Fundamentals Of Electric Circuits Practice Problem 10.9
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- Опубликовано: 21 янв 2021
- A step-by-step solution to Practice problem 10.9 from the 5th edition of Fundamentals of electric circuits by Charles K. Alexander and Matthew N.O. Sadiku. The values in the question may be different from the ones you have in the edition you're using but the approach should be the same.
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11:32 You forgot to write 0.2 in the ecuation i1+(8+j4)i1=-20. Good video bro!
You should fix the camera position. It's actually not possible to concentrate like this way.
I don't use this method of teaching anymore and it wasn't possible to keep it at one position. Thanks for the feedback
sir my answer (i1) different than your answer how we can write in calcuator .?? ( i1=-20/1+(0.2x8+4j) right?
The 0.2 should multiply everything inside the (8 + j4) bracket
your tutorials are good but I would appreciate if everything could be on one big board. The constant movement makes it a bit difficult to keep track of what has already happened.
hope you would consider. Thanks :)
I had limited options at the time. I hope my "new" method is a bit better :). Here's a sample : ruclips.net/video/wZIYzmdK9OY/видео.html
. Thank you for your feedback
good but you need to adjust your camera
how did you find Zth, my result of angle is different
I simply put 1/(41/185 + 11/370*j) in my calculator, and it gave me that value. If you aren't getting the same, just reset your calculator's settings and make sure it is in degrees
@@KhetzTutorials thank you very much, now i understand, actually my calculator wasnt in degrees, it was in rad.
is the answer correct ? Thequestion also wrong
I believe the answer is correct. Which part of it did you find any mistakes?
@@KhetzTutorials the current source in book is 5 A not 20A
I believe that is the value you have in your textbook as you said. You can get the edition I used in the video's description. The aim afterall is that you learn how to use the concepts and explanation for your unique values
@@KhetzTutorials another question sir, why the I2 is equal to -0.2 Vo? I was thinking to write I2-0.2vo
Currents along the same wire can't be different - they can only differ in sign. The i2 current can be said to flow along the 0.2vo wire but in the opposite direction. Therefore, it'll have the same value but with a different sign to show the difference in direction. Note that 0.2vo is a current source - the vo is only there to show that the value of the current depends on vo so it is a voltage dependent current source.