Fluids Explained
Fluids Explained
  • Видео 51
  • Просмотров 811 718
I built a lab water flume in my office at home
I built a mini lab flume in my office at home, and this video explains how I did it. Lab flumes are used to give practical demonstrations to engineering students, but when the covid-19 pandemic led to a series of national lockdowns in 2020, I had no choice but to build my own flume at home.
The channel Practical Engineering was one of my inspirations for this project, check it out at the link below:
ruclips.net/channel/UCMOqf8ab-42UUQIdVoKwjlQ
Music:
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Lights by Sappheiros soundcloud.com/sappheirosmusic
Creative Commons - Attribution 3.0 Unported - CC BY 3.0
Free Download / Stream: bit.ly/LightsSappheiros
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Просмотров: 3 337

Видео

Pumps in Bernoulli’s Equation (Lesson 5 part 1)
Просмотров 2,2 тыс.3 года назад
In this video we work through an example of how to design a pumping system. This includes using Bernoulli’s Equation to find how much pressure head the pump needs to add to the system and the pumping power equation to find how much power the pump would require to operate. The example used in the video is Shustoke Reservoir in Warwickshire, UK. This is a representative example to explain the cal...
Bernoulli’s Equation for a Real Reservoir/Pipe System (Lesson 4, Part 2)
Просмотров 2 тыс.3 года назад
In this video we show how Bernoulli’s Equation accounting for losses can be applied to a real-world system with a 117,000m long pipe. The example used in the video is The Elan Valley Reservoirs / Elan aqueduct. More information about this system is below: en.wikipedia.org/wiki/Elan_Valley_Reservoirs en.wikipedia.org/wiki/Elan_aqueduct
Bernoulli's Equation Including Losses (Lesson 4, Part 1)
Просмотров 2,2 тыс.3 года назад
In this video we show how to use Bernoulli’s Equation accounting for losses to work out the velocity of water in a pipe for a model reservoir / pipe system.
Local Loss Equation, Continuous Loss/Darcy-Weisbach Equation and Moody Diagram (Lesson 3, Part 3)
Просмотров 2 тыс.3 года назад
In this video we both measure and theoretically predict losses in total head in a pipe due to local and continuous losses. The video includes examples of how to use the local loss equation, the continuous Loss/Darcy-Weisbach equation and the Moody Diagram. This video includes a real example with a model constant head tank and pipe. The link below is a slightly more detailed explanation of the M...
Laminar Flow, Turbulent Flow and Reynolds Number (Lesson 3, Part 2)
Просмотров 25 тыс.3 года назад
In this video we look at an example of laminar and turbulent flow, discuss the underlying theory with reference to Reynolds Number and work through some examples of how to calculate if a flow is laminar or turbulent.
Friction and Viscosity in Pipe Flow (Lesson 3, Part 1)
Просмотров 4,2 тыс.3 года назад
In this video we look at the effects of friction and viscosity in real pipe flows, and how these processes lead to a flows velocity profile. This video includes a real example with a model constant head tank and pipe.
Bernoulli’s Equation for Pressure of Ideal Systems (Lesson 2, Part 2)
Просмотров 1,8 тыс.3 года назад
Following on from the last video, where we showed how to use Bernoulli’s Equation to work out the velocity of water in a pipe being fed from a constant head tank, in this lesson we are going to use the same procedure to work out the pressure in a pipe. Again, we will be assuming there are no energy losses (‘ideal’ system). This video includes a real example with a model constant head tank and p...
Bernoulli’s Equation for Velocity of Ideal Systems (Lesson 2, Part 1)
Просмотров 3,4 тыс.3 года назад
In this video we show how to use Bernoulli’s Equation to work out the velocity of water in a pipe being fed from a constant head tank, assuming there are no energy losses (‘ideal’ system). This video includes a real example with a model constant head tank and pipe, and theoretically derived results using Bernoulli’s Equation are compared to this test.
The Principle of Continuity (Lesson 1, Part 3)
Просмотров 3,7 тыс.3 года назад
This video introduces the principle of continuity in hydraulics and fluid dynamics. The lesson includes demonstrations using a model flume and worked examples of the.
Steady / Unsteady Flow and Uniform / Non-uniform Flow (Lesson 1, Part 2)
Просмотров 23 тыс.3 года назад
This video introduces the definition and concept of Steady / Unsteady flow and Uniform / Non-uniform flow in hydraulics and fluid dynamics. These are the main ways in which we can characterise flows. This topic is extremely important, as we need to understand the type of flow we are dealing with so we know if the equations we are applying to that flow are valid. The lesson includes demonstratio...
Discharge, Velocity and Cross-sectional Area in Hydraulics and Fluid Dynamics (Lesson 1, Part 1)
Просмотров 6 тыс.3 года назад
This video introduces the concept of discharge, velocity and cross-sectional area in hydraulics and fluid dynamics. These are the essential parameters we need to describe a flow. The lesson includes demonstrations using a model flume, worked examples of the theory and real world examples to show how the theory relates to real flows. Footage of the 'real world example' is shot at the Nant Gwerno...
Introduction to Hydraulics Lesson Series
Просмотров 7643 года назад
This video gives a brief introduction to this series of lessons on Hydraulics. The video features the Nant Gwernol Ravine in Wales as an example of flowing water in the natural world.
Rapidly Varying Flow Part 4: Super-critical flow over a small obstruction
Просмотров 1,1 тыс.4 года назад
Example sowing the water surface profile in super-critical flow over a small obstruction.
Rapidly Varying Flow Part 3: Flow over a large weir
Просмотров 1,7 тыс.4 года назад
Example showing the water surface profile over a large weir set so the depth over the weir is the critical flow depth. In this example, the upstream flow depth has to increase to maintain minimum specific energy.
Rapidly Varying Flow Part 2: Flow over a medium sized weir
Просмотров 1,5 тыс.4 года назад
Rapidly Varying Flow Part 2: Flow over a medium sized weir
Rapidly Varying Flow Part 1: Sub-critical flow over a small obstruction
Просмотров 2,7 тыс.4 года назад
Rapidly Varying Flow Part 1: Sub-critical flow over a small obstruction
Calculating specific energy, critical flow depth, critical velocity and minimum specific energy
Просмотров 9 тыс.4 года назад
Calculating specific energy, critical flow depth, critical velocity and minimum specific energy
Plotting the depth-energy relationship for an open channel
Просмотров 2,7 тыс.4 года назад
Plotting the depth-energy relationship for an open channel
Manning’s equation to calculate discharge for a compound open channel
Просмотров 13 тыс.4 года назад
Manning’s equation to calculate discharge for a compound open channel
Manning’s equation to calculate the flow depth at a given discharge for a trapezoidal open channel
Просмотров 73 тыс.4 года назад
Manning’s equation to calculate the flow depth at a given discharge for a trapezoidal open channel
Manning’s equation to calculate velocity and discharge for a trapezoidal open channel
Просмотров 26 тыс.4 года назад
Manning’s equation to calculate velocity and discharge for a trapezoidal open channel
Manning’s equation to calculate the flow depth at a given discharge for a rectangular open channel
Просмотров 41 тыс.4 года назад
Manning’s equation to calculate the flow depth at a given discharge for a rectangular open channel
Manning’s equation to calculate velocity and discharge for a rectangular open channel
Просмотров 23 тыс.4 года назад
Manning’s equation to calculate velocity and discharge for a rectangular open channel
Uniform flow in an open channel
Просмотров 11 тыс.4 года назад
Uniform flow in an open channel
Calculating the power a turbine can generate on a hydroelectric scheme using Bernoulli’s equation
Просмотров 27 тыс.4 года назад
Calculating the power a turbine can generate on a hydroelectric scheme using Bernoulli’s equation
Designing a pumped reservoir/pipe system using Bernoulli’s equation
Просмотров 5 тыс.4 года назад
Designing a pumped reservoir/pipe system using Bernoulli’s equation
How to draw total energy line including continuous and local losses
Просмотров 7 тыс.4 года назад
How to draw total energy line including continuous and local losses
Calculating pressure in a pipe using Bernoulli's equation accounting for losses
Просмотров 13 тыс.4 года назад
Calculating pressure in a pipe using Bernoulli's equation accounting for losses
Calculating velocity of water in a pipe using Bernoulli's equation accounting for losses
Просмотров 29 тыс.4 года назад
Calculating velocity of water in a pipe using Bernoulli's equation accounting for losses

Комментарии

  • @kilobyte7814
    @kilobyte7814 2 дня назад

    Pls which textbook do you use for this

  • @you2tooyou2too
    @you2tooyou2too 2 дня назад

    This is a very limited (only one) example of the many ways that siphons can be/are used: partial/inverted/self-starting/capillary/bubbling/barometer/... PS: 'vacuum' is nearly possible above about 32' (a function of barometric/atmospheric pressure), near which the water near the apex will be boiling and the column will collapse.

  • @Jacquemini
    @Jacquemini 27 дней назад

    I got drunk asf and had to know this thanks for the video

  • @mr.curious1537
    @mr.curious1537 Месяц назад

    Actually Cohesive force also comes into action, as this air pressure theory is already debunked.

  • @josephpostma1787
    @josephpostma1787 Месяц назад

    What happens when the lengths of pipe boths before and after the bend vary?

  • @deepakagrahari997
    @deepakagrahari997 Месяц назад

    just amazing

  • @hamster-wh3ws
    @hamster-wh3ws Месяц назад

    Fab explanation, thanks :)

  • @phyarth8082
    @phyarth8082 Месяц назад

    Make this experiment with very fine particle inkjet printer or in fair of science find dye that is exactly in size or water molecule and is not transparent, yes such particle don't exist but that is point of scientist Brownian motion 10^14 hz collisions observed pollen particles of flowers jiggles 1000 smaller paint (dye) particles of potassium permanganate jiggles faster mixing of layers is much faster, no stratification of layers of laminar flow exist. 1:40 Your camera showing only 1/3 length of total pipe but even here you see that already intensity of dye are mixing, no even flow layers stratification. Not forget fact that water molecules compare to dye particles are 10000 times smaller, inject printer dye have smallest particle compare to water 1000 times bigger than individual water molecule. Take very long pipe and use see than no laminar flow exist. What you can see that Brownian mixing follows sinusoidal pattern Kármán vortex street. Of course which is behaviors of Brownian motion of mixing not flow regime of laminar or turbulent. Reject Brownian motion of molecules is rejecting all atomist model of matter, according to Reynolds flow is perfect layers of continuous flow that sometimes moves in vortices and eddies if flow is high (turbulent). And we stuck with this interpretation to this day.

  • @phyarth8082
    @phyarth8082 Месяц назад

    First for laminar flow which is parabolic continuity rule of flow rate cannot be applied in parabolic laminar flow maximum velocity is in center and zero at surface of channel. That is first indicator laminar and turbulent is invalid definition together with Re number. Second perform experiment in transparent tube with potassium permanganate which dissolves in water and with inject printer ink which very fine particles, but still are 100 times bigger than water molecules but you see that at Re<2000 paint mixes perfectly because of Brownian motion in liquid 10^14 Hz collision rate of molecules no such thing as laminar flow. To solve velocity loss deltaw need initial maximum flow w0 and geometrical parameters of channel (pipe) (L, d, epsilon). reason why Regula heat exchangers is 30% less efficient and uses 2 times more metal is because Reynolds and Prandtl, Nusselt numbers who are nonsense, why exploit inanimate devices if workers can work for free and exploit humans is better choice.

  • @SteveRogersOutdoors
    @SteveRogersOutdoors 2 месяца назад

    What are the dimensions of your flume? And that is 10mm acrylic? Correct.

  • @triparadox.c
    @triparadox.c 2 месяца назад

    I am here because the brief explanation of "how a bore evacuator works" just doesn't cut it for me.

  • @kakashi-yu7ok
    @kakashi-yu7ok 2 месяца назад

    how do we open the fuel tank of car with out vehicle key or without destroying the opening?

  • @jasonvarner5726
    @jasonvarner5726 3 месяца назад

    Great video, I'm building a financial model template for a hydro power dam and this was the first piece of content on the entire internet that made sense. I was able to use the calcs and it makes sense! Thanks.

  • @adesokantitilope3152
    @adesokantitilope3152 3 месяца назад

    Nice one Practically,is 'n' and 's' will be given If not,what are conditions or code to get those values if not given Or are they constant values

  • @ChanmaluethLual-yh5kr
    @ChanmaluethLual-yh5kr 3 месяца назад

    Past three immediately when I went to you-tube I understand everything ❤ so thank

  • @gatdetriekthian-py8nv
    @gatdetriekthian-py8nv 3 месяца назад

    Can tell you me more about manometer

  • @gatdetriekthian-py8nv
    @gatdetriekthian-py8nv 3 месяца назад

    Thanks you for your explanation sir

  • @Thejoystickjoker
    @Thejoystickjoker 3 месяца назад

    Explain everything throughly sir as i cant understand... Plz give a reason for everything u write and give a good reason.. Also this part 4:05 remake da video 4:28 here too pi... Unable to understand... Understood very little😢😢😢😢😢 4:53

    • @Trenbow
      @Trenbow 3 месяца назад

      THANK GOD IM NOT ALONE!!!!! He spends the first 5 minutes explaining the formula P= F1/A1 etc. Then at 5:01 (solving the Ex) He gave NO prior explanation of formula he used?????100/pi(0.1/2) Then proceeds not show how he got the answer 12.732... Where did he pull this random formula from with no context? are we supposed to know 100/pi? This is a 6 year old video so I doubt he will reply.. But you're not alone. I've been studying for the ASVAB and this Hydraulic press themed problem is giving me so much shit in the Mechanical Comp Section. Good luck mate hope you well!

  • @andycrawford9245
    @andycrawford9245 3 месяца назад

    0.00255m2 (at 9.49mins) is 0.00255 square metres. IT IS NOT, AS YOU SAY 0.00255 METRES SQUARED! GRRRRRR.....

  • @andycrawford9245
    @andycrawford9245 3 месяца назад

    You say metres cubed when you mean cubic metres! 8m3, for instance, is 8 cubic metres. 8 metres cubed is 8x8x8 which is 512 cubic metres - bit of a difference!!

  • @lady0awa
    @lady0awa 3 месяца назад

    Saving my neck the day before the exam. Very straightforward and clear. Bless you

  • @jamstawildman
    @jamstawildman 3 месяца назад

    Nice explanation! One very minor point: the letter h is pronounced aitch- it doesn’t actually have an h at the start of itself.

    • @nahom3427
      @nahom3427 2 месяца назад

      Wow!! What a useful comment, appreciate it mate!

    • @kakashi-yu7ok
      @kakashi-yu7ok 2 месяца назад

      no shit sherlock

  • @bma6469
    @bma6469 3 месяца назад

    My guy never disappointed when come to his fields of expertise. Thank you once again and Keep it up, I'm the biggest consumer of your materials.

  • @heathavpatel4033
    @heathavpatel4033 4 месяца назад

    Thanks ❤

  • @clemasters1
    @clemasters1 4 месяца назад

    The best fluid mechanics videos I’ve ever seen and I’ve seen a lot haha.

  • @timsweeney1960
    @timsweeney1960 4 месяца назад

    excellent video! life saver

  • @abdulalhaddadi8254
    @abdulalhaddadi8254 4 месяца назад

    Thanks helpfull

  • @bma6469
    @bma6469 4 месяца назад

    Another fantastic example. Love it.

  • @bma6469
    @bma6469 4 месяца назад

    I don't khow well I can appreciate the works you put in delivering astonishing concepts behind pump'head. A topic that was vaguely covered and hard to grasped during my 2nd year at University. Once, I greatly appreciated your input and dedication to the subject itself.

  • @RickyKamali
    @RickyKamali 4 месяца назад

    Dude thanks but I'm confused of the 2 you divided in area.

    • @rat_king1236
      @rat_king1236 3 месяца назад

      the equation for area requires radius which is the diameter/2

  • @NoxYaSoxOff
    @NoxYaSoxOff 4 месяца назад

    Remember democrats were historically the most racist & notably supported the Klans. They’re also the ones who call everyone against them fascist and justify any wrong doing towards said person, ironically.

  • @NoNAME-tq8mm
    @NoNAME-tq8mm 4 месяца назад

    👍nice

  • @metallicsoldat
    @metallicsoldat 5 месяцев назад

    I was wondering about what is the pressure at end B based on a requirement that the flow velocity through the pipe is 1m/s and flow rate is 100l/s. Say there is no requirement for delivery pressure at B, length of pipe is L metres, B is higher than A in height. By using bernoulli's theorem, pressure/head required to pump water from A to be B will be = Head loss due to friction + Potential head due to height difference between A and B. Does this mean that water pressure at point B will be zero? appreciate an answer. thank you!

  • @symtex36
    @symtex36 5 месяцев назад

    Math makes me feel dumb.

  • @shamelsinha8528
    @shamelsinha8528 5 месяцев назад

    Thanks for this video! I just wanted to clarify something. I tried applying the formula where you simply do 1/3 or 2/3 times the length of the gate to find the location of the equivilent point load of the triangular load from the water but it is not giving me 2.643m like you got using L'=I/AL + L... Like 0.75/3 is not equal to 3-2.643 if that makes sense. I realize this is because the formula I used doesn't account for the fact that there is water above the height of the gate and the distance between the height of the water and centroid of the gate is important but is there a way to use my method to solve this problem (i.e., maybe doing a weighted average of the location of the point load based on the height of water and the location of the point load based on the height of the gate)?

  • @raaghenuur3228
    @raaghenuur3228 5 месяцев назад

    Thanks alot very beneficial explanation 🙏it helps !

  • @JesusAmador-lr2pc
    @JesusAmador-lr2pc 5 месяцев назад

    If the pipe was not open to the environment, say it was a closed pipe, would we still be able to apply Bernoulli's equation to solve for pressure at Point 2. With point 1 still being at the top of the reservoir and a given flowrate

  • @alfredtovar6451
    @alfredtovar6451 5 месяцев назад

    so tedious, so stupid, waste of time

  • @tomwinkler294
    @tomwinkler294 5 месяцев назад

    Isn’t the pressure at the bottom of the tank much higher than the pressure at the top of the tank? I would assume the pressure would not depend on the hight of the tank but rather just the hight until where the tube is inside the tank

  • @HashemAljifri515
    @HashemAljifri515 5 месяцев назад

    I didn't understand the total force is the pressure time the perpendicular area which is 10.6*1...sin45 nahnah

  • @jamalfuzail4369
    @jamalfuzail4369 6 месяцев назад

    Say flow (Q) knows is 100 lit/sec.

  • @jamalfuzail4369
    @jamalfuzail4369 6 месяцев назад

    If flow (Q) is given or known what is the formula to calculate cross sectional area for a concrete channel. Kindly answer. Thank you.

  • @dorsan8491
    @dorsan8491 6 месяцев назад

    really helpful

  • @magretholatunbosun7706
    @magretholatunbosun7706 6 месяцев назад

    Thank you for your simplified explanation. I have a question: How did you calculate the volume for the tank under your flume based on what is coming in (flume outlet) and what goes out?

    • @fluidsexplained1901
      @fluidsexplained1901 6 месяцев назад

      Thanks for the question. Because the flow is steady, the flow in and out doesn’t make a big difference to the volume needed in the sump. I simply calculate the volume of water needed in the flume at max depth setting (based on the stop-blacks) and made sure the tank was large enough to hold this volume plus sufficient extra to ensure the pump was submerged when the flume was at maximum flow-depth. Hope that makes sense?

  • @user-im3yj9nb8z
    @user-im3yj9nb8z 6 месяцев назад

    0.044 what is this i mean is this answer in bars or in which unit? or if the answer is in meters then kindly can you clear that what is 0.044 ?

  • @brianty6676
    @brianty6676 7 месяцев назад

    Thanks mate. Great video.

  • @koltinhachey2554
    @koltinhachey2554 7 месяцев назад

    Isn't N/m square Pascals

  • @aazad3760
    @aazad3760 7 месяцев назад

    ❤❤❤

  • @ahmedmusa3994
    @ahmedmusa3994 7 месяцев назад

    Im happy to be confident after your video clips lectures

  • @ahmedmusa3994
    @ahmedmusa3994 7 месяцев назад

    Thanks help full person