Runge kutta 2nd order Method

[@californiadreams1170]

Average indian: no worries, I will teach you my son!
Thank you man. It's a very good explanation!

[@jackbogue3906]

In the second half where you solved k2, instead of using k2 = hf(x1 + h, y1 + k1) you instead used k2 = hf(x1 + h, y1 + k). This gave you 0.1431 instead of 0.1421. This then left you with y2 = 1.24205 instead of 1.24155. Very slight difference but thought it was worth pointing out.

[@moodflix5053]

0.02462

[@adityamisra7702]

no he is correct. he used y1+k1

[@GMSLAGADE]

يعطيع والله عافية يا رجال

[@fatima-sd5xd]

thank you very much❤️❤️

[@pankajkumarrout2687]

Thank you sir 🙏☺

[@Haat02]

❤❤❤❤❤

[@janewanjiru2270]

Thanks 🎉

[@SteelBB9]

Thank you so much

[@rohanshetty4164]

Best explaination ever🔥

[@Shining-lz9se]

Kindly make video on stability interval of RK2 method 😊

[@Civillearningonline]

Ok

[@AaronKishiki]

The book i was reading was showing that h multiplies only K1 in K2.

[@vitthalkeshave1168]

Thank you ❤️

[@famousjedits_143]

Thanks

[@neha4953]

very helpful

[@md.omarfaruk9785]

Thank you sir

[@Tareq--ri6qe]

❣️

[@WinsteinDc]

This solution isn’t complete

[@rahulbhatt1]

Sir what if h is not given?

[@Civillearningonline]

Do you have any questions of that type?

[@Kiddo_storyworld]

@@Civillearningonline yes

[@yashpunera]

I have all those Q's in my paper where h is not given.

[@joshnajs]

@@yashpunera Hi did you find out how to find h?

[@yashpunera]

@@joshnajs use h= x1-x0 when not given .

[@brightfutureacademy187]

X2=x0+2h sir

[@Civillearningonline]

No.

[@brightfutureacademy187]

@@Civillearningonline it is true

[@madhujha9357]

You are right but x2=x0+2h or x2=x1+h gives same result all the times it is successively...

[@madhujha9357]

X2=x1+h=x0+h+h=x0+2h

[@mirmueid9294]

Apko hindi mai nhi aye ga padana...... Jb ki apki english thk nhi hai.....kya zarurat hai.. Jo language achai se aye ge usse language se padawo.......

[@Your-competitorGRD]

Guru ho skta hai, sir south ka honge.
Kannad me pdega😂

[@archmaths]

​@@Your-competitorGRD😂