Hi there, really great practical video, i have a question, is it that the speed of the motor say PMSM is actually determined somewhat passively, what do i mean is that the voltage of the rotating part of the motor is the Back EMF, which is proportional to the rotational speed, my understanding is no matter how much voltage you deliver to the motor system, a certain amount of the voltage will be taken by the resistive load on the circuit(assuming the load hasn't changed), and the rest will be balanced by the Back EMF, which in turn determines the rotational speed of the motor. Is my understanding correct? Love to hear your thoughts on that. Thanks in advance.
This is a complicated system to describe. Yes, the current to the motor resistance is a voltage. V=I*R so this IR drop only goes to heat the motor as I^2*R (watts) and in the winding resistance the Arms is the effective heating or energy lost in the form of heat doing no actual work at the output.
@@dinocrum Hi thanks for the reply. Apart from the resistance, another question i have is say when we are doing FOC control, we calculate the torque we need to apply we convert it to current, so that's my current in q axis, and without any field weakening we set current in d axis at 0, after the FOC transformation, we have our 3 phase voltage we need to inject, and at this voltage, the motor has certain speed. My question is: if i increase the voltage while maintaining the current in d axis = 0, in theory the torque will be increased, but since the load hasn't changed, can we say the increased voltage will mainly contribute to increasing the speed?
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Great content
A very good video thank you very much. This is a principle of understanding of something that is dying out due to digital crap technology.
3:46 - Starts talking about speeding up a motor
Don't run it too fast, you'll get valve float and it might throw a rod.
can please send these PDF's that you are using in this video ??
Hi there, really great practical video, i have a question, is it that the speed of the motor say PMSM is actually determined somewhat passively, what do i mean is that the voltage of the rotating part of the motor is the Back EMF, which is proportional to the rotational speed, my understanding is no matter how much voltage you deliver to the motor system, a certain amount of the voltage will be taken by the resistive load on the circuit(assuming the load hasn't changed), and the rest will be balanced by the Back EMF, which in turn determines the rotational speed of the motor.
Is my understanding correct? Love to hear your thoughts on that. Thanks in advance.
This is a complicated system to describe. Yes, the current to the motor resistance is a voltage. V=I*R so this IR drop only goes to heat the motor as I^2*R (watts) and in the winding resistance the Arms is the effective heating or energy lost in the form of heat doing no actual work at the output.
@@dinocrum Hi thanks for the reply. Apart from the resistance, another question i have is say when we are doing FOC control, we calculate the torque we need to apply we convert it to current, so that's my current in q axis, and without any field weakening we set current in d axis at 0, after the FOC transformation, we have our 3 phase voltage we need to inject, and at this voltage, the motor has certain speed. My question is: if i increase the voltage while maintaining the current in d axis = 0, in theory the torque will be increased, but since the load hasn't changed, can we say the increased voltage will mainly contribute to increasing the speed?
@@willyturing1803 send email to dcrumlish at copleycontrols dot com thanks. Dean
what's the software you were using for motor control ?
Copley CME software. Send me email please dcrumlish@copleycontrols.com
Does anyone know where I can get a small field weakening controller?
Send me email at dcrumlish@copleycontrols.com and I will help you get a drive.