@TIKLESACADEMY sir aapke questions ka level bhut low h jo hamare yaha questions aate h unka to aata Pata nhi chalta h mere 40 mein se 12 no aaye jbki meine aapki saari videos dekhi thi😢😢😢 0:01
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Tomorrow's my engineering mechanics exam and this really helped! Well articulated sir! Better than my college professor's lectures. 🥰 Huge respect 💯💯 New subscriber here! Hehe
Sir you are really a great personality or great professor of mechanics.sir aap mere opinion se bhagwan ho mechanics wo hum engineers ke zindagi mai aaye wo warna college ke professor ke chakar mai fail ho jate......keep it up sir
Sir please iske samne ke bhi friction ke type sikhao,,please Sir ,mera first year back hai our lockdown ke karan mere classes bhi bandhogaye the abhi aapke hi videos dekh kar sikh raha hu. Aapke karan mechanics easy lagne laga hai. Thank u sir
Appreciable...i m an upsc aspirant having maths optional and I used your lectures in my study and they are very helpful to me in my entire journey thnks a lot sir for making such difficult topics very easy
sir aapke questions ka level bhut low h jo hamare yaha questions aate h unka to aata Pata nhi chalta h mere 40 mein se 12 no aaye jbki meine aapki saari videos dekhi thi😢😢😢
A ladder of 5m length is supported against a rough wall at angle Q(theta) with the floor the coefficient friction at Wall and floor is 0.2 if the weight of the ladder is W and acts as a center of the ladder find the angle Q(theta) with the floor when the ladder is at point of slipping
Step 1. *Free body diagram.* Step 2. *Equilibrium:* {B. Σf(x)=0; Σf(y)=0 A. Resolve inclined forces into their components along x and y axes. C. F in “→”, “↑” direction = +ve, &, F in “←”, “↓” direction = -ve D. ΣMx = 0; ΣMy = 0; i.e. sum of moments = 0. Moment = Force × ⊥ distance w.r.t a point. Also = Component of Force ⊥ to the distance from that point. Any Force F passing through that point during finding moment w.r.t that point = 0. So, always take moment w.r.t a point which makes maximum number of Forces 0.} Step 3. *Formula of Friction:* { *F = μR* , where μ is the coefficient of friction which is the ratio of the force of friction F to the normal force R, F/R. F always acts opposite to the motion of the body and along the surface. Angle of friction is the angle between the resultant R' (say) of F and R with respect to R, denoted by φ. hence *μ = tan⁻¹(φ)* } Step 4. Lami's Theorem: { *When three forces (T1, T2, T3 acting at a point P are in equilibrium, then each force is proportional to the sine of the opposite angles (A, B, C respectively) to that force in that system* The forces must be in same plane, and they all must be in same direction otherwise this theorem is not applicable. *T1/sin(A) = T2/sin(B) = T3/sin(B)* } Step 5. *Resultant of Friction:* {The resultant R' (say) is the resultant of the Frictional force F & the normal force acting ⊥ to the surface against the weight, R. It can be used to solve Wedge problems when angle of friction is given it makes it easier to solve, also Lamis theorem might be applied too, (read step 3 and step 4)}.
a 5 metre long ladder is resting on a smooth vertical wall with it is lower end 3 m from the wall what should be the coefficient of friction between the ladder and the floor for equilibrium .
Sir ji iska solution btao plz Ladder is resting on a horizontal floor leaves against a vertical wall at an angle 60 degree with the floor. If the coefficient of friction is 0.25 at the wall and the floor, what percentage of length of ladder a person can asend without causing the ladder slip? Neglect the weight of ladder.
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@TIKLESACADEMY sir aapke questions ka level bhut low h jo hamare yaha questions aate h unka to aata Pata nhi chalta h mere 40 mein se 12 no aaye jbki meine aapki saari videos dekhi thi😢😢😢 0:01
Sir apka video free or quality se bhara hua hai apke jaise log ki jarurat hai desh ko age badhane me.mai ek diploma student hu or apka sara video mujhe pashand aata hai
Because you give content on rural language and students are easily understand
Thanks for watching and supporting 🙏
Thanks for watching and supporting 🙏
Sir no one teaches better than you. I m completing my sylabus only by watching your videos and also sharing this to all my friends
Tomorrow's my engineering mechanics exam and this really helped!
Well articulated sir!
Better than my college professor's lectures.
🥰
Huge respect 💯💯
New subscriber here! Hehe
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Sir you are really a great personality or great professor of mechanics.sir aap mere opinion se bhagwan ho mechanics wo hum engineers ke zindagi mai aaye wo warna college ke professor ke chakar mai fail ho jate......keep it up sir
you are the best teacher i have ever seen
Sir, your Explanation is very Logical, Please to hear and very systematic.
The video was really helpful, all the concepts were explained very lucidly and clearly . Thank You So Much !!
Sir please iske samne ke bhi friction ke type sikhao,,please
Sir ,mera first year back hai our lockdown ke karan mere classes bhi bandhogaye the abhi aapke hi videos dekh kar sikh raha hu.
Aapke karan mechanics easy lagne laga hai. Thank u sir
Sir u are just taking the class in the way that is understandable in simple words.
Your video is really awesome u have cleared my doubts in ladder friction thank u so much sir
THANKS FOR WATCHING.
Appreciable...i m an upsc aspirant having maths optional and I used your lectures in my study and they are very helpful to me in my entire journey thnks a lot sir for making such difficult topics very easy
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sir aapke questions ka level bhut low h jo hamare yaha questions aate h unka to aata Pata nhi chalta h mere 40 mein se 12 no aaye jbki meine aapki saari videos dekhi thi😢😢😢
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ayenga ayenga kr kr aap bhut achha samjhate ho
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Thank you sir.
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A ladder of 5m length is supported against a rough wall at angle Q(theta) with the floor the coefficient friction at Wall and floor is 0.2 if the weight of the ladder is W and acts as a center of the ladder find the angle Q(theta) with the floor when the ladder is at point of slipping
Ur just wow sir🙏♥️
Big salute sir... You are amazing
Thanks for watching
Belt friction var video banava sir . Great teaching , mind-blowing teaching
❤❤Thank you sirrr
I will definitely share your videos with my mates
Thanks for watching.
Teaching skills 🔥🔥
Sir thanks a lot!! Actually teaching for mechanics wasn't that good , learnt a lot concepts and applications from your lectures Sir. 😁
Thank you sir...🙂
U teach VRy good sir 🥺👍
Tq sir you helped me a lot now I passed em subject
Thank you so much for making this video it helps me a lot
Sir engineering mechanics ki concept samaj Mai aa gaya Hai. Belt friction per video upload kerdige GA question bhi lag raha hair.
Yes definitely.... Please wait
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Make regrously type problem videos
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Greatest teacher 👏
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Thank you so much sir ❤❤🙏🙏
Thanks for watching
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Sir open gear drive pe question kraiye
Step 1. *Free body diagram.*
Step 2. *Equilibrium:*
{B. Σf(x)=0; Σf(y)=0
A. Resolve inclined forces into their components along x and y axes.
C. F in “→”, “↑” direction = +ve,
&, F in “←”, “↓” direction = -ve
D. ΣMx = 0; ΣMy = 0; i.e. sum of moments = 0.
Moment = Force × ⊥ distance w.r.t a point.
Also = Component of Force ⊥ to the distance from that point.
Any Force F passing through that point during finding moment w.r.t that point = 0.
So, always take moment w.r.t a point which makes maximum number of Forces 0.}
Step 3. *Formula of Friction:*
{ *F = μR* , where μ is the coefficient of friction which is the ratio of the force of friction F to the normal force R, F/R. F always acts opposite to the motion of the body and along the surface. Angle of friction is the angle between the resultant R' (say) of F and R with respect to R, denoted by φ. hence *μ = tan⁻¹(φ)* }
Step 4. Lami's Theorem:
{ *When three forces (T1, T2, T3 acting at a point P are in equilibrium, then each force is proportional to the sine of the opposite angles (A, B, C respectively) to that force in that system*
The forces must be in same plane, and they all must be in same direction otherwise this theorem is not applicable. *T1/sin(A) = T2/sin(B) = T3/sin(B)* }
Step 5. *Resultant of Friction:*
{The resultant R' (say) is the resultant of the Frictional force F & the normal force acting ⊥ to the surface against the weight, R. It can be used to solve Wedge problems when angle of friction is given it makes it easier to solve, also Lamis theorem might be applied too, (read step 3 and step 4)}.
Thanks bhai
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My dear sir ,two block connected with a string................., type problem solve karne ka approach bataiye please,🙏🙏🙏🙏🙏
Yes definitely.... Please wait
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Plz upload more videos on this topic
Yes definitely.... Please wait.... More videos will come soon.... Please keep in touch
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THANKS FOR WATCHING.
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Thanks for watching
a 5 metre long ladder is resting on a smooth vertical wall with it is lower end 3 m from the wall what should be the coefficient of friction between the ladder and the floor for equilibrium .
Please wait , i will upload a special video on this question. For that please send me complete question (if you have).
a great teacher....thank you sir...
Sir kabhi kisi topic ka definition bhi bata diya kariye
Awesome explaination sir..
Sir ji iska solution btao plz
Ladder is resting on a horizontal floor leaves against a vertical wall at an angle 60 degree with the floor. If the coefficient of friction is 0.25 at the wall and the floor, what percentage of length of ladder a person can asend without causing the ladder slip? Neglect the weight of ladder.
I will try to upload a special video on this question. please wait and keep in touch
@@TIKLESACADEMY Thanks you sir
Please.. do soon soon sir exam are near
Sir thank you for your guidance its definitely very helpful and appreciated
Awesome explained Thank you sir❤️
Sir mene padha hai ki clockwise negative aur anti clockwise positive hota hai
Koi bhi method se solve karo, answer same aata hai.
You could have resolved weight horizontally and vertically in terms of angel.