Hi. I have watched many tutorials on variety of subjects. This guy is a great tutor and explains things clearly and slowly, and I thank him for sharing this knowledge on line.
Thank you so much. Studying for the civil professional engineering exam in the states. Your approach is clear, concise, and impactful. I love your conceptual approach to the physical and mathematical. This kind of thinking, the "what if" is what's required to pass the exam. 3 examples and a healthy dose of theory! Certainly I grew in wisdom today!
Thanks for the comment. Absolutely, and this is probably the easiest way to do it for laminar flow. But in this video I was mainly trying to demonstrate how to read the chart.
Hi mate, how come you didn't use the density of water ? i got the cal of 1946566.337 when i added density (kg/m3) of 20 degrees at density of 998.2? when working out reynolds number
Hi Bruce, this is because there are two ways to calculate Re, the way I did it is ( velocity x diameter) / kinematic viscosity, where I assume kinematic viscosity is 10^-6 m^2/s. The other way you can do it, which is the way shown on the x-axis of the Moody Diagram and the way I think you have done it, is (velocity x density x diameter) / dynamic viscosity. Kinematic viscosity is defined as dynamic viscosity over density, so for this example where I assume kinematic viscosity as 10^-6 m^2/s, dynamic viscosity would be 10^-3 kg/ms (assuming density is 1000 kg/m^3, you have used a more precise definition). So calculating Re using the formula on the Moody diagram would be Re = (1000 x 1.64 x 0.012 )/10-3=19680. Hope that makes sense and clears it up?
I swear that he's the best lecturer at the university, Thank you so much for being such a great gentleman.
Thanks 😊
My guy never disappointed when come to his fields of expertise. Thank you once again and Keep it up, I'm the biggest consumer of your materials.
Sway more clear and compréhensible than the one I have just watched, Thanks for the effort this is what we call an éternel charity of knowledge.
Thanks for the comment!
Really well presented material. I’m returning to this subject after 30 years and this kind of clarity is greatly appreciated. Well done sir.
Hi. I have watched many tutorials on variety of subjects. This guy is a great tutor and explains things clearly and slowly, and I thank him for sharing this knowledge on line.
Agreed. He has a gift.
crystal clear explanation, much appreciated thank you
Thank you so much. Studying for the civil professional engineering exam in the states. Your approach is clear, concise, and impactful.
I love your conceptual approach to the physical and mathematical. This kind of thinking, the "what if" is what's required to pass the exam.
3 examples and a healthy dose of theory! Certainly I grew in wisdom today!
Perfect explanation and use of example slowly taking us through each step. Thanks a lot! :)
Thanks!
Moody diagram finally makes sense, thank you very much!! !
Thanks for the comment, glad it helped!
AMAZIINGGG thanks so much for this!! really good help before my exam
Thanks and dont stop !!
Thanks for the comment, really happy it helped!
many thanks your videos are very useful
Thanks, glad it was useful!
For 1968 as the Re, you can divide that by 64 for laminar flow. You'll get f as .0325
Thanks for the comment. Absolutely, and this is probably the easiest way to do it for laminar flow. But in this video I was mainly trying to demonstrate how to read the chart.
Thanks ❤
Great video, do you have videos on Hydrology & Water Resources??
Thanks for the comment. I am planning to do some in the next few months, so keep an eye on the channel!
do you know how you would obtain this in Watts (W) ?
Hi mate, how come you didn't use the density of water ? i got the cal of 1946566.337 when i added density (kg/m3) of 20 degrees at density of 998.2? when working out reynolds number
Hi Bruce, this is because there are two ways to calculate Re, the way I did it is ( velocity x diameter) / kinematic viscosity, where I assume kinematic viscosity is 10^-6 m^2/s. The other way you can do it, which is the way shown on the x-axis of the Moody Diagram and the way I think you have done it, is (velocity x density x diameter) / dynamic viscosity. Kinematic viscosity is defined as dynamic viscosity over density, so for this example where I assume kinematic viscosity as 10^-6 m^2/s, dynamic viscosity would be 10^-3 kg/ms (assuming density is 1000 kg/m^3, you have used a more precise definition). So calculating Re using the formula on the Moody diagram would be Re = (1000 x 1.64 x 0.012 )/10-3=19680. Hope that makes sense and clears it up?
@@fluidsexplained1901 hey mate, yes it does thank you very much.
Thanks