In Internal flow of non circular ducts the hydraulic diameter is 4A/P... Where P is the wetted perimeter... Annulus means the flow will be between two concentric tubes... so the outer surface of the inner tube and inner surface of the outer tube are get wetted...hence P = πDo + πDi...
For Nu value databook has not just 3.66 It has 3.66+((0.0668(D/L)Re Pr)/(1+0.04(D/L)Re Pr)) Please confirm me with correct equation I have exam tomorrow
Sir mass flow rate kg /min mai hai ...usko ap ne kg/sec mai change nhi kiya ....last equation mai
Nice clear explanation
Sir we will take m value converts the seconds but you take minits value. why sir
Sir,
your explanation is good👍
Kaise pass karna hai
Sir how to identify the which problem are external or internal
sir, why u have taken mass flow rate in(kg/min) in heat tranfer equa of 1st problem?, we have to take it in kg/s
On the same step mas flow rate is converted into kg/s
@@VENKATQ love ur teaching sir❤
but we are getting length value as 4.83
to find engine oil properties Tm=147 degree C should we do interpolation to find out the values?
Yes..if u need exact answer do interpolation...else take nearest value...
Tqq sir
Where water values should be taken in data book
in my version of data book it is available in page no 22...search around through index...
how to calculate outer diameter if only inner diameter is given in tube
Sir why the perimeter of the tube is π (Do+Di)
In Internal flow of non circular ducts the hydraulic diameter is 4A/P...
Where P is the wetted perimeter...
Annulus means the flow will be between two concentric tubes... so the outer surface of the inner tube and inner surface of the outer tube are get wetted...hence P = πDo + πDi...
Well explainasion
What about...T.infinity valuse...where you use
hi can i please have the name of the book you are using
sir how did you calculate the value of cp
Cp of water is a constant value...
@@VENKATQ yes sir but on internet cp of water is given as 4182 J/KgC,thus got confused.
Thanks sir
What book do you take the formula from?
s subhrmanyam
I got q = 6127.639 W at the end.
For Nu value databook has not just 3.66
It has 3.66+((0.0668(D/L)Re Pr)/(1+0.04(D/L)Re Pr))
Please confirm me with correct equation
I have exam tomorrow
Don't get confused...it is 3.66 only...for the equation you ststed condition will be given in details...which will not be asked in examinations...
underdog