☑️17 - Thevenin's Theorem: Circuits with Dependent Sources 1

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  • Опубликовано: 17 окт 2024

Комментарии • 68

  • @koushiksamanta7563
    @koushiksamanta7563 17 дней назад +2

    Bro is dangerous 💀, I mean he is using loop equation rather than KCL or nodal. Damn bruh❤

  • @szc7f
    @szc7f Месяц назад +1

    sir, for calculating the Vth in the example2, can I set the different positive and negative resistor terminals and write the equation as 4Vx+10Ix-5Ix+15Ix=0?

    • @PanagiotisSalamalikis
      @PanagiotisSalamalikis 29 дней назад +1

      In general, you want to have positive voltage difference when the current flows from a low to a high potential point (voltage source in this example) and negative potential difference when the current flows from a high to a low potential point (any resistor). My point is that you have to use opposite signs for the source (4Vx) and the resistors (10Ix, 5Ix, 15iX). So the answer is no.

  • @nishantgupta5015
    @nishantgupta5015 Год назад +5

    Thank you
    To help me in clearing my mid sems ❤❤

  • @zaidabdulkarim2125
    @zaidabdulkarim2125 2 месяца назад +1

    Hello sir, in example 2 when we found i1 it is in fraction if we change it to decimal it is 0.66A so in i0 when we replace i1 to find it it will be -1.32A hence, isn't Rth Vo/io = 1/-1.33 = -0.76 ohms. so only because i changed the fraction to a decimal it changed the answer totally?? if so then when should i just keep it as a fraction and when should i change it to decimal?

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  2 месяца назад +1

      Usually during the solution process, use fraction, and then you convert the final answer to decimal, but if you want to be changing to decimal every now and then, leave your decimal to 4dp.

  • @nishjijiiiii1045
    @nishjijiiiii1045 5 месяцев назад +1

    Hi! May I know why are there two value of Ix? What is the difference between the Ix obtained in solving the resistance vs the Ix obtained in solving the voltage?

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  5 месяцев назад

      The idea is.
      To find the rth we need to solve for Ix, that's the first Ix.
      For the second Ix helps you to find Vth.
      The two are independent. So in another question it can be a different ball game altogether

  • @irisianacani9316
    @irisianacani9316 4 месяца назад +1

    while finding vth at example one does no current flow from the 6v battery and we only consider 0.5 Ix?

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  4 месяца назад

      Current flows from the 6v battery. You can make 6v the reference source to do the current distribution, it is correct, but my reference was the 1.5ix current source that is why I have the 0.5ix moving towards 6v.
      You can equally do a current distribution using the 6v as reference and get the same answer

  • @KwizeraPacifique-xf9dd
    @KwizeraPacifique-xf9dd 17 дней назад +2

    i thought Vx in example 2, was supposed to be Vx= 15(Ix)

  • @danthetutor6300
    @danthetutor6300 Год назад +1

    What was the purpose of the polarity over the 5 ohm for vx .Shoudnt the voltage across ir be -5Ix.Since in the direction assumed there will be a negative drop?

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  Год назад +1

      The polarity on the 5ohms just explains or indicates the direction of current through it, i.e. From positive to negative.

  • @GenerousChicken
    @GenerousChicken Месяц назад +2

    In example1, why the current flowing through the 5ohn resistor is 0.5 Ix?

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  Месяц назад +2

      It's simple: 1.5ix is flowing towards the junction. And ix flows in 3ohms, hence
      1.5ix - ix = 0.5ix will flow in 5 ohms

  • @mohubemahlatsephaladi6246
    @mohubemahlatsephaladi6246 4 месяца назад +3

    THANKS SIR WE BE GETTING 90'S BECAUSE OF YOU😭😍😍😍😍😍😍😍😍😍😍😍😍😍

  • @mokhtarnasser2482
    @mokhtarnasser2482 Год назад +2

    is Vth always 0 if there are only dependant sources? like it was in example 2 since there are no independent sources to provide voltage.

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  Год назад +2

      Yes, the vth will be zero if there are no independent sources.

    • @yi_huimeng1936
      @yi_huimeng1936 6 месяцев назад

      Can you explain why you set 1 V source on the a ,b?

  • @erdal.uzunlar
    @erdal.uzunlar 8 месяцев назад +2

    Thank you very much for this awesome video!

  • @KinguinMalfoy
    @KinguinMalfoy Год назад +1

    You had two different values for the same variable Ix... why are they different..
    And does the Vth only affect that loop

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  Год назад +2

      The values for Ix are different because you are doing two different things:
      1. You want to find RTh hence you need to excite the circuit because mind you, the independent sources are removed and if independent sources are removed, dependent sources have no purpose because they are controlled by these independent sources. So ones you excite the circuit with a 1v or 1A source you get a value for Ix. Also when finding Ix or any current value, do not consider the loop with a dependent current source.
      2. After finding RTh, you need to find Vth, and this time you leave the terminal open, hence the value for Ix will surely be different.
      For the last part. You can use the other loop from vth to the far left. Ignore the loop with the current source.

  • @hleketanicarl2984
    @hleketanicarl2984 Год назад +1

    How is it possible that the voltage drop across 4 ohm resistor is 5.33V? That means 5 ohm and 3 ohm resistor only dropped 0.67V from the 6V battery. Can you please explain that?

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  Год назад +2

      Notice that in this case, there is a dependent source which also contribute to the circuit.

  • @confused_engineer
    @confused_engineer Месяц назад +1

    Rth= Vth/Isc and Isc across load is Ix so Rth=4ohms
    What is wrong with this

  • @aliekamaraa445
    @aliekamaraa445 Год назад +1

    Sir
    Does this tutorial video meant for senior high school level or university

  • @MasbuleleDyubele
    @MasbuleleDyubele 6 месяцев назад +1

    Thank you so much ❤

  • @21khalid8
    @21khalid8 Год назад +1

    in example 1 why did u subtract 1.5 from 1

  • @viwemkhothi6349
    @viwemkhothi6349 Год назад +1

    isnt the current in the 15ohm resistor ( i0-i1)-(i1 since i1 is also going through 15 ohm in the opposite direction ?

  • @dcmar-ava5150
    @dcmar-ava5150 11 месяцев назад +1

    Please 2:25
    What if you use Io=1A. How one now find vth
    Please sir

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  11 месяцев назад +3

      Okay,
      Do current distribution. That is
      Current in 4ohms is (ix + 1), in 3 ohms is ix and in 5ohms is 0.5ix.
      Apply kvl to the loop containing resistors, 3, 4, 5.
      Ix = -8/9
      Vo = 4(-8/9 + 1)v
      Rth = vo/io = 4/9/1 = 0.444 ohms

  • @katzuev7786
    @katzuev7786 7 месяцев назад +1

    Thank you!💘

  • @lugandaronald64
    @lugandaronald64 7 месяцев назад +6

    This is contradicting to content I read from Basic engineering circuit analysis by David Irwin 11th edition page 192, I suggest u check that page and see where u go wrong if at all u are wrong

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  7 месяцев назад +1

      Kindly specify where you disagree with me.

    • @lugandaronald64
      @lugandaronald64 7 месяцев назад +2

      ​@@SkanCityAcademy_SirJohn
      The part where you apply an independent current source, the book says you only do this if the entire circuit is made up of only dependent circuits, yet here yo dealing with one that has both independent and dependent

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  7 месяцев назад +2

      @lugandaronald64 mmm are you sure?? Kindly double check

    • @volerdenuit1582
      @volerdenuit1582 7 месяцев назад +1

      @@lugandaronald64 i agree

    • @lugandaronald64
      @lugandaronald64 6 месяцев назад +2

      ​@@SkanCityAcademy_SirJohnI rechecked and both methods work, the first time I replied I had not yet tried both, but now am sure they both work, thanks for the great content

  • @sadiamubashira9354
    @sadiamubashira9354 Год назад +1

    thank u so much

  • @sourav3000-h4x
    @sourav3000-h4x 4 месяца назад +1

    In my calculation vth is coming
    16/3 v 😅😅