How to calculate the Empirical and Molecular Formula of Compounds for 2025 JAMB tutorial

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  • Опубликовано: 27 янв 2025

Комментарии • 42

  • @PhilipMelifonwu
    @PhilipMelifonwu 16 дней назад +2

    Thank u sir I really appreciate

    • @NurseBright
      @NurseBright  16 дней назад

      You are welcome
      Keep sharing with friends

  • @RabeccaKakunta-j9n
    @RabeccaKakunta-j9n День назад +1

    Thank you i really enjoyed ur teaching

  • @Yass-l2y
    @Yass-l2y 2 месяца назад +1

    I like the ur passion of teaching keep it up sir

  • @olalereoluwatoyin490
    @olalereoluwatoyin490 10 дней назад +2

    C5H4O =e.f

  • @okadigboAnthony
    @okadigboAnthony 6 месяцев назад +1

    I love you're teaching it's so easy

  • @jethrofynn8234
    @jethrofynn8234 Год назад +4

    Sir please I am a Ghanaian and I want you to make more videos for us. thank you sir.

    • @NurseBright
      @NurseBright  Год назад +4

      You are welcome ❤️
      Anticipate More Video lessons soon

  • @wulengkiwegapjigotau2456
    @wulengkiwegapjigotau2456 4 месяца назад +3

    This is amazing , keep it up sir❣❣

  • @MatthewEledu-p1s
    @MatthewEledu-p1s 9 месяцев назад

    Thank you sir

  • @angelaagbenyegahaddey9354
    @angelaagbenyegahaddey9354 7 месяцев назад

    Thank you

  • @Edikan00001
    @Edikan00001 10 месяцев назад

    You made this look very easy
    Something i thought was very hard
    Kudos to you u earned my subscription 👏

  • @NatashaFulani
    @NatashaFulani 9 месяцев назад

    Thank you so much

  • @AdabaVeronica
    @AdabaVeronica 3 месяца назад +1

    🔥🔥

  • @MatthewEledu-p1s
    @MatthewEledu-p1s 9 месяцев назад +1

    E. F, C5H4O
    M. Mass, 3
    M.F,C15H12O3

  • @onojastanley9401
    @onojastanley9401 Год назад +1

    E.f = C5H4O
    M.F = C15H12O3
    Thanks sir
    I'm really learning a lot from you sir

    • @NurseBright
      @NurseBright  Год назад

      You are welcome ♥️
      Anticipate more video lessons soon♥️
      Share with friends 💥

  • @NumviyimanaAbel
    @NumviyimanaAbel 15 дней назад +1

    We want how to find molarity calculator

  • @BlessingOtuoye-o2c
    @BlessingOtuoye-o2c Месяц назад

    Thanks so much sir

  • @LifeofToraa
    @LifeofToraa Год назад +1

    Thanks bright ❤️🙌🏽🙌🏽🙌🏽

  • @idikegift7325
    @idikegift7325 Год назад +2

    Thank you sir,nice video
    Answer:
    Empirical formular
    C5H4O
    Molecular formular
    n=3
    C15H12O3

  • @OladokunBose-d9w
    @OladokunBose-d9w 2 месяца назад +1

    EMPERICAL FORMULA:C5H4O
    MOLECULAR FORMULA:C15H12O3

  • @Callmeomene
    @Callmeomene 10 месяцев назад

    God will bless you oh am in ss1 you helped me understand better ❤😢😊

  • @olayinkabalogun243
    @olayinkabalogun243 6 месяцев назад +3

    Sir why is it that if i wantbto join the money is too much why😭😭😭😭😭😭😭😭😭😭😭😭

  • @OluwadeleAnointed
    @OluwadeleAnointed Год назад +1

    Thank you very much sir
    I will be writing jamb next year

    • @NurseBright
      @NurseBright  Год назад

      You are welcome ❤️
      A new video series will be Out very soon on My Channel
      Anticipate ❤️

  • @BlessingMoses-ny6wf
    @BlessingMoses-ny6wf 10 месяцев назад

    Sir can you please help me to solve this?
    If a compound has a molecular formula of C4H8O4 and a molar mass of 178g/mol, what is its Empirical. E.F.?

  • @ogboruvictory-hz4ns
    @ogboruvictory-hz4ns Год назад +1

    🙏🙏

  • @winbrightclothing2356
    @winbrightclothing2356 Год назад +3

    My exam is next week and I'm so scared
    C5H4O E.F
    C15H12O3 M.F

    • @prettytopia
      @prettytopia 9 месяцев назад

      What did you score?

  • @folashade5532
    @folashade5532 Год назад +1

    Empirical formula _C5H4O
    Molecular formula _C15H12O3

    • @Sereneglow210__
      @Sereneglow210__ 10 месяцев назад

      pls im not getting how you guys got that molecular formula

  • @Sereneglow210__
    @Sereneglow210__ 10 месяцев назад

    sir pls i got the empirical formula C5H4O but im not getting the molecular formula

    • @Zephyr-jw9hv
      @Zephyr-jw9hv 9 месяцев назад

      calculate your ‘n’ and which is molecular mass (240.28g/mol) over empirical mass (solve for it and you should get 80g/mol) which would equal to 3. Use the value for n to multiply your empirical formula = 3(C5H4O)
      hope this helps

  • @mutexdesigns783
    @mutexdesigns783 4 месяца назад

    E.F= C5H4O
    M.F= C15H12O3

  • @ndubuisielizabeth3747
    @ndubuisielizabeth3747 Год назад +1

    My exam is tomorrow
    This really helped alot

  • @munirjibril4064
    @munirjibril4064 10 месяцев назад

    CH2O

  • @ElizabetholihaOsama
    @ElizabetholihaOsama 3 месяца назад

    C5-H4-O-E.F
    C15-H12-O3M.F