Moment Of Inertia Of T-Section 🔥| Engineering Mechanics | Civil Stuff
HTML-код
- Опубликовано: 10 окт 2024
- Moment Of Inertia Of T-Section 🔥| Engineering Mechanics | Civil Stuff
Friends in this video we are going to going to discuss how to calculate moment of inertia of T section or angle about its centroidal axes.
If you find this video helpful then make sure to hit that LIKE, SHARE and SUBSCRIBE button and don't forget to press that bell icon
Thank you🙏
Our previous videos:-
M.I. Of Symmetrical I-Section:- • Moment Of Inertia Of S...
Moment of inertia of Unsymmetrical I section:- • Moment Of Inertia Of U...
Problem-3 On Moment Of Inertia- • Moment Of Inertia | Pr...
Problem-2 On Moment Of Inertia:- • Moment Of Inertia | Pr...
Problem on parellel axis theorem:- • Problem On Parellel Ax...
Parellel Axis Theorem:- • Parallel Axis Theorem🔥...
Problem-1 On Moment Of Inertia:- • Moment Of Inertia | Pr...
Moment of inertia formulas:- • Moment Of Inertia Form...
Moment of inertia:- • Moment Of Inertia | Se...
1st moment of area:- • 1st Moment Of Area | L...
Moment of inertia of rectangle:- • Moment Of Inertia Of R...
Moment of inertia of Hollow Rectangle:- • Moment Of Inertia Of H...
..........................................................................................
Queries solved:-
Moment of inertia of T Section
What is parellel axis theorem
Derivation of parellel axis theorem
How to apply parelle axis theorem
What is centroid
What is moment of inertia
How to calculate moment of inertia
Moment of inertia Engineering Mechanics
Moment of inertia in
Moment of inertia of symmetrical i section
Moment of inertia of Unsymmetrical I section
Moment of inertia of L Section
Moment of inertia of an Angle section
.........................................................................................
Follow us on-
Personal Instagram:- / kunal_badgujar_07
Facebook:- m.facebook.com...
Instagran:- www.instagram....
Twitter:- / civilstuff
Blogger:- civilstuff07.blogspot.com
Gmail:- civilstuff07@gmail.com
#civilstuff
#momentofinertia
#TSection
15 min me bade acche se samjha Diya yaar apne tou .
Esa tou collage ke teacher bhi nahi samjha pate .
Jesa apne mujhe 1st attempt me hi samjha diya .
Thank You 💕
Thanks for the appreciation
@@CivilStuff✨💫WELCOME💫✨
Your explanation is very neat and clean that's why I understand in one time
Thanks for the appreciation
Your handwriting and diagram is really neat.Nice and easy explanation Sir 💐✌🍫 Thank you !!!
Thanks for the appreciation...
your videos are amazing, helps me a lot for my exams✌🏼
Thanks for the appreciation
And also for me.
sir ap bhut acha padhate ho
Yese hi video bnate rho sir
Last part was awesome db^3/12
I was getting confused in that✌️✌️✌️✌️✌️
Thank you
counter check for CAD
Area: 15000.0000
Perimeter: 700.0000
Bounding box: X: -75.0000 -- 75.0000
Y: -125.0000 -- 75.0000
Centroid: X: 0.0000
Y: 0.0000
Moments of inertia: X: 53125000.0000
Y: 15625000.0000
Products of inertia: XY: 0.0000
Radii of gyration: X: 59.5119
Y: 32.2749
Principal moments and X-Y directions about centroid:
I: 53125000.0000 along [1.0000 0.0000]
J: 15625000.0000 along [0.0000 1.0000]
Thank you for encouraging me add more one example and make the working to be viewed well
Maza aa gaya kya Sam jhaya hai
Bahot shukriya bhai
Thanks
You are nice teacher and your conception are to easy for understand.
Thank you so much
thanku sir u are a great teacher
Thanks for the appreciation
Thank you ❤ bhaiya😊
Thankyou ❣️
Thanks bro, now I understand
❤️❤️❤️ really Thank u so much
Thank you soo much I got 10/10 in assignment because of u brooo 💜 ♾️💝 thanku
Thanks for the appreciation
Very nice video
Thanku so much ❣️🥰🙏
My biggest headache is now solved....!!
Thank uhh❤️
Welcome
Thank you so much 🥰 bro
Sir very good explanation and thanks 🙏
Welcome
There is one Mistake where you have return 13 instead of 12
But is very good channel for learning
Sorry for the mistake
& thanks for the appreciation
Don't forget to follow me on my personal instagram for more updates: instagram.com/kunal_badgujar_07
Your all video are great .
Thank you
Thank you sir
Thanks
Aapka bahut bahut sukriya
Welcome
Sir please help
Does we are applying parallel axis therom on IYY please reply🙏🙏
And on which diagram we have to apply parallel axis therom or it depends up on question ❓
Thank you sir great experience with you
Good keep it
Different between safe load and buckling load
I am considering that you are asking this question in regards to buckling phenomenon.
The load at whch column buckles will be your buckling load.
And safe load will be the load which column can bear without failure.
So safe load = buckling load/factor of safety
Note that safe load will always be more than the buckling load
Thanks sir ti was very help full
Most welcome
awesome sir
Thanks a lot broo 👍👍
Thankyou so much Sir 🙏
Welcome
Great explanation bro !!
Now I am okay in this topic
Keep it up 🙏🙏🙏🙏
Thank you sir ❤️
Welcome
Great sir
👍
Too good sir ji
Thank You Sir, Suprb Explanation sir
Thanks for the appreciation
NYSC Sir 👌
Mera ek aadami ne pucha moment of inertia kya hota hai me kya bolu ?🙄
Thank you bro
Sir Concept sahi hai...
But answers nhi match ho rhe hai.😢..
Mai khud 5 times hand calculate kiya hu..
My answer may be wrong brother.
But i hope you got the concept correctly
@@CivilStuff yes Sir..
Thank you so much..
Your all videos are very helpful for me..
And sorry, if I said something wrong 🙏🙏
No no
It is good that you are correcting me and other viewers will also find this helpful.
Thanks sir for helping me
Welcome sir
nice explanation
Thanks
Thank you so much. This was very helpful
Icc nikalne me db3/12kaise likhe sir please help me sir
Sorry sir Iyy ka sutra kaise laye sir db^3/12
Btother yeh video me mene rectangle ka moment of inertia ke formulae derive kiye hai.. Yeh video aap dekhiye,apko sab samaj me aa jayega
ruclips.net/video/XPHiPs0HEBs/видео.html
Sir I've a question can u slove ?
Yes
You can contact me on civilstuff07@gmail.com
Are BhAiya aap Kha Seekhe Yeah hme Sikhwa do. 🥰
Namumkin jaisi Koi Bhi Cheezz nhi jo Khud na bne bo koi Naseev nhi Milegi manzil chahe kreeb nhi mai hu dil ❤ ka Ameer bhai Gareeb nhi. 🙏❣️❣️
👌
awesome
Thnku bhai..
Tankuuuuu
Super sir 💙💙💙💙💙💙💙💙💙🙏🙏
Thanks for the application
खंड के गुरुत्वाकर्षण के केंद्र से गुजरने वाली x-x और y-y अक्ष के बारे में टी-खंड की जड़ता की गति का पता लगाएं
Thanks for you
Welcome brother
Thank you v. much Sir!
Welcome sir
Well explained.allah give u more knowledge .and subscriber also❤️👌
Thank you sir for the appreciation
Sir aapne bottom se q Liya h kisi kisi book m to 1 rectangle ka 50/2 kr rkha Aisa q h
Okk.. Dekhiye jo humne y find kiya hai apko usse ya to top se find karna padta hai..ya to bottom se find karna padta hai jesa ki humne video me kiya hai. To jesa ki humne y bottom se find kiya hai uski wajah se hamara datum bottom ho jayega, uski wajah se Rectangle 1 ke liye y1=50/2+150 kiya hai..
Agar ap y top se find karte ho to uss case me hamara datum top consider karna padega.. To uss case me y1=50/2 karna padega
Hope you understand... If you have still any doubt feel free to ask
I have a doubt, how can you solve this problem. Plz again one more
Please share your problem at civilstuff07@gmail.com
@@CivilStuff okay sir
Thank you so much bhai bhut achha samjhay
Welcome
Bro please engineering mechanics ka baaki ka part bhi complete krdo
Yes brother
Thank you so much sir for this awesome video.
Crisp and useful content 🔥
Thanks for the appreciation
bro can you please tell something about your education qualification...it will help me to select better option for future....please🙏🙏🙏
Brother currently m in final year of btech in civil engineering.. What kind of information you would like to know
what is your future plan, after completing b tech? and bro i am in 2nd year of civil engineering any suggestion for me?
Let's talk on Instagram... Dm me.. We'll talk after some time i have some work now...
@@CivilStuff toh bhaiya aap pdo shi se phir smjhana
Ok sir... Thanks for the feedback
Aapne jo Ixx ka formula liya usme g kya he
Suffix
Sir aap 2 second topic ka btana plz
Sorry sir... I am not getting what ypu are talking
Hook law or bta do
Nice sir
Welcome
find the moment of inertia for T- section top with flange 200*15mm and web 20*100mm about its centroidal vertical axis
😢
What happened?
hello, is there any continuation or is this the complete answer ?
It is complete answer
Pls upload videos in English,everyone coming here is educated
Sir appne Jo Ixx ka bar Kiya he kesa bar kiyahe ar bi Ixx2 ka kease bar Kiya he sir ham ka samaj me nai aaya he ar ek bar bata da sir tik he 😊😊
Hi,
Actually i am not getting what you are asking
Could you pls elaborate more so i can help you?
Apne Jo figure draw Kari he vo hum exam me draw kar sakte hai
Yes why not
Sir 3rd semester ka paper civil engineering diploma SFD and BMD with couple problem lo pls
Ok brother...
@@CivilStuff thanks sir❤
Brother if you have any doubt or question to ask you can contact through mail civilstuff07@gmail.com
Sir isme x1 or x2 kyu nhi find kra rectangle1 or rectangle2 m
Q ki brother T-Section symmetrical hota hai about its vertical axis. To uska centroid usi Vertical axis pr lie karega.. To humein ye pata tha isliye humne vo find ni kiya.
Y_ calculation is wrong that's why answer = 🥲
Sir 2 digit calce set kese kare
Matlab
Ye questions btaye please 🙏🙏 sr
Konsa?
;ro vide aachi hai pr back music aur kaam kro bass bhout jayda disattract kr rahi hai plzzzz🙏🙏🙏
Brother next video se background music nhi add karunga me... And thanks for tge feedback
Isme x axis aur y axis lene ki zarurat nahi hai na ?
Nahi bro... The entire calculation will change if you change the locations of X and Y axis
Y baar wronge hai na
Sir rectangle 2 mai 130 kese araha h please batado
Konsa 130 mm brother
@@CivilStuff ha
Sir ji Y ka man and h ka man me thoda dikat hai please sir thoda samjha dijiye
Brother aap instagram pr contact kijiye me aapko jarur help karunga
SFD and BMD Ko pada digiye
Yess brother
Hesehi mechan8cs complete ho jata hai
We'll start for SOM
Sir. Can you write the question in hindi please.
Casio me kese dekhaaa
Matlab... Samajh nahi aya brother muje
نبي ترجمهههه عندي اختبار بعد شوي
those who are not getting of (hy) here ȳ - y1 for hy1, y2 - ȳ for hy2
Bhai mer khyal tt average rheda hh jde briefly explain Naa kra tnn
❣️
why you did not find the x1 andx2
Which x1 and x2
It's is symmetric so x bar 0
Correct
What is the need to do so much trouble in a simple way
Means...
Y axis dikhawo
y bar answer is getting a diff one
Show me your calculations
civilstuff07@gmail.com
Bd3/13 was wrong
I wish everything was in English
Sir
Iyy2 nhi nikale
brother your value of IXX1 IS WRONG THERE IS CALCULATION MISTAKES
H is 100
No need to use parallel axis theorem in 2nd eq
Nice explanation 👌
Yes bro u r right
Ixx1 ka answer kaise aynega
I have already uploaded some videos You can watch other videos on the same concept
Ixx2 ka bd3/12 hoga aapane bd3/13 likh hai