I am the student of Engineering Geology and have rock mechanics in course. your lecture have provided great aid to me in understanding stress condition. thank you soo much
At 8:29, you have explained that sigma x equals sigma 1, then at 10:33, how is it possible to write formula for sigma 1 using sigma x and sigma y? Could you please explain as soon as possible?
If I'm right so, Here sigm 1and 2 are major and minor prin stresses acting on pri.plans at the angle of 45° .. due to normal stresses x,y on normal plane...
Around 13:31, its bit confusing that, why you are using two set of formulas for finding maximum shear stress. for finding the value of sigma 1 and sigma 2 we need values of tou max, sigma 1, sigma 2 as per your explanation in red ink but after that, how could tou max can be found out by using sigma 1 and sigma 2? could you please explain clearly?
Suppose in the question it is directly given that the principal stresses are 100 and 50 MPa. You are required to find the max. Shear stress. Then you can directly get your answer , without even knowing the normal stresses sigma X and sigma y.
Why not you solve an industrial problem using ansys and check whether the product design is safe or not. teach us application oriented, thats what we need.
this is the most and the brilliant explanation method that I found in all youtube big RESPECT sir
I am the student of Engineering Geology and have rock mechanics in course. your lecture have provided great aid to me in understanding stress condition. thank you soo much
Thanks a lot sir. You are Awesome, Love from Pakistan. You always tried to clear the points that are not cleared in other youTube videos.
25:21 now to got to strength nd stress difference
Next level of explination👌
Superb explanation sir✌️
Thank you sir aapne Meri bhot badi problem solve Kar di aapke video se Mai solve Kar pa rha Hun saare numerical
Clearly explained sir thanks for ur valuable class 💯
Nice plz upload more lecture
Thank you sir, good explanation 👌🏾
Sir ur lectures are very clearly plz upload more videos on strength of material sir
At 8:29, you have explained that sigma x equals sigma 1, then at 10:33, how is it possible to write formula for sigma 1 using sigma x and sigma y? Could you please explain as soon as possible?
If I'm right so, Here sigm 1and 2 are major and minor prin stresses acting on pri.plans at the angle of 45° .. due to normal stresses x,y on normal plane...
Thanks a lot, SIr!
Brilliant explanation sir😊👏👏
beautifully explained. Thank you!
Excellent.Also please explain about distortion energy theory
Great lecture, THANKS!
How find value of sigma3?
Why won't you give more lectures on You tube guriji it is really useful for average students like me
Pls explain von mises theory also
Very nice sir thank 👍
Thankyou
very good lecture , thanks sir
can you plz explain all the theory of failure.
can you explain with boundary diagram ?
plz upload more videos on the same topic.
Thank you, Sir!
Lect is good... But there should be derivation of shear stress formula I was expecting...
Dear I aldready derived those formulas from Mohr circle..you can watch my lecture on Mohr circle. there I have shown how that formula came.
sir plz uploiad other theories of failure
sir apni gurudev _/\_
Around 13:31, its bit confusing that, why you are using two set of formulas for finding maximum shear stress. for finding the value of sigma 1 and sigma 2 we need values of tou max, sigma 1, sigma 2 as per your explanation in red ink but after that, how could tou max can be found out by using sigma 1 and sigma 2? could you please explain clearly?
Suppose in the question it is directly given that the principal stresses are 100 and 50 MPa. You are required to find the max. Shear stress. Then you can directly get your answer , without even knowing the normal stresses sigma X and sigma y.
Thanks a lot sir
tq sir
Why not you solve an industrial problem using ansys and check whether the product design is safe or not. teach us application oriented, thats what we need.
Sir plz do more vedios
thanks
It seems Arnab Goswami is teaching.
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