Gravitation: Change in Energy and Work for Satellite Orbits

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  • Опубликовано: 7 сен 2024

Комментарии • 36

  • @neetugovil6989
    @neetugovil6989 5 месяцев назад +2

    Wonderful explanation, I don't think I will do any question of this topic wrong again.
    Thank you

  • @meflea3675
    @meflea3675 10 месяцев назад +2

    I genuinely love your video style so so much. I find it incredibly hard to read and focus on written notes, but your way of presenting is so clean and perfect for me I cannot begin to express my gratitude. I will definitely share this with anyone I know who needs help with the topics you cover.
    And I have my notifications turned on to see other topics you'll cover as well as I genuinely find your presentation very intuitive.

    • @stepbystepscience
      @stepbystepscience  10 месяцев назад

      I'm so glad that my videos are helpful to you! There are many ways to learn and I enjoy making these videos to help others.

  • @cappmasters7253
    @cappmasters7253 3 месяца назад +2

    this video is powerful bro

  • @PookieAndAnnie
    @PookieAndAnnie 23 дня назад +1

    Thank you so much sir.
    This is really helpful

  • @RyanThomas-ly2dl
    @RyanThomas-ly2dl 5 месяцев назад +2

    thanks

  • @GoodluckOgieva-pj9ds
    @GoodluckOgieva-pj9ds 10 месяцев назад +1

    U are a scholar
    I like the way you derive the formula
    Really nice

  • @KaarenYazdani
    @KaarenYazdani 3 месяца назад

    It was a great video, but I have issues with it. How did we get the initial mass? Is the initial mass the mass of the satellite and the mass of the fuel? How do we know how much fuel we need? For example, if we were going to put a 10-kilogram satellite into orbit 400 kilometers above the surface of the Earth, how do we know the amount of energy required without knowing the amount of fuel we need in the first place?

  • @user-xg7vt7nr3y
    @user-xg7vt7nr3y 6 месяцев назад +1

    Nice bro keep it up❤

  • @ghostmortal1724
    @ghostmortal1724 4 месяца назад

    Loved it❤❤

  • @malcolmboyley2334
    @malcolmboyley2334 3 года назад +1

    Excellent video as usual thank you

  • @stephenzhao5809
    @stephenzhao5809 3 года назад +1

    Thanks!

  • @ranonymous27
    @ranonymous27 Год назад +1

    Amazing videos! please make videos about Gravitational potential too

    • @stepbystepscience
      @stepbystepscience  Год назад +1

      Have you seen this video: ruclips.net/video/z3ujg_CkslI/видео.html

    • @ranonymous27
      @ranonymous27 Год назад +1

      @@stepbystepscience yes I have

    • @stepbystepscience
      @stepbystepscience  Год назад +1

      @@ranonymous27 Was it what you were looking for?

    • @ranonymous27
      @ranonymous27 Год назад

      @@stepbystepscience yes, the explanation was great, thank you very much

  • @anikasingh3127
    @anikasingh3127 3 года назад +1

    Thank you so much. All my concepts are clear!

  • @cappmasters7253
    @cappmasters7253 3 месяца назад

    the formula for work is not applicable if velocity initial for satellite is zero because kinetic energy 1 will be zero

  • @par7aspd835
    @par7aspd835 2 года назад +1

    Why do some textbooks cite work done = change in GPE, when you have stated work done= change in total energy?

    • @stepbystepscience
      @stepbystepscience  2 года назад

      Both are correct, in the video I was also considering kinetic energy.

    • @neetugovil6989
      @neetugovil6989 5 месяцев назад

      You can use W=∆PE when it is given that satellite's orbit was changed without causing any change in velocity or very slowly.

  • @udayreddy3705
    @udayreddy3705 Год назад

    quick question sir, if you are bringing the satellite closer to earth instead of away would our r1 then be the greater value?

    • @eicos9276
      @eicos9276 Год назад

      Yeah it would be. When you move closer to the Earth it is favourable in terms of gravitational potential energy, as you do negative work to move it closer. GPE is negative inside the escape point, so it will get "more negative" if that makes sense?

  • @ibrahimsaidali3140
    @ibrahimsaidali3140 Год назад +1

    A: I have difficult to accept the KE=1/2mv^2
    B: Why is there the 1/2?

    • @stepbystepscience
      @stepbystepscience  Год назад

      Good question, here is a page that discusses the derivation of the equation,
      physics.info/energy-kinetic/