spent whole day reading different pdf..but did not understand..watched this 24 minute video and everything is clear...Thanks alot for this great effort:)
You have to use the integrating factor method. I don't have a video on it yet, but if you type "integrating factor method for second-order differential equations" into RUclips, I'm sure you'll find one! :)
Very good and clear, potentially a little slow for those that understand most of the method (for example homog eqns) but are stuck at solving with the RHS (the non homog part).
hey thx for doing this ...was a big help - i watched the video befor and solve this one by myself ...so i think this makes you a very good teacher or lecturer ^^
Cheers! got an exam on this tomorrow. Much easier to understand! However i prefer to leave Yp in the form of Ae^x. Didn't get confused by it and found the calculations easier. :) keep up the good stuff
In this particular example, you can't leave it as Ae^x, even if you want to! :) If you do, the solution won't work out correctly. Good luck on your exam tomorrow!! :D
The answer is supposed to be e^-x ( 8x^2 + 4x + 1) if guess the particular solution to be xe^-x (Ax + B) from where does the constant term ( 1 ) shown in the answer come from?
I keep using Variation of Parameters instead of Undetermined coefficients (In step 2) and I always get (-1/15) e^(2x) + (2/5)*Xe^x. You got (2/5)*Xe^x. So why isn't it working for me? Is there some situations in which I cannot use Variation of Parameters?
How I wish you have an example for case #2 which has the same roots. Or can can used the 2e^x to show an example of non-homogeneous BVP with the same roots? What will happen?
first of all i would like to thank you very much for teaching this stuff madam.i want you to tell me the answers to these problems i got in my exam. 1. y’’- λ2y =sin2x is the differential equation .What is the solution? 2. Find the length of the arc of the curve y = │x-1│+│x-2│ from x=1 to x=3 thank you very much once again
In reference to the above example, what if in my particular solution i have something like Ae^-3, like i dont have a power on e that leds to any cancellation of any terms in the general solution, can i still add an x so that its further distinct, like Axe^-3? or its just enough that the powers are distinct so , dont need to make it further unique?
+Male Hakim If the exponents don't match exactly, then they are already distinct. Only when the exponents match exactly do you have to add in an extra "x" to take care of the overlap. That being said, Ae^-3 is a constant, so if you have any other terms that are just a constant, then you have an overlap issue there.
hey u showed another method to find the particular solution in which Yp=Y2integY1/C2w(x,y)+integY2C1/w(x,y) something was involved . i cant find that video please lead me to that video
My main problem is getting the particular solution. Any hints on that? for example i failed to figure out how a particular solution for the following equation looks like. y'' + 4y' + 4y = 25sinx
Hi. I've looked for a video on your channel about solving First/Second ODE with trigonometric coefficients on the left hand side of the equation. Trigonometric or anything other than real coefficients. Do you have some kind of a video? Thnks a lat!
It depends. For 2nd order, it depends on whether you are in Type I (b^2-4ac of your compatibility equation is greater than zero), Type II(b^2-4ac is equal to zero), or Type III (b^2-4ac is less than zero).
Hi, your videos are really good! I am trying to solve a similar problem but with multiples of (1/x) multiplying the y' and the y term. Any ideas? Thank you
A great video, you're a saint, but we're in differential calculus we don't need details on how to take derivatives. Just a word of advice, thanks again!
your lectures have been very illuminating Thanks so much. Please do you have tutorials on heat and wave equations like Solve the equation XUxx − 4Uxt = 0 by means of the coordinate transformation ξ = t + 4 ln x, τ = t !
When you said *So that's it* at the end, this is one of the long and abit confusing problems so it's not that simple :p But still, I think I got the hang of it so thank you ^^
Am really learning a lot from this channel. Your explanations are far much better than my bitch ass calc turor! However, i got a question. The equation u wrote on the top right works when the characteristic equation, in this case, r^2 + 3r + 4, yields different roots. Is there a different equation one uses if the roots yielded were the same or imaginary? coz thats always the expected outcome of any quadratic equation
+Male Hakim Yep, exactly. When the roots are different, you need videos about "distinct real roots", when the roots are the same, you need videos about "equal real roots", and when the roots are imaginary, you need to look for videos about "complex conjugate roots". Hope that helps!
Just a bit of advice: People studying maths at this level generally don't need you to meticulously explain every step of the product rule. It is quite a basic process that people watching this video should be able to do without even thinking about it.
Thank YOU so much for the comment! It makes me happy. :)
spent whole day reading different pdf..but did not understand..watched this 24 minute video and everything is clear...Thanks alot for this great effort:)
YES, that's the best compliment you could give me!! I'm so glad it helped!! :D
You have to use the integrating factor method. I don't have a video on it yet, but if you type "integrating factor method for second-order differential equations" into RUclips, I'm sure you'll find one! :)
SO happy you are not my professor. I can not focus, your voice is amazing :D BTW, the video is great
try a particular solution of y_p=A, instead of y_p=Axe^x. i haven't worked that out, but it's a good first guess! :)
nice job!
you are the best,keep it up
for me just tone of your voice makes me watch all your math videos
Very good and clear, potentially a little slow for those that understand most of the method (for example homog eqns) but are stuck at solving with the RHS (the non homog part).
I was just looking for solving these problems with initial condition! Nice Work!
hey thx for doing this ...was a big help - i watched the video befor and solve this one by myself ...so i think this makes you a very good teacher or lecturer ^^
Reallly helped…. Got a test in 4 hours👍🏼
Thank you very much. You answered all my questions. Very clear and nice explanation and hand writing. Thanks again!
Thank you so much ; indeed it works way more when using the initial conditions on the general equation and not on the homogeneous equation only...
I'm just happy I can help. :)
@bmcavalcante It's just a blackboard image I am writing on, and then recording with screenflow. :)
thank you for this video. i actually understand the concept now :)
very helpful, Keep helping us the student please. Your help is highly appricated.
Thanks
you're welcome!! i'm so glad it helped!! :D
Thank you very much.
You have done a great job.
I love the way,you explain,everything details.
That's awesome!! Thank you for letting me know; you made my day!! :D
Cheers! got an exam on this tomorrow. Much easier to understand! However i prefer to leave Yp in the form of Ae^x. Didn't get confused by it and found the calculations easier. :) keep up the good stuff
In this particular example, you can't leave it as Ae^x, even if you want to! :) If you do, the solution won't work out correctly. Good luck on your exam tomorrow!! :D
@bijoy183 Thanks for the comment. :)
Glad I could help!
Thank you! I will definitely keep making videos! :)
Thank you so much for this video, you are a true saviour.👌👌👌👌
Hope you make more videos until i finish my math major! Your a great instructor
I'm still confusing about the transform if the r(x)=k.e^x
For example, r(x)=3e^x, what i've learned the yp=Ae^x
The most in depth and helpful videos on this I've found. Thanks a lot!!
Thank you so much!
I love this kind of math problems. I've been watching these videos for hours.
Great video. Thank you for the help.
I have my Calculus and Linear Algebra final this week.
All the best, you'll do great
DID YOU PASS?!?!??!!!
The answer is supposed to be e^-x ( 8x^2 + 4x + 1)
if guess the particular solution to be xe^-x (Ax + B) from where does the constant term ( 1 ) shown in the answer come from?
I'm so glad you liked it!! :D
Can the right hand side be a constant instead of "a constant times e to the power of x"?
how will we find particular integral of y''+4y'+4y=16e^(-2t) ln(t)
You are priceless !!! Thank you for this amazingly helpful video !
Glad it could help! :)
Oh wow, GOOD LUCK with your finals!! :D
Cant figure out how to find the Yp at the non homogeneous equations. May anyone help me?
what the software is this?
Great work!!!
I keep using Variation of Parameters instead of Undetermined coefficients (In step 2) and I always get (-1/15) e^(2x) + (2/5)*Xe^x. You got (2/5)*Xe^x. So why isn't it working for me? Is there some situations in which I cannot use Variation of Parameters?
Thanks From New Zealand.
Very cool! Glad I could help!
very clear instructions in the intro. +∞
Better than my (Ivy League) professor. Honestly, thank you SO much.
Thank you sooo much!!! You're sooo talented girl! You rock! THANK YOU! xx
How I wish you have an example for case #2 which has the same roots. Or can can used the 2e^x to show an example of non-homogeneous BVP with the same roots? What will happen?
at 07:15 the reason of adding X is that you have 2 solutions for R that equal 1
first of all i would like to thank you very much for teaching this stuff madam.i want you to tell me the answers to these problems i got in my exam.
1. y’’- λ2y =sin2x is the differential equation .What is the solution?
2. Find the length of the arc of the curve y = │x-1│+│x-2│ from x=1 to x=3
thank you very much once again
Awww thanks! Hopefully that means I was helpful. :)
What is the particular solution if g(x) is cosx multiply sinx
In reference to the above example, what if in my particular solution i have something like Ae^-3, like i dont have a power on e that leds to any cancellation of any terms in the general solution, can i still add an x so that its further distinct, like Axe^-3? or its just enough that the powers are distinct so , dont need to make it further unique?
+Male Hakim If the exponents don't match exactly, then they are already distinct. Only when the exponents match exactly do you have to add in an extra "x" to take care of the overlap. That being said, Ae^-3 is a constant, so if you have any other terms that are just a constant, then you have an overlap issue there.
This was soooooo helpful! Thanks you sooo soooo much.
You're so welcome, T, I'm so glad it helped!! :D
hey u showed another method to find the particular solution in which Yp=Y2integY1/C2w(x,y)+integY2C1/w(x,y) something was involved . i cant find that video please lead me to that video
This one? Variation of Parameters for Differential Equations
Thanks!
Thanks a lot for these video.Your a great instructor
i think i can clear my exams now easily :) thanx alot :)
My main problem is getting the particular solution. Any hints on that? for example i failed to figure out how a particular solution for the following equation looks like. y'' + 4y' + 4y = 25sinx
+Male Hakim Whenever you have sin or cos like that, the particular solution is going to be Asin(x)+Bcos(x). I hope that helps!
Excellent video! But what happens if you have x's multiplied to your y primes? Like this: xy''+y'=x^3?
Hi. I've looked for a video on your channel about solving First/Second ODE with trigonometric coefficients on the left hand side of the equation. Trigonometric or anything other than real coefficients. Do you have some kind of a video? Thnks a lat!
+Male Hakim I'm not sure that I do! I will have to add more examples like that. :)
Amazing, just amazing, your detail of explanation i love it thank you for the video
Awww! Thank you so much!! :D
Thank you. You are a great teacher.
+Justin Perea Thank you so much!
where x is coming there on particular solution?
How would u find c1 and c2 for a homogeneous equation?
It depends. For 2nd order, it depends on whether you are in Type I (b^2-4ac of your compatibility equation is greater than zero), Type II(b^2-4ac is equal to zero), or Type III (b^2-4ac is less than zero).
Great Video!!
You have such neat handwriting. I'm captivated :)
krista how to solve y"=2y'-y=0.tnx
Is this same to cachy non homogeneous eg
What app are you using to write this, looks great!
Thanks, Ryan! It's called Sketchbook. :)
Hi, your videos are really good! I am trying to solve a similar problem but with multiples of (1/x) multiplying the y' and the y term. Any ideas? Thank you
Thank you maam for your help!
My pleasure, Rasel! 😊
Do you know what the answer is supposed to be? If so, can you tell me? :)
what would yp be if it was y''+ 2y' + y = 2e^tsint
i hope so! you're welcome!! :D
what is the software you are using its pretty cool i'm also into teaching so please let me know I'll be very thankfull to you :)
I explain here :) www.kristakingmath.com/my-videos
integralCALC Thank you !
Can u help me solve y'' - 2y' - 3y = 64 e^-x x
dont know where iam going wrong
A great video, you're a saint, but we're in differential calculus we don't need details on how to take derivatives. Just a word of advice, thanks again!
better she puts it in there in case someone does
It's more of a reminder, even students in Calc4 can slip up on some of the stuff from calc1 because of how long ago it was. It happens!
Brilliant! :D Thanks a lot :)
awesome!! :)
Thanks Teacher.
You're welcome!
12:12 All those e^x's looking for 'A'! Could have cancelled and saved some writing simply because (we know) e^x is never '0'
your lectures have been very illuminating Thanks so much. Please do you have tutorials on heat and wave equations like
Solve the equation XUxx − 4Uxt = 0 by means of the coordinate transformation ξ = t + 4 ln x, τ = t !
I'm so glad they've helped! 😀 I don't have heat and wave equations yet, but I'm hoping to add them in the future.
great video. cheers friend!
Thanks, Viv! :D
Amen to that!!
Your amazing!
Thank U So Much
You're welcome!
Not too fast, not too slow, just right. ;)
:D
When you said *So that's it* at the end, this is one of the long and abit confusing problems so it's not that simple :p
But still, I think I got the hang of it so thank you ^^
***** These problems are tough, but I'm glad this helped!
Am really learning a lot from this channel. Your explanations are far much better than my bitch ass calc turor! However, i got a question. The equation u wrote on the top right works when the characteristic equation, in this case, r^2 + 3r + 4, yields different roots. Is there a different equation one uses if the roots yielded were the same or imaginary? coz thats always the expected outcome of any quadratic equation
+Male Hakim Yep, exactly. When the roots are different, you need videos about "distinct real roots", when the roots are the same, you need videos about "equal real roots", and when the roots are imaginary, you need to look for videos about "complex conjugate roots". Hope that helps!
no joke! :)
Wow, now these problems don't seem hard anymore, just tedious!
He is really good, But the program she is using is way better.
thanks alot.
can you please change the background ?
its annoying simply :
patrickJMT have a competition here!
you saved my life cutie
When will your channel endorse a mascot or pet?
Just a bit of advice: People studying maths at this level generally don't need you to meticulously explain every step of the product rule. It is quite a basic process that people watching this video should be able to do without even thinking about it.
nah man, better to go in depth and help someone who didn't know rather than make videos just to suit you and your opinions
where x is coming there on particular solution?