Visit for more www.glad2teach.com Find hard-to-divide numbers. In 3 mins master long division with 9 . Easy multiplication division trick ... divide fraction www.glad2teach.com .
Dear MrFalconford, thanks for the kind words of appreciation. Change always happens gradually. From the next Academic Session (in August 2011) my EasyCal techniques would be officially taught in the curriculum of certain School Districts in USA. If the results are as expected then other school districts may follow. Schools in US have realised the importance of empowering students with strong Mathematical Skills.
I am in University for Computer Science, Mathematics, and Statistics, and taking the hardest calculus courses I can. I cannot divide those numbers mentally, hell I don't even know a lot of my multiplication tables, but you don't need to know them to be good at math... How good you are at math has absolutely nothing to do with how fast you can mentally calculate arithmetic. All the best.
Thank you for teaching me this faster way! I was having a hard time in school because our teacher (principal) is so strict, she only explains it once then no more. So so so so so so so thank you glad2teach!👏👍👏👍👏👍👏👍
Dear Iemon Soda , with your best wishes I am still very much alive. Yes it has been 5 years since I created this video and many other videos like that. If you were to read the replies I have been posting here for those many years you would find almost all types of questions solved by me that were troubling the visitors. Still every now and then someone posts a comment "this does not work...". Visit my glad2teach website to learn more (link given below the video above) Shahryar Glad2teach
I'm a really good with multiplication, addition, substraction but I always had a little leak with division. Really impressive stuff, I never worked on my division because I always thought I had to do the long way. Really nice video.
I've always been good with math, but thanks to some of your videos, I have found out by myself how to quickly find out how a number is perfectly divisible by 7 without easy ones like 575, 757, or 343, 434. I can do it for any 3 digit number, but it will not work for anything more than 3 digits. I'm just happy that numbers stop at 10. If it stopped at 11, I'm sure I would fail a lot. Thanks for the video.
@Jarel8787, I would be glad to help. Your Ques is 355 / 9 = ? Like I have explained in the easycal video above, keep taking the Digit Sum in this pattern 3(3+5) (3+5+5) (remember to write the last digit sum seperately) 3 8 ... (13) [Now just ask yourself how many times would 9 go into 13 ]. Of course just 'once' leaving Remainder 4 ) So 38 + 1 = 39 ( with remainder 4 ) Or you can write the Answer as decimal. 39.4444
I have just come up with how to do this in the way presented in this video (better said - similarly to the way presented in this video). On the very beginning, let's pre-calculate, what we should get as solution and as the rest: 2104 ÷ 8 is 263 r 0 This is how to compute this using the glad2teach's way: 2104 ÷ 8 gives us the 3-digit number "ABC" (which os called "solution") plus the rest "R". "abcd" is our 4-digit number "2104" (so a=2, b=1, c=0, d=4). *PART 1* Now we compute starting values "A.0", "B.0" and "C.0" of our solution's digits "A", "B" and "C". We compute "A.0": A.0 = a = 2 (first digit of our number "2104") A.0 = 2 We compute "B": B.0 = A.0×2 + b = 2×2 + 1 = 4 + 1 = 5 (we multiply "A" by 2 as every 10 divided by 8 gives us the rest of 2) B.0 = 5 We compute "C.0": C.0 = B.0×2 + c = 5×2 + 0 = 10 + 0 = 10 R.0 = 10 We compute "R.0": R.0 = C.0×2 + d = 10×2 + 4 = 20 + 4 = 24 R.0 = 24 We compute ultimate value of our rest "R": R.0 ÷ 8 = 24 ÷ 8 = 3 r 0 C' = floor( 24 ÷ 8 ) = floor( 24 / 8 ) = floor( 3 ) = 3 (note: *floor function* of given number "x" is a function that gives the integer which is less then equal to "x") en.wikipedia.org/wiki/Floor_and_ceiling_functions C' = 3 R = R.0 mod 8 = 24 mod 8 = 0 (note: *"a mod b" is the number which is the rest of a÷b*) en.wikipedia.org/wiki/Modulo_operation *R = 0* _____ *PART 2* Now we make the calculations by adding from the ending digit to the first digit of our number "abcd" (that is, number "2104"): In this way we obtain our ultimate values of the solution's digits "A", "B" and "C". We compute ultimate value of "C": C.1 = C.0 + C' = 10 + 3 = 13 C = C.1 mod 10 = 13 mod 10 = 3 *C = 3* We compute ultimate value of "B": B' = floor( C.1 ÷ 10 ) = floor( 13 ÷ 10 ) = floor (13/10 ) = floor( 1,3 ) = 1 B' = 1 B.1 = B.0 + B' = 5 + 1 = 6 B = B.1 mod 10 = 6 mod 10 = 6 *B = 6* We compute ultimate value of "A": A' = floor( B.1 ÷ 10 ) = floor( 6 ÷ 10 ) = floor (6/10 ) = floor( 0,6 ) = 0 A' = 0 A.1 = A.0 + A' = 2 + 0 = 2 A = A.1 mod 10 = 2 mod 10 = 2 *A = 2* *PART 3* So our solution "ABC" and the rest "R" is: "ABC" = 263 "R" = 0 So 2104 ÷ 8 is 263 r 0 as it was pre-calculated on the very beginning.
In similar way, we could do also "÷7" (in this case, we would multiply every digit "a", "b", "c", "d" by 3 (as 10 mod 7 = 3, which means, 10÷7 gives the rest o 3). But, technically, it multiplying the digits by 2 (when dividing by 8) or by 3 (when dividing by 7) will give us greater and greater numbers... So this way is fast and comfortable only for dividing by 9. So the Indian Math Tutors (such like "glad2teach") use other method to divide by 8: ruclips.net/video/plTQ80l20Mk/видео.html "Trick 359 - Divide Any Number by 8 Mentally" Suresh Aggarwal They just divide the number by 2, but three times :) How to divide by 7? I think, just do this in standard way, that means, calculate this by hand… I think, also we could divide by 9 - just we divide given number by 3, but two times.
Good question !! Not a problem if your teacher hates Remainders. You can give her the answer as Decimal. For Example - while dividing by 9 if you get the Remainder 3 then in decimal form ( way a calculator shows the answer ) it would be .3333_ _ If it is 6 then in the decimal form it would be .6666_ _ . So on Try it yourself -- Glad2teach
Dear BubbbaJay, this EasyCal technique is based on the interpretation of the ancient Vedic Mathematics from India. Vedic Math dates back to 3000 years. I am not aware if the great Trachtenberg has mentioned the same technique in the book he wrote in prison. The modern system of counting we humans use today ( it is called " Decimal Place Value System" ) is based on Base 10 . It was discovered in India ( type " Base 10" in google and read..... ).
Dear PetitTabarnak, thanks for the heartfelt appreciation. Division is supposed to be the hardest operation of Mathematics as it is difficult to visiualise all its steps in the mind. In the EasyCal Video above I have done Division using simple Addition that too in a linear manner ( thus easy to visualise ). Just practice this technique to perfection. Shahryar (Glad2teach)
Dear ColorMeMidori, you have a good observation !! However it is not always that the first digit of the question would be the first digit of your answer as well. There can be a Carry backward digit that can get added to the first answer digit.
Dude, u ROCK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! after practicing ur tricks, i was able to complete my maths paper 2day an hour before the time limit....u have really given me the greatest encouragement...If i become successful, i will recommend all to try out these tricks..thanx a lot
Guys it works with all numbers! 1st: see how close the number is to ten (for example in 2104/8, 8 is 2 less than 10) 2nd: carry the first number down (2) 3rd: multiply by the answer to step 1 and add the next # (2 times 2 is 4, plus 1 is 5) 4th: continue in this sequence (5 times 2 is 10 plus 0 is zero [remember to add the one above the five]) 5th: find the remainder (multiply 10 by 2 and add 4) 6th: put the remainder off to the side and see how many times 8 can go into it (in this case 24/8 is 3) 7th: add the 3 above the 0 8th: add to get the final answer of 263 *Note if this does not work for you then you are to stupid to figure it out. Please do not post stupid comments because they will just highlight your own stupidity.
Nice, love your troll hunting through year old comment threads. In my comment I was merely presenting a fix to make a varied form of the video's method work for all problems. I do apologize if my end note came off as arrogant, but it was there basically to prevent troll comments like yours. Have a nice day, and please take a basic english grammar class.
Did someone hurt you? XD I never instigated any of this nonsense. I'll speak with you again when you can type correctly (no offense if you have some brain injury or lack hands or something).
You have introduced a concept that can change the education tradition of slow and tedious to smart and fast. Boy your going to have a difficult time trying to get the american education system to change their ways but none the less I thankyou. It is a truely wonderful way to understand the Magic of numbers.
@Xavior Joyce Since I've posted that comment, I've graduated high school, lost my virginity, been through college, had 3 jobs, finished an apprenticeship, and bought a new car.
I enjoy reading all the comments ( both positive and negative ) esp those making fun of my accent (witty ones).This particular EasyCal technique (of faster division with 9) people find difficult to comprehend. But it is in fact easy. You can watch 3 more such videos on glad2teach website ( link given below the video above ) Shahryar (Glad2teach)
Dear hunkyjelly, your Ques: 8681140/9 As shown in the Easycal Video above, you just need to keep adding Digits in this pattern 8 (8+6) ( 8+6+8 ) ( 8+6+8+1 ) ...like that... put the last Digit Sum separately 8 (14) (22) (23) (24) (28) last digit sum is also (28 ). This 28 would get divided by 9 to get 3 (Remainder 1 or .11111 in Decimal ) Taking Care of Carrys ( Ten's digit of all 2 digit no.s ) & add that 3 9 6 4 5 7 1 . 111 ( ANSWER ) Method is easy as we are adding just single digits.
Chickenpoper, like you said these EasyCal techniques can make 'the hardest things simple'. Let me add here that they can also make 'simplest things simpler' Question you have given me belongs to the second category. It is already a simple Algebraic Expression that you need to simplify. You must have heard of the idiom "Birds of a feather flock together" . This is all we need to do. Arrange the Like Terms together (2x + 5x)+ (3n - 4n) + (-3y + 3y) = 7x -1n + 0y = 7x - n (Solved)
Another way to do calculation for this is, when your number (X digit) goes in 2 digits(p.x 15,12,17 etc) do /// X-9 = the next digit in line ////// ,im pretty sure that works (if i understood the reasoning behind this) and this away you'll avoid carrying big numbers in the end to divide by 9 Thanx for this video! Always amazed at how some ppl can see and utilize the properties of some numbers.
@alexanderdeg1 Let's call the dividend 'abcde' = 35768 and the quotient 'pqrs'. First digit of quotient: p = a = 3. Second digit of quotient: q = p + b = 3 + 5 = 8. Third digit of quotient: r = q + c = 8 + 7 = 15. Carry 1: q is now 9, r is now 5. Fourth digit of quotient: s = 15 + d = 15 + 6 = 21. Carry 2: r is now 7, s is now 1. Remainder: 21 + e = 21 + 8 = 29. Dividing this by 9 gives 3 (carry this to s, which is now 4), remainder 2. So 35768/9 = pqrs = 3974, remainder 2. Study #t=3m07s.
@justsmilehomie 4 7 9 8 5 3 divided by 9 after using glad2teach method , u'll get : 4 11 20 28 33 36 by carrying forward , u'll then get 5 3 3 1 3 36 ( while carrying forward, when 8 + 3 , eventually u will b getting 11 [a extra 1 for the third number]. ) thn 36 divded by 9 , u'll get 4. Add it up, there is the answer 53317 ^^ hope tat tis solves your problem....
you can easily check if a number is devisible by 3, 6 or 9. Build cross sum of the number, e.g. for 254871 checksum is 27. In this case 254871 is divisable by 3 or 9 with no remainder. 324582 is devisible by 3 or 6 with no remainder and so forth.
@shajjn You have to keep all your digits in your remainder, too. Instead of (4+3), it should be (3+4+1+6+3), which is 17. 17/9 = 1+8/9, so your answer should be 3794+1+8/9 = 3795.8889.
i have a better idea add all digits if the sum is 9 it is divisible by 9 example:189,126 add them 1+8=9 +9=18 +1=19 +2=21 +6=27 if two digits add again 2+7=9 if the sum is 9 it is divisible
Why doesn't the trick work for this number: 7612948 / 9 ?? I keep getting 834760 remainder 8 when the answer is 845883.111 Someone please explain this.
8 is below the second base 10. Then do the same was as was done with 9. 2104/8 Repeat the first algarismo.2 Multiply it by 2. (2 x2 = 4) Some neighbor. (4 +1 = 5) Multiply by 2 (.5 x2 = 10) Some with the next (10 +0 = 10) Multiply by 2. (10 x 2 = 20) Some with the next and divide by 8 (20 +4 = 24/8 = 3 = 2104 13 250 = 263
I think the hardest is working out square roots (without a calculator) including non square numbers. Any method you know that is better than A: Trial and error multiplication of numbers near the estimated square root. B: Continued Fractions (tedious to multiply out) C: Infinite Power Series
பள்ளி மாணவர்களின் கல்விக்காக உருவாக்கப்பட்ட இந்த சேனல் உங்களின் ஆதரவையும் பகிர்வையும் வேண்டுகிறது, உங்களின் பகிர்வு ஏதோ ஒரு மாணவரின் கல்விக்கு உதவும், நன்றி ( என்றும் தோழமையுடன் ) பகிர்வோம்..... பயன்பெறச்செய்வோம்..
@alexanderdeg1 3+5=8 8+7=15 so you have to put a 1 aside to add later, as you did. but then you forgot the previous number was 15 not 5, so you should have: 15+6=21 so you have to put a 2 aside not a 1 as you did... 21+8=29 so you put a 2 aside to add later but then the remainder is 9 and 9/9=1 so you have to put aside a 3 instead of a 2 and the remainder is 0, so it goes: 3851 +123 3974 hope i was helpful, even though 6 months too late..
@RainbowSnuff Let's go through it step by step. Your first digit is 2. Next up is (2+5) = 7. So far we have 27XX. Next up is (7+9) = 16. The one carries backward to our last step of 7, making it 8, and the 6 stays put. Now we have 286X. (16+8) = 24. Just like before, our 2 carries backward, making our 6 into a 8, and the 4 stays put. All together, that's 2884. Now for the remainder term. (24+1) = 25. 25/9 = 2 + 7/9, so our answer is 2886 + 7/9. Does that make sense?
i understand u perfectly! and ur classes are great btw. i learned a couple of the tricks when i was younger but the refresh is great. im born in Boston raised in Venezuela by the way!
Thank you for this help! I will be going back to School soon (first time in 4 years) and I was a bit scared I wouldn't be able to get ANYTHING right but know after watching your vids I feel that I have a chance.
@SweetAssasination Listen, i made a simple mistake and thats why people ask questions. Im sorry you feel like you need to put people down in such an agressive manner, but i still thank you for taking the time to help.
You missed something here. You correctly found 256 adding the numbers as you saw in the video. Just keep going with 6+3, which is 9. Don't write it down, but divide it by 9, as it is 2313/9. 9/9=1. Add this to the last number you found, which is 6. You now have 257.
I did it as initial 3 then 3x3 +5 = 14, 3x14=42, +7 = 49 49= 7x7 r 0 so 44+7 = 51 r 0. So for 221013÷8, initial 2, 2x2+2=6, 2x6+1=13, 13x2=0=26, 26x2+1=53 and for remainder 53x2+3 = 109, 109 = 13x8+5 so we get lines of working: 2 2 1 0 1 3 --------------- 2 6 3 6 3 1 2 5 ------------- 2 7 6 1 3 + 13 r 5 = 27626 r 5 Much as prefer your approach to 357÷7 I can't see how it scales up to 221013÷8. Please explain.
Yes, it works with 252. Pull down the 2, then add 2 + 5, which is 7. Then add 7 + 2, which is 9. That's your remainder, but 9 goes into 9 once, you add that one to the 27 that you already have.
Dear djstarsiee, glad that my existence was of some use to you !! You can visit Glad2teach website ( link below this video ) to watch 3 more such Easycal videos
Dont butt in, that just keeps him going , I would have to explain a whole lot and Im not really even interested in this, he keeps it going and you dont have all the facts or you wouldnt be asking what I"m talking about. thank you
Working it out like this you get 1/9---1/0---1/3----0/8 with a remainder of 25. 9 goes into 25 2 times so you add 2 to the 8 to get 0, carry the 1 over to the next column to get 1+1+3 =5, 1+0=1, 1+9=10....so 10150 remainder 7
oh my God, i cant believe it, this is such a great trick! I was never good in math and now i can solve these problems, it s not difficult :-)))))))))))))))))) anymore
@ErikLandvall it work look 1st number is 3 then 3 +6= 9 then 9+9=18 , put the 1 on 9 , 18 + 5= 23, 9 go in 23 by 2 then 2+ 8=10 , write down 0 only and add 1 to 9 n dont forget the other 1 so that is 11 n only write down 1 then 3 +1 = 4, 23-18= 5, so the answer = 410.5
I don't understand why this method doesn't work with 210/7 - the only answer I get is 235 or something when the simple answer is 30. What am I doing wrong now?
it is based on VEDIC DIVISION i.e. division by 1(-1) this is vinculum number i.e. 10-1=9. and same trick can be made for division by 8 or 7 or 11,12,13........so on.
I have a question He said that you put the last sum under the 9 and divide it But what if the last sum is number 8 or below We can't divide 9 to numbers below 9
2104➗8 is easy now. All I did is use the calulator to see how that was ➗done.233 is what the numbers would show. Leave the 4 alone because it will be the remainer of 7. Go back to 233 and add the two last numbers which will add to 6. Place the 6 on the 3 that between 2 and 3. Answer: 263. That is how I figuire out what was going on with that number. You could also use the 7 as a minus instead of a plus to get the middle number of the answer. Btw, I did ask glad2 tech on what they was going to say about 2104➗8 on how they were going to show how they did that. I told them their video cut off from that also waiting to see what he said how he would have figuire that out. Hopefully it about the same way.
Puyunet, since yr 2007 I have solved many "doesn't work" type of ques. Click on "View all comments" . This is a 3000 Year old algorithm, should work everytime Your ques: 278934 ÷ 9 Keep taking Digit Sum 2 (2+7) (2+7+8) (2+7+8+9) ..... Last sum (2+7+8+9+3+4) 2 (9) (17) (26) (29) Last Sum (33) ÷ 9 ( remember 9 goes '3' times in 33, leaving remainder 6 or .666 That is 3.666) Taking care of Carries (that is ten's digit of 2 digit no. ) 30989 + 3.666 30992.666... (ANS)
@glad2teach 278934/9 = 30992.66 1st write down 2, 2+7=9, 9+8=17, write down only the 7 n add the 1 to the 9, 17 + 9=26 write down the 6 and add the 2 to the 7, 26+3=29 write down the 9 and add the 2 to the 6, 29+4= 33 and , 9 go on 33 3 time so add 3 to the 9 that gave u 12, write down the 2 and add the 1 to 6+2= 9, 7 +2 =9, 9+1 = 10 write down the 0 and add the 1 to the 2 = 3, 33- 27= 6. so the answer is 30992.6
I tried to divide 213013 by 9, and the my answer wouldnt match the other, although, there was only 1 number diffence: My answer: 236677 R 3 Calculators answer: 236678.1111111111 Not much of a diffrece but, can you help me with this...?
@MilkyWay763 yes it worked for me example 56/9 bring the 5 down 5+6 =11 so 9 goes into 11 1 time with a remainder of 2 so 5+1 is 6 and bring the remainer over and it becomes 6.2
@ glad2teach WHY in the second division problem you called 10+2 when the 1 part of the ten is in the previous column above the six ready to make it a seven yet you use it in with the 0 which has confused the method even further...Please explain.
Dear MrFalconford, thanks for the kind words of appreciation. Change always happens gradually. From the next Academic Session (in August 2011) my EasyCal techniques would be officially taught in the curriculum of certain School Districts in USA. If the results are as expected then other school districts may follow.
Schools in US have realised the importance of empowering students with strong Mathematical Skills.
I am in University for Computer Science, Mathematics, and Statistics, and taking the hardest calculus courses I can. I cannot divide those numbers mentally, hell I don't even know a lot of my multiplication tables, but you don't need to know them to be good at math...
How good you are at math has absolutely nothing to do with how fast you can mentally calculate arithmetic.
All the best.
Thank you for teaching me this faster way! I was having a hard time in school because our teacher (principal) is so strict, she only explains it once then no more.
So so so so so so so thank you glad2teach!👏👍👏👍👏👍👏👍
:0 UR AMERICAN!!!
Dear Iemon Soda , with your best wishes I am still very much alive. Yes it has been 5 years since I created this video and many other videos like that.
If you were to read the replies I have been posting here for those many years you would find almost all types of questions solved by me that were troubling the visitors. Still every now and then someone posts a comment "this does not work...". Visit my glad2teach website to learn more (link given below the video above)
Shahryar
Glad2teach
I'm a really good with multiplication, addition, substraction but I always had a little leak with division. Really impressive stuff, I never worked on my division because I always thought I had to do the long way. Really nice video.
I've always been good with math, but thanks to some of your videos, I have found out by myself how to quickly find out how a number is perfectly divisible by 7 without easy ones like 575, 757, or 343, 434. I can do it for any 3 digit number, but it will not work for anything more than 3 digits.
I'm just happy that numbers stop at 10. If it stopped at 11, I'm sure I would fail a lot. Thanks for the video.
Moving up from D to B grade is surely a big leap of improvement. Another push and you would be on 'A'
-- All the Best
@Jarel8787, I would be glad to help.
Your Ques is 355 / 9 = ?
Like I have explained in the easycal video above,
keep taking the Digit Sum in this pattern
3(3+5) (3+5+5) (remember to write the last digit sum seperately)
3 8 ... (13) [Now just ask yourself how many times would 9 go into 13 ].
Of course just 'once' leaving Remainder 4 )
So 38 + 1 = 39 ( with remainder 4 )
Or you can write the Answer as decimal.
39.4444
I looked like I want to kill the phone when I was 'mentally calculating'
This is a brilliant video and the techniques shown are absolutely amazing. Thanks because you've really helped me a lot. Keep up the good work.
Really !! In most job exams calculator is strictly prohibited.
Shahryar (glad2teach)
Dear pqvimana, practice is the key to master anything. Glad that you have already understood its importance. Best Wishes
Shahryar (Glad2teach)
No!!!
you need another video on 2104 ÷8....i want to hear it..
I have just come up with how to do this in the way presented in this video (better said - similarly to the way presented in this video).
On the very beginning, let's pre-calculate, what we should get as solution and as the rest:
2104 ÷ 8 is 263 r 0
This is how to compute this using the glad2teach's way:
2104 ÷ 8 gives us the 3-digit number "ABC" (which os called "solution") plus the rest "R".
"abcd" is our 4-digit number "2104" (so a=2, b=1, c=0, d=4).
*PART 1*
Now we compute starting values "A.0", "B.0" and "C.0"
of our solution's digits "A", "B" and "C".
We compute "A.0":
A.0 = a = 2 (first digit of our number "2104")
A.0 = 2
We compute "B":
B.0 = A.0×2 + b = 2×2 + 1 = 4 + 1 = 5
(we multiply "A" by 2 as every 10 divided by 8 gives us the rest of 2)
B.0 = 5
We compute "C.0":
C.0 = B.0×2 + c = 5×2 + 0 = 10 + 0 = 10
R.0 = 10
We compute "R.0":
R.0 = C.0×2 + d = 10×2 + 4 = 20 + 4 = 24
R.0 = 24
We compute ultimate value of our rest "R":
R.0 ÷ 8 = 24 ÷ 8 = 3 r 0
C' = floor( 24 ÷ 8 ) = floor( 24 / 8 ) = floor( 3 ) = 3
(note: *floor function* of given number "x" is a function that gives the integer which is less then equal to "x")
en.wikipedia.org/wiki/Floor_and_ceiling_functions
C' = 3
R = R.0 mod 8 = 24 mod 8 = 0
(note: *"a mod b" is the number which is the rest of a÷b*)
en.wikipedia.org/wiki/Modulo_operation
*R = 0*
_____
*PART 2*
Now we make the calculations by adding from the ending digit to the first digit of our number "abcd" (that is, number "2104"):
In this way we obtain our ultimate values of the solution's digits "A", "B" and "C".
We compute ultimate value of "C":
C.1 = C.0 + C' = 10 + 3 = 13
C = C.1 mod 10 = 13 mod 10 = 3
*C = 3*
We compute ultimate value of "B":
B' = floor( C.1 ÷ 10 ) = floor( 13 ÷ 10 ) = floor (13/10 ) = floor( 1,3 ) = 1
B' = 1
B.1 = B.0 + B' = 5 + 1 = 6
B = B.1 mod 10 = 6 mod 10 = 6
*B = 6*
We compute ultimate value of "A":
A' = floor( B.1 ÷ 10 ) = floor( 6 ÷ 10 ) = floor (6/10 ) = floor( 0,6 ) = 0
A' = 0
A.1 = A.0 + A' = 2 + 0 = 2
A = A.1 mod 10 = 2 mod 10 = 2
*A = 2*
*PART 3*
So our solution "ABC" and the rest "R" is:
"ABC" = 263
"R" = 0
So
2104 ÷ 8 is 263 r 0
as it was pre-calculated on the very beginning.
In similar way, we could do also "÷7" (in this case, we would multiply every digit "a", "b", "c", "d" by 3 (as 10 mod 7 = 3, which means, 10÷7 gives the rest o 3).
But, technically, it multiplying the digits by 2 (when dividing by 8) or by 3 (when dividing by 7) will give us greater and greater numbers...
So this way is fast and comfortable only for dividing by 9.
So the Indian Math Tutors (such like "glad2teach") use other method to divide by 8:
ruclips.net/video/plTQ80l20Mk/видео.html
"Trick 359 - Divide Any Number by 8 Mentally"
Suresh Aggarwal
They just divide the number by 2, but three times :)
How to divide by 7?
I think, just do this in standard way, that means, calculate this by hand…
I think, also we could divide by 9 - just we divide given number by 3, but two times.
@@damianmatma708 Thank u so much
Good question !! Not a problem if your teacher hates Remainders. You can give her the answer as Decimal. For Example - while dividing by 9 if you get the Remainder 3 then in decimal form ( way a calculator shows the answer ) it would be .3333_ _
If it is 6 then in the decimal form it would be .6666_ _ . So on
Try it yourself -- Glad2teach
My friend which part of the world you are from ?
sri lanka
Iraq
France
USA
Dear BubbbaJay, this EasyCal technique is based on the interpretation of the ancient Vedic Mathematics from India. Vedic Math dates back to 3000 years. I am not aware if the great Trachtenberg has mentioned the same technique in the book he wrote in prison.
The modern system of counting we humans use today ( it is called " Decimal Place Value System" ) is based on Base 10 . It was discovered in India ( type " Base 10" in google and read..... ).
Good night. Thank you for explaining the method of division by 9. Postasses I would have to divide by 8 and other numbers.
Dear PetitTabarnak, thanks for the heartfelt appreciation. Division is supposed to be the hardest operation of Mathematics as it is difficult to visiualise all its steps in the mind.
In the EasyCal Video above I have done Division using simple Addition that too in a linear manner ( thus easy to visualise ). Just practice this technique to perfection.
Shahryar (Glad2teach)
hello sir, it is applicable only 9 not others.upload other division also .
okay
Kodam Sruthi your correct madam
999 ÷ 9 is not 99 but 111
You have to carry the one each time making it 111. @@Copplettt
Thanks Captain
Dear ColorMeMidori, you have a good observation !! However it is not always that the first digit of the question would be the first digit of your answer as well. There can be a Carry backward digit that can get added to the first answer digit.
wah bout dat division 8 prob
Dude, u ROCK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
after practicing ur tricks, i was able to complete my maths paper 2day an hour before the time limit....u have really given me the greatest encouragement...If i become successful, i will recommend all to try out these tricks..thanx a lot
Guys it works with all numbers!
1st: see how close the number is to ten (for example in 2104/8, 8 is 2 less than 10)
2nd: carry the first number down (2)
3rd: multiply by the answer to step 1 and add the next # (2 times 2 is 4, plus 1 is 5)
4th: continue in this sequence (5 times 2 is 10 plus 0 is zero [remember to add the one above the five])
5th: find the remainder (multiply 10 by 2 and add 4)
6th: put the remainder off to the side and see how many times 8 can go into it (in this case 24/8 is 3)
7th: add the 3 above the 0
8th: add to get the final answer of 263
*Note if this does not work for you then you are to stupid to figure it out. Please do not post stupid comments because they will just highlight your own stupidity.
+Elliott McGuirt 51656/8?
Nice, love your troll hunting through year old comment threads. In my comment I was merely presenting a fix to make a varied form of the video's method work for all problems. I do apologize if my end note came off as arrogant, but it was there basically to prevent troll comments like yours. Have a nice day, and please take a basic english grammar class.
Elliott McGuirt Fuck u😤😤😤😤😤😤😤
Did someone hurt you? XD
I never instigated any of this nonsense. I'll speak with you again when you can type correctly (no offense if you have some brain injury or lack hands or something).
Elliott McGuirt YOU ARE ONE FUCKED UP PERSON. Did I type that correctly for you?
Can you read?
STOP INSULTING PEOPLE!!!!
(GEEEZUS )
You have introduced a concept that can change the education tradition of slow and tedious to smart and fast. Boy your going to have a difficult time trying to get the american education system to change their ways but none the less I thankyou. It is a truely wonderful way to understand the Magic of numbers.
"You're time starts... NOW" I paused the video :D
@Xavior Joyce Since I've posted that comment, I've graduated high school, lost my virginity, been through college, had 3 jobs, finished an apprenticeship, and bought a new car.
Quite hard
Lol
Lol
You are not "time starts", you are PunkZombie1300
I enjoy reading all the comments ( both positive and negative ) esp those making fun of my accent (witty ones).This particular EasyCal technique (of faster division with 9) people find difficult to comprehend. But it is in fact easy. You can watch 3 more such videos on glad2teach website ( link given below the video above )
Shahryar (Glad2teach)
all i can say it is awesome trick it's nicely ,,,, now i wondering divisor from 2 to 8...for these method ....
Pagal
Dear hunkyjelly, your Ques: 8681140/9
As shown in the Easycal Video above, you just need to keep adding Digits in this pattern
8 (8+6) ( 8+6+8 ) ( 8+6+8+1 ) ...like that... put the last Digit Sum separately
8 (14) (22) (23) (24) (28) last digit sum is also (28 ). This 28 would get divided by 9 to get 3 (Remainder 1 or .11111 in Decimal )
Taking Care of Carrys ( Ten's digit of all 2 digit no.s ) & add that 3
9 6 4 5 7 1 . 111 ( ANSWER )
Method is easy as we are adding just single digits.
Thanks , Very Helpfull .
Chickenpoper, like you said these EasyCal techniques can make 'the hardest things simple'. Let me add here that they can also make 'simplest things simpler'
Question you have given me belongs to the second category. It is already a simple Algebraic Expression that you need to simplify.
You must have heard of the idiom "Birds of a feather flock together" . This is all we need to do. Arrange the Like Terms together
(2x + 5x)+ (3n - 4n) + (-3y + 3y)
= 7x -1n + 0y
= 7x - n (Solved)
Can you make another video with all other numbers. Please.
kartik
Another way to do calculation for this is, when your number (X digit) goes in 2 digits(p.x 15,12,17 etc) do
/// X-9 = the next digit in line //////
,im pretty sure that works (if i understood the reasoning behind this) and this away you'll avoid carrying big numbers in the end to divide by 9
Thanx for this video! Always amazed at how some ppl can see and utilize the properties of some numbers.
can we do this in decimals
@alexanderdeg1 Let's call the dividend 'abcde' = 35768 and the quotient 'pqrs'.
First digit of quotient: p = a = 3.
Second digit of quotient: q = p + b = 3 + 5 = 8.
Third digit of quotient: r = q + c = 8 + 7 = 15. Carry 1: q is now 9, r is now 5.
Fourth digit of quotient: s = 15 + d = 15 + 6 = 21. Carry 2: r is now 7, s is now 1.
Remainder: 21 + e = 21 + 8 = 29. Dividing this by 9 gives 3 (carry this to s, which is now 4), remainder 2.
So 35768/9 = pqrs = 3974, remainder 2.
Study #t=3m07s.
nice.thanks,this really helped me.i usually take sooo long to do this type of questions
I got a maths test in 4th of July on the whole thing we did this year and your videos are very helpful to me.
thats soo cool finally i can figure out my math homework
I had fun watching these videos. I love Math and these tricks are like magic! Thank you!
Excellent
@justsmilehomie
4 7 9 8 5 3 divided by 9
after using glad2teach method , u'll get :
4 11 20 28 33 36
by carrying forward , u'll then get
5 3 3 1 3 36
( while carrying forward, when 8 + 3 , eventually u will b getting 11 [a extra 1 for the third number]. )
thn 36 divded by 9 , u'll get 4.
Add it up, there is the answer 53317
^^ hope tat tis solves your problem....
what about division by 8
you can easily check if a number is devisible by 3, 6 or 9. Build cross sum of the number, e.g. for 254871 checksum is 27. In this case 254871 is divisable by 3 or 9 with no remainder. 324582 is devisible by 3 or 6 with no remainder and so forth.
That really helped me thank u Indian man 😭😭😭
stoNex Vaioleti that’s racist don’t say that
Was this supposed to be funny
Any land of the same.
@shajjn You have to keep all your digits in your remainder, too. Instead of (4+3), it should be (3+4+1+6+3), which is 17. 17/9 = 1+8/9, so your answer should be 3794+1+8/9 = 3795.8889.
i have a better idea add all digits if the sum is 9 it is divisible by 9
example:189,126 add them 1+8=9 +9=18 +1=19 +2=21 +6=27
if two digits add again 2+7=9 if the sum is 9 it is divisible
i know that rules
good one
thanks
hi, would you like to share more tips, etc for math please. I want to teach my son
Saj Sajid hi
honestly i found these vids after getting pissed at the practice asvab so far helping a lot.
Hlo sir it is only applicable for 9...not for other....if u agree hit a like
Why doesn't the trick work for this number: 7612948 / 9 ?? I keep getting 834760 remainder 8 when the answer is 845883.111 Someone please explain this.
I just did it the old fashioned way ... it worked better.
How to do 2104/8 plz tell.
Plz make a video dividing with different numbers plz.
This video is awesome. Thanks for this video
8 is below the second base 10.
Then do the same was as was done with 9.
2104/8
Repeat the first algarismo.2
Multiply it by 2. (2 x2 = 4)
Some neighbor. (4 +1 = 5)
Multiply by 2 (.5 x2 = 10)
Some with the next (10 +0 = 10)
Multiply by 2. (10 x 2 = 20)
Some with the next and divide by 8 (20 +4 = 24/8 = 3 =
2104
13
250 = 263
Thanks Buddy
beno fernandes 13?
I guess that was a mistake that 13
But u understand
I think the hardest is working out square roots (without a calculator) including non square numbers.
Any method you know that is better than
A: Trial and error multiplication of numbers near the estimated square root.
B: Continued Fractions (tedious to multiply out)
C: Infinite Power Series
how about at the start for the 10's
பள்ளி மாணவர்களின் கல்விக்காக உருவாக்கப்பட்ட இந்த சேனல் உங்களின் ஆதரவையும் பகிர்வையும் வேண்டுகிறது, உங்களின் பகிர்வு ஏதோ ஒரு மாணவரின் கல்விக்கு உதவும்,
நன்றி ( என்றும் தோழமையுடன் )
பகிர்வோம்..... பயன்பெறச்செய்வோம்..
i didnt unerstand
Replies
Einstein your voice helps so much it hard to forget what you say.
1:33
-1 that’s 3 quick maths
@99divy
1st digit = 2
2nd digit = 2+2=4
3rd digit = 2+2+1=5
4th digit = 2+2+1+9=14 (therefore 3rd digit = 5 and 4th = 4)
remainder = 2+2+1+9+5=19
19/9=2r1 as remainder = 2, add 2 to the answer
2466
i can divide when i was 3
Ok
Could*
This method is really interesting.
Sir 221013 ÷9 =3571 hai remainder 3 ans 3751.3 hoga na .thanks for the trick
shiv shakti in this case but not if remender is 7 then??
@alexanderdeg1
3+5=8
8+7=15 so you have to put a 1 aside to add later, as you did.
but then you forgot the previous number was 15 not 5, so you should have:
15+6=21 so you have to put a 2 aside not a 1 as you did...
21+8=29 so you put a 2 aside to add later but then the remainder is 9 and 9/9=1 so you have to put aside a 3 instead of a 2 and the remainder is 0, so it goes:
3851
+123
3974
hope i was helpful, even though 6 months too late..
that acsent thow
stop watching vines
kartik
@RainbowSnuff
Let's go through it step by step. Your first digit is 2. Next up is (2+5) = 7. So far we have 27XX. Next up is (7+9) = 16. The one carries backward to our last step of 7, making it 8, and the 6 stays put. Now we have 286X. (16+8) = 24. Just like before, our 2 carries backward, making our 6 into a 8, and the 4 stays put. All together, that's 2884. Now for the remainder term. (24+1) = 25. 25/9 = 2 + 7/9, so our answer is 2886 + 7/9. Does that make sense?
ok I try
2 3 5 7 9 ÷ 3
/ 1/1/ /
2 5 0 7 9÷3=3
2507+3=2510
so the awnser is 2510?
Checking with calculator...
Awnser= 7,859.6666666667
Da fuuuu
RaZe Shot oh thanks!
bitch
YOURE SO BLOODY DUMB AHAHAHAHAHAHA
xXBangamiteXx 📚🇮🇳
So are so fucking dumb... Dumbest of all...
i understand u perfectly! and ur classes are great btw. i learned a couple of the tricks when i was younger but the refresh is great. im born in Boston raised in Venezuela by the way!
sir upload 8 division also
Thank you for this help! I will be going back to School soon (first time in 4 years) and I was a bit scared I wouldn't be able to get ANYTHING right but know after watching your vids I feel that I have a chance.
This doesn't work very well with other numbers. Doesn't work at all. It only works with 9... -_-
agreed
Because you divide 9 by 9, at a certain part.....
techki Phil
Hii
this methode work with others numbers
@SweetAssasination Listen, i made a simple mistake and thats why people ask questions. Im sorry you feel like you need to put people down in such an agressive manner, but i still thank you for taking the time to help.
257 * 9 = 2313 so when doing 2313 ÷ 9 we'll get 256.… and then what?
You missed something here. You correctly found 256 adding the numbers as you saw in the video. Just keep going with 6+3, which is 9. Don't write it down, but divide it by 9, as it is 2313/9. 9/9=1. Add this to the last number you found, which is 6. You now have 257.
InDaStreetBeats Entertainment
you did something wrong...
2313÷9
=256
-----------6+3=9
-----------9÷9=1
----256+1=257
Raib Mizan
No we get 257 I think you forgot to take 1 as carry
I learn this two weeks ago in my Pre-IBDP Algebra II/ Trig. class, but with polynomials. It's called the synthetic division.
disliked , so many limitations
Kiran Shinde .. tell me where you got wrong
I did it as initial 3 then 3x3 +5 = 14, 3x14=42, +7 = 49
49= 7x7 r 0 so 44+7 = 51 r 0.
So for 221013÷8, initial 2, 2x2+2=6, 2x6+1=13, 13x2=0=26, 26x2+1=53
and for remainder 53x2+3 = 109, 109 = 13x8+5 so we get lines of working:
2 2 1 0 1 3
---------------
2 6 3 6 3
1 2 5
-------------
2 7 6 1 3 + 13 r 5 = 27626 r 5
Much as prefer your approach to 357÷7 I can't see how it scales up to 221013÷8. Please explain.
I am a maths teacher
meth teacher*
Robin Henriksen lol
Mahesh Kalita
Mahesh Kalita
Want a oreo?
Yes, it works with 252. Pull down the 2, then add 2 + 5, which is 7. Then add 7 + 2, which is 9. That's your remainder, but 9 goes into 9 once, you add that one to the 27 that you already have.
What would you do then if you have for example - 9+8? Would you write 17? That would make the answer longer, and therefore, wrong... What do you do?
Dear djstarsiee, glad that my existence was of some use to you !!
You can visit Glad2teach website ( link below this video ) to watch 3 more such Easycal videos
I am so dumb at maths, your vids are helping me step by step. Thank you for existing :)
Please, the video is cut short. How do I figure 2104\8
Dont butt in, that just keeps him going , I would have to explain a whole lot and Im not really even interested in this, he keeps it going and you dont have all the facts or you wouldnt be asking what I"m talking about. thank you
So what we do? / END / DAFUQ?
Working it out like this you get 1/9---1/0---1/3----0/8 with a remainder of 25. 9 goes into 25 2 times so you add 2 to the 8 to get 0, carry the 1 over to the next column to get 1+1+3 =5, 1+0=1, 1+9=10....so 10150 remainder 7
Thank you man I sucked at math I barley knew my timestable but thanks to your tricks I am normal!!! THANK YOU!!!
oh my God, i cant believe it, this is such a great trick! I was never good in math and now i can solve these problems, it s not difficult :-)))))))))))))))))) anymore
Thank you sir for explaining the maths in nice & easy way
@ErikLandvall it work look
1st number is 3 then 3 +6= 9 then 9+9=18 , put the 1 on 9 , 18 + 5= 23, 9 go in 23 by 2
then 2+ 8=10 , write down 0 only and add 1 to 9 n dont forget the other 1 so that is 11 n only write down 1 then 3 +1 = 4, 23-18= 5, so the answer = 410.5
I don't understand why this method doesn't work with 210/7 - the only answer I get is 235 or something when the simple answer is 30. What am I doing wrong now?
You make it so easy and fast. Genious you are.. no doubt about it. thanks for sharing.
Does this work with any one digit number or does it only work with 9?
it is based on VEDIC DIVISION i.e. division by 1(-1) this is vinculum number i.e. 10-1=9. and same trick can be made for division by 8 or 7 or 11,12,13........so on.
I have a question
He said that you put the last sum under the 9 and divide it
But what if the last sum is number 8 or below
We can't divide 9 to numbers below 9
Gianna Crisha then that woulb simply be your remainder
2104➗8 is easy now. All I did is use the calulator to see how that was ➗done.233 is what the numbers would show. Leave the 4 alone because it will be the remainer of 7. Go back to 233 and add the two last numbers which will add to 6. Place the 6 on the 3 that between 2 and 3. Answer: 263. That is how I figuire out what was going on with that number. You could also use the 7 as a minus instead of a plus to get the middle number of the answer. Btw, I did ask glad2 tech on what they was going to say about 2104➗8 on how they were going to show how they did that. I told them their video cut off from that also waiting to see what he said how he would have figuire that out. Hopefully it about the same way.
Puyunet, since yr 2007 I have solved many "doesn't work" type of ques. Click on "View all comments" .
This is a 3000 Year old algorithm, should work everytime
Your ques: 278934 ÷ 9
Keep taking Digit Sum
2 (2+7) (2+7+8) (2+7+8+9) ..... Last sum (2+7+8+9+3+4)
2 (9) (17) (26) (29) Last Sum (33) ÷ 9 ( remember 9 goes '3' times in 33, leaving remainder 6 or .666 That is 3.666)
Taking care of Carries (that is ten's digit of 2 digit no. )
30989 + 3.666
30992.666... (ANS)
I just realised that this EasyCal Video has been watched by 1 Million people. Unless the same few are watching it over and over again ... lol
Thank You
@glad2teach 278934/9 = 30992.66
1st write down 2, 2+7=9, 9+8=17, write down only the 7 n add the 1 to the 9, 17 + 9=26 write down the 6 and add the 2 to the 7, 26+3=29 write down the 9 and add the 2 to the 6, 29+4= 33 and , 9 go on 33 3 time so add 3 to the 9 that gave u 12, write down the 2 and add the 1 to 6+2= 9, 7 +2 =9, 9+1 = 10 write down the 0 and add the 1 to the 2 = 3, 33- 27= 6. so the answer is 30992.6
I would like to learn how to divide other numbers using the base number!!! Thanks so much for posting this! This is amazing!,
I tried to divide 213013 by 9, and the my answer wouldnt match the other, although, there was only 1 number diffence:
My answer: 236677 R 3
Calculators answer: 236678.1111111111
Not much of a diffrece but, can you help me with this...?
@MilkyWay763 yes it worked for me example 56/9 bring the 5 down 5+6 =11 so 9 goes into 11 1 time with a remainder of 2 so 5+1 is 6 and bring the remainer over and it becomes 6.2
@ glad2teach WHY in the second division problem you called 10+2 when the 1 part of the ten is in the previous column above the six ready to make it a seven yet you use it in with the 0 which has confused the method even further...Please explain.
OMG! I this is so simple! I actually understood. I need this to score high for a timed examt for a job. Thank You! Subscribed!