Since the prime factors of 777 = 3 x 7 x 37, hence phi (777) = phi(3).phi(7).phi(37). Using the rule: phi(p) = p-1, then we have phi(777) = (3-1)(7-1)(37-1) = 2.6.36 = 432.
Thank you so much bro In one video me understood the whole topic of this vdo view only one no any doubt no repeat🔁 no pause for understand nothing U r a gem 💎
phi(m*n) = phi(m) * phi(n), iff gcd(m,n) = 1 aka m & n should be coprime. In case of phi(49), we would get our m = 7 and n = 7 and we would be finding phi(7*7) according to formula mentioned above. But, it only works when gcd(7,7) = 1 ----- but unfortunately, gcd(7,7) = 7.
Since the prime factors of 777 = 3 x 7 x 37, hence phi (777) = phi(3).phi(7).phi(37). Using the rule: phi(p) = p-1, then we have phi(777) = (3-1)(7-1)(37-1) = 2.6.36 = 432.
This video helped me understand the concept so much better than before. Thank you kindly.
Thanks a lot ... I was searching for the "49" questions ,,, u helped me a lot 🙌🙌🙌🙌
Simple explanation and amazing layout of the rules. I understand this much better now thank you.
i like your video, its easy to understand . thank you
Mate, this video saved my ass in my Cryptography assignment! Great video! Keep up the good work.
crypto? That sounds high lvl class, I was even forced to learn this sht in first year math class dyum
Thank you so much bro
In one video me understood the whole topic of this vdo view only one no any doubt no repeat🔁 no pause for understand nothing
U r a gem 💎
Shoutout to this youtube video for being better than my professor.
Thank you sir your explanation is too great ❤️❤️❤️❤️
And the answer is 432
So simple .. so efficient.. So Good
It's too simple... good class& more helped 👏👏👏break a leg
really awesome .thank u so much and very nice explanation
Welcome
great and helpful lecture for me.thank you so much.love from pakistan
Explained so nicely...I got this topic in one go...thank you so much
Phi(1)=?
Thnak you sir direct to the comcept no beating around the bush wonderfull teaching
Thank you sir you made this yopic very clear for me and yes I did the same mistake but then corrected after watching your video🙏🏻
Thank you so much! Your explanation is very clear!!
phi(m*n) = phi(m) * phi(n), iff gcd(m,n) = 1 aka m & n should be coprime.
In case of phi(49), we would get our m = 7 and n = 7 and we would be finding phi(7*7) according to formula mentioned above.
But, it only works when gcd(7,7) = 1 ----- but unfortunately, gcd(7,7) = 7.
Great video sirrr...really helpful....found error on my teacher's pdf as well
ans 432…????????
Yes,777=7*3*37
Thanks for great explanation sir, and Phi(777)=432 :)
Excellent explanation 🎉
Amazing explanation. thank you for helping me with my cryptography class
Tq so much brother... It's help me a lot to understand 👍😊
crystal clear explanation .Thank you so much
Thank you sir, now I fully understand this topic.
What type of question ask to related to this concept
Thank you so much for your video. It make my doubts clear ❤️
Thankyou Sir ❤️❤️
Tx sir this topic is in applied maths class 12th cbse ncert now all the doubt regarding this topic crystal clear now 😀
how do I find phi of something like 3^90?
160200
5.81864238*10^42
some of them still uploaded the easy problem but you uploaded all categories. I like it.
Am in difficulty thanks to help me bro
How will we find the phi of 4
Thank you sir I understand this topic very clearly so again thank you
Can you give solution for phi(d(2100))
Literally lifesaver
Thanks sir .... Muje clear krna Tha ....
Can you please tell me how to find those elements which do not belong to range of euler phi function?
what if we can't find the factor of a number ?
Thanks so much..very clear explanation
Very helpful. Thanks for your help
great explanation thank you sir.
Thank you Sir 🙏
By the way very helpful lecture .. thanks a lot 🙏🏻
Sir nice strategy of explaining with examples 😀
Great work 🎁
The great explanation. You are a great teacher .The answer of phi(777) is 660
φ(777)=432 not 660
φ(777)=φ(7)φ((3)φ(37)
= 6x2x36
= 432
Is rule 3 equivalent to p(p-1) ?
Good explanation 🙏🏼
YOU ARE THE MAN
simple and practice, very good ¡
Ans:-432
شكرا جزيلا .....💞
What if they are 2 prime numbers
Sir, shouldn't phi of 1 be 1??
Nice explanation!
1 to the power of anything is still 1, so 1 - 1 is 0
Thanks brother 🔥
Thank you so much.....😍
Thanks a lot sir ji
Thank you so much sir 😊😊
Thank you sir for a very clear lecture
Sir, phi of 1 equal 1 not zero
I liked your video
You explain very nice
777=37×3×7
Phi(37)×phi(3)×phi(7)
=36×2×6=432
Vry helpful video thx sir
well done helped a lot.
Fast and understanding
Nice job🌼
nice explain...thx
Thank you so much..........
The value of euler phi of 1 = 1, not 0 as said in the video.
Hey.. mene bohot search kia
Mila nahi
Can you tell me why is that ?
Is 660 is the answer??
Plz answer it....
330
nice ...:) thank you thank you.. :) very clear .. i learned a lot
Thanks, it's literally save me👍
phi(777)=432
Good Job Brother
Nice explanation
very nice explaination
Great work
Can you solve it for n=12
ans is 4
Hw ans is 776.plz reply
Thank you sir
What is the answer of phi 4
2
I think phi(1^10)=0?
Thanks man
Thankyou so much
Ilove U 🎉
Thanks sir....
thankew💞👍
Why it become 64 ? (EXAMPLE 3)
If Phi of 2 raise to 4 = (16-8) = 6
Phi of 5 = (5-1) = 4
Phi of 3 = (3-1) = 2
6 x 4 x 2 = 48
Anyways thank you for the information
16-8=8
Got your each and every line very clearly👍👍
Tnk u sir
Sir phi(1)=1 hota hai na
Great 👍
432 is the answer,, phi (1) =1 not 0
Thanks
He don't know so many properties of Euler phai function, please use Burton Number theory
Amazing
Helpful bro
Thanks from pakistan thanks a lot kl mra mid hai uni mai ap ny hlp ki
very useful