When CH1 and CH2 are Off, then inductor will release its charge and D2 and D1 will be in forward bias condition and current flow towards load to source.....so how the current is again positive????
Yes bro you are right but , Current directions is sam When Ch1 and ch2 are on then Current flow l ( inductor) to lode And after ch1 and ch2 are off then Current flow l to lode , not lode to inductor.
Mind blowing explanation. One time listen automatically understood. Thank u so much madam
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When ch1 and ch2 are off , load inductance generates voltage and forward biases both D1 and D2
How will current flow in diodes ,they are reversed biased
back emf of rle load flows through diode....
When CH1 and CH2 are Off, then inductor will release its charge and D2 and D1 will be in forward bias condition and current flow towards load to source.....so how the current is again positive????
Yes bro you are right but ,
Current directions is sam
When Ch1 and ch2 are on then Current flow l ( inductor) to lode
And after ch1 and ch2 are off then Current flow l to lode , not lode to inductor.
When both the chopper are off,then what is the source that will send current to flow through the diode d1
thank u madam for making this type of helpful video
plzzz upload more & more video
Thank you
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LEARN AND GROW
Thanks ma'am ❤️❤️❤️❤️
Glad to help you
thanku maam it was really helpful...
Glad to help you
Thank you mam
Glad to help you
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Alpha greater then 0.5 ku hota h ye to batao ye 0.5 kha se aa gya
Choper 2 to off h to waha see current kaise aaya
Ma'am output voltage negative kese h
Ch2 se current kaise likalega
nice :-)
Thank you for your words
With regards
Learn and grow
Thanks ma'am 👍👍👍
Glad to help you