lecture17 | Problems on Forced convection | Internal flow | Heat and Mass Transfer

[@user-tz6zl6gm6j]

the flow is turbulent and it is Re less than 10,000 you have to take Nu=0.036 Re⁰⁸ pr⁰³³ *(D/L)⁰⁰⁵⁵....but you have taken Re great than 10,000 ?

[@shafi1164]

Sir you made a mistake sir , the flow is turbulent and it is Re less than 10,000 you have to take Nu=0.036 Re⁰⁸ pr⁰³³ *(D/L)⁰⁰⁵⁵....but you have taken Re great than 10,000 how ....

[@raphazard8737]

I think he made mistake

[@fishhushh4546]

Tqqqq so much sir

[@varinformation8798]

Sir, if Re

[@414jeevankumar2]

hw to do interpolization sir

[@sreenivaskalyan3282]

Sir MOM subject chepandi sir

[@jallachandrashekhar9579]

Thank you sir

[@rameshsompalli2025]

Thanks a lot sir

[@VENKATQ]

thank uu...share channel with ur frnds...

[@arunmahe6503]

Thank u luv u sir...

[@varunkashetty9769]

Sir U have used 2 different values for area in last problem.
When should we use which formula ?

[@VENKATQ]

for mass flow rate use cross sectional area (3.14d*d/2)...for convective heat transfer heat is liberated form the surface...so we should consider surface area (3.14*d*L).

[@user-tz6zl6gm6j]

for finding equivalent dia we should use cross section area or surface area?

[@VENKATQ]

it depends on the area through which heat transfer occurs...if heat transfer occurs from the surface, then we have to consider surface area...

[@ANJANAR-hj5mt]

Why u took cross sectional area for calculation mass flow rate??

[@VENKATQ]

for any fluid flow condition thats the formula...m = A*V

[@ANJANAR-hj5mt]

@@VENKATQ like...I asked y cross sectional area and not overall area?

[@VENKATQ]

@@ANJANAR-hj5mt to find volume flow rate we have to consider cross sectional area since the area perpendicular to the flow is cross sectional area only

[@414jeevankumar2]

Sir is there the viedo on the lmtd

[@VENKATQ]

In lecture 26 to 28 discussed about LMTD method

[@karthikveeravalli4921]

Which published data book you preffers sir

[@VENKATQ]

Kothandaraman