China | A Nice Algebra Problem | Math Olympiad

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  • Опубликовано: 6 июн 2024
  • math olympiad
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    Find the value of x and y?
    How to solve x^y+y^x=17
    In this video, we'll show you How to Solve Math Olympiad Question A Nice Exponential Equation x^y+y^x=17 in a clear , fast and easy way. Whether you are a student learning basics or a professtional looking to improve your skills, this video is for you. By the end of this video, you'll have a solid understanding of how to solve math olympiad exponential equations and be able to apply these skills to a variety of problems.
    #matholympiad #mathtricks #maths

Комментарии • 28

  • @mrjnutube
    @mrjnutube Месяц назад +2

    You could simply say:
    Let a²=x^y, b²=y^x. You'll arrive at the same answer, and it'll be faster.

    • @SALogics
      @SALogics  Месяц назад +1

      You are right, I appreciate your idea ❤

  • @silvanomattioli9720
    @silvanomattioli9720 Месяц назад +3

    3^4-4^3 easy in brute force mode like y made at the end. BUT is not the only one...

    • @SALogics
      @SALogics  Месяц назад +1

      Very nice solution, I appreciate that ❤

  • @BruisedReedofTas
    @BruisedReedofTas 24 дня назад +1

    Method is ok until the factorization of 17 part. You're assuming solution from the Natural numbers without explicitly saying so (and that a Natural number solution won't result from a "non-Natural factorization"). As another commenter points out, expanding to the integers gives two more solutions (factorization of -1x-17 and -17x-1 are both valid). Expanding to real or complex numbers does give infinite solutions as all a = m+ni, b = 17/m-ni (m,n are any real numbers, m=/= 0) lead to valid solutions as well.

    • @SALogics
      @SALogics  23 дня назад +2

      You are right, I appreciate your knowledge ❤

  • @GT-fs5fu
    @GT-fs5fu 2 месяца назад +3

    Nice video. Keep up the good work.

    • @SALogics
      @SALogics  2 месяца назад +1

      Thanks, will do! ❤

  • @David2718281828
    @David2718281828 Месяц назад +17

    Don't work so hard! 18^1 - 1^18 = 17

    • @David2718281828
      @David2718281828 Месяц назад +1

      This is similar to the solution by @user-ts9kq4vn2u

    • @David2718281828
      @David2718281828 Месяц назад +3

      But with one equation and two unknowns, for any given value of x you can likely find a solution for y.

    • @SALogics
      @SALogics  Месяц назад +2

      Very nice, you are a genius, I appreciate that ❤

    • @SALogics
      @SALogics  Месяц назад +2

      Really??

    • @SALogics
      @SALogics  Месяц назад +2

      Yes, you are right ❤

  • @Lemda_gtr
    @Lemda_gtr 12 дней назад +1

    Smart

    • @SALogics
      @SALogics  11 дней назад +1

      Thanks and welcome ❤

  • @abbasmasum1633
    @abbasmasum1633 Месяц назад +1

    The best methos ever. Guess & check is not a real method. Thank you for showing us this :)

    • @SALogics
      @SALogics  Месяц назад +1

      You're welcome! ❤

  • @nikolayguzman331
    @nikolayguzman331 Месяц назад +1

    Nice idea.

    • @SALogics
      @SALogics  Месяц назад +1

      Thanks a lot ❤

  • @santokhsidhuatla7045
    @santokhsidhuatla7045 Месяц назад +1

    X^y-y^x= 17
    3^4-4^3=17
    81-64=17
    X=3
    Y=4

    • @SALogics
      @SALogics  Месяц назад +1

      Yes, you are a genius! I appreciate that ❤

  • @alfonsorafaelposadaescando4482
    @alfonsorafaelposadaescando4482 Месяц назад +1

    Buenísimo
    👍👍🇻🇪👍👍

    • @SALogics
      @SALogics  Месяц назад +1

      muchas gracias! ❤
      Thank you so much ❤

  • @markderlo212
    @markderlo212 Месяц назад +1

    I wonder if this method is applicable eg to
    this : x^y - y^x = 399 ? or ...= 169