Digital SAT - 5 Most difficult Math Questions
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- Опубликовано: 10 мар 2024
- Are you aiming for a perfect score on the Digital SAT? Join Jackie Caruana, an expert tutor with a perfect score, on an exclusive journey to conquer the Digital SAT Math section. In this essential guide, Jackie reveals top strategies, ingenious tricks, and critical tips designed to secure a perfect 800 on the Digital SAT Math. Dive into an in-depth analysis of the 5 most challenging Digital SAT Math questions directly from the Collegeboard, tailored for students gearing up for the SAT in May 2024!
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For the parabola question 7:30, there is a way to interpret the expression that was derived.
(a+b+c) = 64a - 14
Knowing that a must be greater than zero for the parabola to open upward, we rearrange the expression as follows:
64a = (a+b+c) - (-14)
For a to be greater than zero, (a+b+c) must be greater than -14. So, choice D.
When (a+b+c) = -14, it means that we have a straight line (x^2 term vanishes). For values below -14, we have a downward parabola.
For sum and product of solutions 12:30 14:00, it is useful to remember the parabola equation in factored form.
a (x - m)(x - n)
where m, n are roots
a [ x^2 - (m+n) + mn]
Comparing coefficients with the standard form
a [ x^2 + (b/a)x + (c/a) ]
We have the SHORTCUT relations:
m+n = -(b/a)
mn = (c/a)
Yes, exactly 😎
Since f(-9)=f(3) means they are x intercepts, whenever it shows like that it means they x intercepts right. because I thought it could be something else other than the zeros. I thought -9 and 3 can have same y values but not x intercepts. like what if they could be points like (-9,5) and (3,5).
Good question! I could've explained this better in the video....it doesn't necessarily mean they are the x-intercepts....I say that in the video because I know that the x-intercepts are equidistant to the vertex, which I wanted to find. So short summary, any parabola is symmetric around its vertex. If two points on the parabola are at the same height, they are equidistant from the vertex...
So The given condition
f(−9)=f(3) tells us that the function takes the same y-value at these points....In your example of (-9,5) and (3,5) that would also work as the y-values are at same height and are equidistant! .... in any case, as long as we keep the y-values the same and understand their relation to the vertex (equidistant), we can get the x-coordinate of the vertex! =) =)