Sir may you please solve 10.62 end of chapter question on thevenins theorem plz. It will be of great help from this sadiqu book as we are having exams in a few days
In case of circuit containing dependent source, the procure is to insert either a 1A current source or 1V voltage source. See this ruclips.net/video/3gPoJkLovXo/видео.html
@@HunzlaAwan Jab bhi video ke muttaq sawal puchte hain to video time ka hawala deten hain. Agar aap time 16.57 pe jo answer hai, uske bare me puch rahi ho to oh 2/3= 0.6667 hai
As always, amazing explanation sir. Thank you
Welcome dear
Thank U.
Sir may you please solve 10.62 end of chapter question on thevenins theorem plz. It will be of great help from this sadiqu book as we are having exams in a few days
Done
AOA Sir in what way the 10 0hm and -j4 ohm is in series in example 10.8
oh sorry, I forgot to put brackets. it should be 10 +(-j4||(6+j2))
Why you added voltage source 1 VOLT?
In case of circuit containing dependent source, the procure is to insert either a 1A current source or 1V voltage source.
See this ruclips.net/video/3gPoJkLovXo/видео.html
thank u
Welcome dear. Best wishes.
18:26, why is it 0-v1 not vth - v1
Please watch this video from time 7:35
ruclips.net/video/6sR-wKsJgcQ/видео.htmlsi=c1S-fNm-l89tY6qF
Sir 0.6667ohm kis tarah aya ?
Mujhe to kahin nazar nahi aaya !
@@ElectricalEngineeringAcademy sir Apne Jo answer nikala tha
@@HunzlaAwan Jab bhi video ke muttaq sawal puchte hain to video time ka hawala deten hain. Agar aap time 16.57 pe jo answer hai, uske bare me puch rahi ho to oh 2/3= 0.6667 hai
@@ElectricalEngineeringAcademy g sir issi ka pooch Raha hoo
@@HunzlaAwan bta to dia k 2/3 braber hota hai 0.6667 ke