-Mohamed_bayan
    @-Mohamed_bayan 3 года назад +1

    What is the software that you use for writing?

    • @SawFinMath
      @SawFinMath  3 года назад +2

      I'm just using Microsoft power point and the recording tab.

    • @-Mohamed_bayan
      @-Mohamed_bayan 3 года назад +1

      Thank you👍🌷

  • @dzbro1194
    @dzbro1194 2 года назад

    you make it seam so simple

  • @ganganijayathilake7178
    @ganganijayathilake7178 Год назад

    Thank you.

  • @hrithiksarma2934
    @hrithiksarma2934 4 года назад

    Can we interpret , for all x there exist y as a many to one function from x domain to y co domain , and there exist y such that for all x as a one to many function form x domain to y co domain .

  • @w7lves
    @w7lves 2 года назад

    can someone give a further explanation for the first example pls?

  • @alfabetony
    @alfabetony 4 года назад +1

    what if y = x ?

  • @moizansari3644
    @moizansari3644 4 месяца назад

    Shouldn't be the ∃x ∃y P(x, y) for "x/y = 1" be False bcz if x=0, y=0, then 0/0 != 1

  • @RidwanSuleiman-o8u
    @RidwanSuleiman-o8u 3 месяца назад

    Please the video is not clear

  • @alfabetony
    @alfabetony 4 года назад +2

    or x = y

  • @h_lid_n
    @h_lid_n 11 месяцев назад

    15:12

  • @CS_Simplified
    @CS_Simplified 2 года назад

    Cooool

  • @ACBinus27
    @ACBinus27 Год назад

    🅝🅘🅒🅔

  • @harshdeepsingh1666
    @harshdeepsingh1666 2 года назад

    Chup mahgya