China | A Nice Algebra Problem | Math Olympiad
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- Опубликовано: 6 июн 2024
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Find the value of x and y?
How to solve x^y+y^x=17
In this video, we'll show you How to Solve Math Olympiad Question A Nice Exponential Equation x^y+y^x=17 in a clear , fast and easy way. Whether you are a student learning basics or a professtional looking to improve your skills, this video is for you. By the end of this video, you'll have a solid understanding of how to solve math olympiad exponential equations and be able to apply these skills to a variety of problems.
#matholympiad #mathtricks #maths
You could simply say:
Let a²=x^y, b²=y^x. You'll arrive at the same answer, and it'll be faster.
You are right, I appreciate your idea ❤
3^4-4^3 easy in brute force mode like y made at the end. BUT is not the only one...
Very nice solution, I appreciate that ❤
Method is ok until the factorization of 17 part. You're assuming solution from the Natural numbers without explicitly saying so (and that a Natural number solution won't result from a "non-Natural factorization"). As another commenter points out, expanding to the integers gives two more solutions (factorization of -1x-17 and -17x-1 are both valid). Expanding to real or complex numbers does give infinite solutions as all a = m+ni, b = 17/m-ni (m,n are any real numbers, m=/= 0) lead to valid solutions as well.
You are right, I appreciate your knowledge ❤
Nice video. Keep up the good work.
Thanks, will do! ❤
Don't work so hard! 18^1 - 1^18 = 17
This is similar to the solution by @user-ts9kq4vn2u
But with one equation and two unknowns, for any given value of x you can likely find a solution for y.
Very nice, you are a genius, I appreciate that ❤
Really??
Yes, you are right ❤
Smart
Thanks and welcome ❤
The best methos ever. Guess & check is not a real method. Thank you for showing us this :)
You're welcome! ❤
Nice idea.
Thanks a lot ❤
X^y-y^x= 17
3^4-4^3=17
81-64=17
X=3
Y=4
Yes, you are a genius! I appreciate that ❤
Buenísimo
👍👍🇻🇪👍👍
muchas gracias! ❤
Thank you so much ❤
I wonder if this method is applicable eg to
this : x^y - y^x = 399 ? or ...= 169