Formation of imines and enamines | Aldehydes and ketones | Organic chemistry | Khan Academy
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- Опубликовано: 10 сен 2024
- How aldehydes and ketones react with primary and secondary amines to for imines and enamines. Created by Jay.
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Organic Chemistry on Khan Academy: Carbon can form covalent bonds with itself and other elements to create a mind-boggling array of structures. In organic chemistry, we will learn about the reactions chemists use to synthesize crazy carbon based structures, as well as the analytical methods to characterize them. We will also think about how those reactions are occurring on a molecular level with reaction mechanisms. Simply put, organic chemistry is like building with molecular Legos. Let's make some beautiful organic molecules!
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How can you justify a direct nucleophilic attack on the carbonyl carbon without protonating the oxygen first? From what I can see, this reaction shouldn't meaningfully progress once the pH in solution eclipses 6-7 (optimum pH = 4-6).
The person that makes the video is really good explaining concepts, I have been watching a lot your videos for my Ochem class and they are really helpful. Thank you so much.
Makes a lot of sense, thank you so much!
Thank you sooo much ...❤🥺🥺🥺
Couldn't find a better teacher!
Beyond helpful videos
Hey, was wondering why u kept using the lone electrons on your lsat 2 examples instead of HSO4-
Wouldn't the O on the SO4- molecule be a better place to take the H+
You saved my ass in organic chemistry, thanks a lot
wow, thank you
holy stepwise mechanism, batman!
Thank you for all your help.
thank you so much!
How come oxygen cannot just take the proton from the first amine that attacked rather than taking one from an amine floating in solution... steric reasons? 9:15
What's affecting on reductive elimination
At 5:31, why does acid protonate the OH rather than the N of the carbinolamine? My thinking is that NH3 is a stronger base than OH, so NH3 would be protonated over OH. Can anyone help me reason where I'm going wrong please?
Amanda Wong it's just being done to explain the product, giving mechanisms is nothing but an estimated guess as to what really the compounds would be undergoing in order to form the final product. In case acid protonates the N of carbinolamine, the final product would be different. It will happen though in nature, but this fact can't be used to explain the product formation here. Hope you get it.
Remember the principle of microscopic reversibility. All of these steps are in equilibrium, so yes you could reprotonate the N but then you would be back to the previous intermediate rather then going forward to the desired product. That is why in practice you want to remove water from the reaction mixture for instance by azeotropic distillation which drives the reaction to completion.