Continuity Equation Semiconductor Derivation Part 1

Поделиться
HTML-код
  • Опубликовано: 25 янв 2025

Комментарии • 25

  • @406giridharchikka4
    @406giridharchikka4 2 года назад +2

    best video in internet world to understand the eqation of continuity

  • @ranu021
    @ranu021 2 месяца назад

    Others were trying to explain through definition but you were explaining it like a kindergartener could understand thankyou very much for making it easier

  • @granthoffman8682
    @granthoffman8682 3 года назад +5

    This stuff is killing me in school. So interesting, but very difficult. Your videos are a godsend. Thank you sir.

  • @TerranIV
    @TerranIV 3 года назад +1

    Wow, thanks for this very thorough and eminently understandable explanation of such a vitally important concept in semiconductors! I haven't been able to wrap my mind around this all semester but I think I finally get what's going on here. Thanks so much!!!

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  3 года назад

      You are welcome! Glad you are finally able to wrap your head around it, it's probably the most challenging topic in intro semiconductors. I had to learn it several different ways before I finally started to understand what was going on.

  • @BRUSCKORB
    @BRUSCKORB 7 месяцев назад

    incredible video

  • @xonisak
    @xonisak 4 года назад +3

    when dividing ∆V throughout the equation, dp/dt side is not zero, shouldn't there be a 1/∆V on the dp/dt side? @ 6:52

    • @moritzhuck7575
      @moritzhuck7575 4 года назад +3

      P (total number) goes to p (Number Density or total Number per Volume)

    • @ManiAvila
      @ManiAvila Год назад

      Thanks, I was having the same doubt when dividing by ∆V

  • @atd9945
    @atd9945 Год назад

    very easy to follow. thank you

  • @theillusionzone
    @theillusionzone 3 года назад +1

    4:54 "Since this is the total amount of charge added...." Err no Jordan; since you multiplied the current density by area dimensionally it must be the 'total amount of current added'.

  • @Arun-bk1fq
    @Arun-bk1fq 3 года назад +2

    Sir, continuity equation relates only minority carriers or it is also applicable to majority carriers?

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  2 года назад +1

      Great question, it makes some approximations which are only valid for minority carriers.

  • @suruchiverma48
    @suruchiverma48 5 лет назад +1

    One question sir. At 3.55, on the left hand side it is dp while on the right hand side it is ∆V. Why not ∆p or dV?

    • @jordanedmunds4460
      @jordanedmunds4460 5 лет назад +1

      Excellent question. I'm approximating the derivative using a finite ∆V, implicitly assuming that the time derivative is a function of the small volume element. dV would be more in keeping with calculus notation, and would work just as well.

  • @zharaalipanahi8084
    @zharaalipanahi8084 2 года назад

    Thanks 🙏

  • @lorebarta1698
    @lorebarta1698 3 года назад

    Wow thanks

  • @magnetar_spc
    @magnetar_spc 3 года назад

    which program do you use for the notes?

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  2 года назад

      These days I use photoshop, but I used to use sketchbook.

  • @girivardhangiri4324
    @girivardhangiri4324 4 года назад

    Drift current mrans

    • @girivardhangiri4324
      @girivardhangiri4324 4 года назад

      Means

    • @abdelmoulabakal3047
      @abdelmoulabakal3047 2 года назад

      @@girivardhangiri4324 maybe the answer is late but the drift current is the current caused by the electric field

  • @ly3282
    @ly3282 5 лет назад

    why bother subtracting recombination rate and adding generation rate?cuz G=R, they get cancelled

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  5 лет назад +4

      Initially we assume that G=R, but strictly speaking this is only true under steady-state. Transiently, it isn’t true. Additionally, G and R might actually be functions! (Of space or time), and so to solve the continuity equation you need to include their full functional form.

    • @yomamafatoshi
      @yomamafatoshi 4 года назад +3

      Solar cells as an counterexample where G is larger than R (hopefully haha)