THANK YOU SIR. But toward the end… I don’t understand the 8 parts divided into six. I understand why he had to divide into 8 and not six. But what is the mask of that, what does 8 splitting mean for the /24? Does that make it a /16 or something else? I think it’s a /29 because that’s 32 hosts. How do you calculate that bit change?
Hey, If you divide a /24 (256 host) network in to 8 parts, you will get 8 networks each having 32 hosts. Now you need 5 bits for 32 host. You already had subnet mask of /24 (which means 24 bits represent network ) and 8 bits were reserved for host. As you only need 5 bits now for host, you left with 3 bits for network. After subnetting you are going to have 27 bits for network and 5 bits for host. Why 27 because you already had 24 bits and you have taken 3 more bits from host side. Hope this help.
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Thank you for such a clear and meaningful description. I hope to watch more of your very practical videos soon. Best wishes.
THANK YOU SIR. But toward the end… I don’t understand the 8 parts divided into six. I understand why he had to divide into 8 and not six. But what is the mask of that, what does 8 splitting mean for the /24? Does that make it a /16 or something else? I think it’s a /29 because that’s 32 hosts. How do you calculate that bit change?
Hey, If you divide a /24 (256 host) network in to 8 parts, you will get 8 networks each having 32 hosts. Now you need 5 bits for 32 host. You already had subnet mask of /24 (which means 24 bits represent network ) and 8 bits were reserved for host. As you only need 5 bits now for host, you left with 3 bits for network. After subnetting you are going to have 27 bits for network and 5 bits for host. Why 27 because you already had 24 bits and you have taken 3 more bits from host side. Hope this help.
Please also carry on also in future with this dedication ..
Sure Dude!!
10.10.122.0 network address & 10.10.123.254 broadcast address
Different network as /25 have only 128 valid ip
You are correct.. thanks for your reply. Please have a look at my new video also.. Its a layer-2 packet walk in case you are interested..
Shouldn't the broadcast address be 10.10.123.255?
@@willd9226 Yes, the last address is .255 It's my bad!! You are correct..
10.10.23.0 -
10.10.23.63
10.10.23.45 is 45 th host in this network
Please correct me if i am wrong
You are right!!
Dhaga khol dia sir ne
:)