Frequency Response and Cut Off Frequency For Low Pass and High Pass Filters

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  • Опубликовано: 5 фев 2025

Комментарии • 11

  • @salemabdesselem692
    @salemabdesselem692 3 года назад +1

    Very useful and so sweet that even a physician (MD) understated every thing. I am so thankful for this free knowledge sharing

  • @anasabubakar4125
    @anasabubakar4125 2 года назад +1

    Wow! I have been searching for this

  • @alattar6568
    @alattar6568 4 года назад +1

    That was so clear and useful sir .well explained 👏
    Thank you so much

  • @adibakbari6748
    @adibakbari6748 3 года назад +1

    You are a life saver. Thank you

  • @lastmanstanding9389
    @lastmanstanding9389 Год назад

    Hi, great tutorial. How would one do this with inductors in place of the resistors, I would like to plot loudspeaker crossovers?

  • @lastmanstanding9389
    @lastmanstanding9389 Год назад

    Is there a video showing how to plot the phase on the above graph?

    • @EngineersAcademyLTD
      @EngineersAcademyLTD  Год назад +1

      There isn't, and I might make one at some point, but for now you could make another column to take the impedance angle (for the purposes of this) to be =X/R (multiply *180/PI() if you want this in degrees)
      These should all span from 0 to 90 degrees if done correctly, for the HP filter, and from 0 to -90 for the LP filter, taking XC as negative when calculating X/R.
      Then, make a column for the angle of the current, this will be minus whatever the previous column was, so negative Z angles will become positive and vice-versa.
      Finally, for the phase we are looking for the phase angle of the voltage across the output component, and V = I*X. We add the angles here, so to our current column we add either +90 in the case of an inductor (HP) or subtract 90 in the case of a capacitor (LP)
      This is not an ideal explanation for a youtube comment but hope it helps for now.

    • @lastmanstanding9389
      @lastmanstanding9389 Год назад

      @@EngineersAcademyLTD thanks a ton for the reply. It's a bit over my head as I'm mathematically challenged and usually learn from examples ;) I managed to get the graph working in Excel, thanks to your explanation.

  • @NoName-yy1jx
    @NoName-yy1jx 4 года назад +1

    Amazing thank you

  • @melodym7337
    @melodym7337 4 года назад

    Thank you so much