All those strings that present in the stack at some time or the other are called "viable prefix" ( read from Bottom to Top and ignore $ ). The initially written 11th iteration is rightly cut as the content of stack written there is not a viable prefix, coz as soon as the Parser sees E+E in the stack parser identifies it as a "handle" and replaces it with E, so the string E*(E+E) is never is the stack.
Best explanation on RUclips ever heard, Thanks for clearing doubt🤟🤟🤟🤟
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Thanks the life saver, i have exam tommor my doubt about this topic is cleared
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Thanks... Finally learned this topic from your video!
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Great Explanation 👍🏻👍🏻👍🏻👍🏻👏🏻
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Very nice explanation
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So nicely explained ... Thank you
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All Videos in Playlist are very Helpful💌💌🥰 and Very Nice Explanation....
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Thanks... finally understand these concepts
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Soooooo well explained
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Cool 👌
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Good explanation 👌
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Khub balo maam damn 🔥
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liked the video...clearly explained
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So freaking clear and easyyy ❤️!!!
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Thank you so much mam it helped me alot..
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Very beautifully explained 👏👏👏
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Good explanation 😊. Thank You Madam
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Thanks a lot for explaining in a superb way...
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All those strings that present in the stack at some time or the other are called "viable prefix" ( read from Bottom to Top and ignore $ ).
The initially written 11th iteration is rightly cut as the content of stack written there is not a viable prefix, coz as soon as the Parser sees E+E in the stack parser identifies it as a "handle" and replaces it with E, so the string E*(E+E) is never is the stack.
Thanks princess ;)
Very easily explained mam 😊
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Thank you so much mam!! This was very well explained!
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good example of SR parsing👍
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Thanks for ur explanation mam 😊
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clearly explained, Thank you so much!
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Keep uploading 😇
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thankyou didi end moment help paper in 5 minutes
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Thank you maam 🙏
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fantastic experience ☺️😍
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ThankYou ma'am
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Thanks...I got it !!!!
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thnk u mam
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Thank you savior
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So much thanks
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thanks for help
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Thanks.
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3:35 Thank you
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tq mam
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❤
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Ma'am how we can find conflict in SLR parsing.and also make a vedio on SLR(1) problem through a table format.
Ansh, I've already uploaded detailed video on SLR(1). I hope it'll clear all your doubts :)
nice video
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S > empty | A
A > empty | aAc | B
B > empty | bBc
String aabccc
Could anyone please help to solve this problem?
Could anyone tell please what is action in 3rd step 🙏🙏🙏
How to take input string..will they give us in exam?
Yes, it should be given in the part of question
Mam its good but explain line 10
There, first id is reduced to E ..... then E+E is reduced to E
@@CSEconceptswithParinita i got that mam...my cd exam is over...thankyou for the lovely concept...🙂
@@grieza8022 always welcome 😊
🤔
Why is that 11th iteration is cut, these are crucial that has to be explained clearly
No it's not
She forgot to parse E+E before the closing bracket
HELLO, HELLO, HELLO MAAM 0:00
From avniet
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There is!
srm walon padh lo
Share kardo😅
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Thanks mam❤️
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Thanks 👍🏻
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