How to Convert Non Linear Equations to Linear Form Y = mX + c

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  • Опубликовано: 15 сен 2024
  • • Linear Approximation a...
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Комментарии • 23

  • @NnanyelugoNwokwelu
    @NnanyelugoNwokwelu 9 месяцев назад +3

    What if x and y are not in the equation

  • @nakatonakilijjaritah
    @nakatonakilijjaritah 5 месяцев назад

    Use transformation to linearize this equation y=[(a+√x)/b√x]^2 and employ linear regression to determine the parameters a and b.Basing on your analysis predict y at x=1.6. Given table X: o.5,1,2,3,4 and Y:10.4, 5.8, 3.3, 2.4, 2. Thanks Tr

  • @earadicator
    @earadicator 4 года назад +6

    I like this but for ax^2+b (at least) when graphing the horizontal axis as x^2, since n^2>=0, the graph of the linear equation can not continue to the left of the origin. For y/x, x=0 can not be plotted, etc.

  • @lansizhui5301
    @lansizhui5301 3 года назад +3

    Wow.. this got easy... thanks for reviewing the igcse paper question really needed it😊

  • @mochibins
    @mochibins 3 года назад +1

    Thanks very much. This was way more helpful than any other video

  • @TaraSulman
    @TaraSulman 4 года назад +3

    Thank you so much. This was very helpful! :)

  • @TheMuseOnline
    @TheMuseOnline 4 года назад +4

    This is extremely helpful, thank you so much!! I come from a non-mathematical background and I have one question if I may. At 16:31 can you please explain what you mean by "ln e is reciprocal of one another"? How did you eliminate the e term there?

    • @edgyman519
      @edgyman519 10 месяцев назад +1

      you posted this comment 3 years ago but im still replying to help others.
      ln means log base e, so ln e is = 1
      so at ln e^(-bx), he took the '-bx' to the coefficient
      so he was left with -bx ln e
      which is = -bx x 1
      so you are left with only -bx

  • @nivetharaja6502
    @nivetharaja6502 Год назад +1

    Thank you so much sir👍

  • @sswsean004
    @sswsean004 Год назад +1

    how about y= a(x-k)^2 +b ?

  • @vilakshanVV
    @vilakshanVV 2 года назад +1

    nice explanation method

  • @paanazmi8062
    @paanazmi8062 3 года назад +2

    Hi can anybody help, after i convert from non-linear to Y=mX + c (linear form), why the graph won't plot straight line in desmos graph simulator?

    • @DisciplineKing
      @DisciplineKing 3 года назад +2

      because the straight line is actually an approximation of the real values. we get the straight line by drawing a 'line of best fit'. look it up :D

    • @paanazmi8062
      @paanazmi8062 3 года назад +1

      @@DisciplineKing i see..thank you very much. i want to show to my cousin Y=mX+C for better understanding by plotting on desmos...seems didnt work..do you know any other online graph that plot Y=mX+c?

    • @DisciplineKing
      @DisciplineKing 3 года назад +1

      @@paanazmi8062 yes, GeoGebra is another free online graph plotting tool.

    • @paanazmi8062
      @paanazmi8062 3 года назад

      @@DisciplineKing thank you very much for your help

  • @NnanyelugoNwokwelu
    @NnanyelugoNwokwelu 9 месяцев назад +1

    How about 1/v +1/u =1/f

  • @oookok8552
    @oookok8552 4 года назад +1

    At 18:10, why is the graph going in the +x, -y region? Since y is in the natural log, it cannot be negative. Can someone explain?

    • @MathematicsTutor
      @MathematicsTutor  4 года назад

      Interesting. Note that the given exponential function has no restrictions on its domain.
      ln y has no restrictions on its range. If you connect this with the example provided, you will appreciate that the graph domain has no restrictions. Hope that helps. Thanks

    • @oookok8552
      @oookok8552 4 года назад

      @@MathematicsTutor Thanks alot Mr. Kumar! I understood what you said, thanks again!

  • @IKE-kf7cg
    @IKE-kf7cg 5 месяцев назад

    y=(a+x)/(b+x) can you transforming

  • @zarithimran2486
    @zarithimran2486 3 года назад +1

    Nice video

  • @NnanyelugoNwokwelu
    @NnanyelugoNwokwelu 9 месяцев назад +1

    What if x and y are not in the equation