How to find logarithm without log tables|Tricks and tips series for JEE|CBSE| NEET|CET

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How to find anti-logarithm without log tables?
• 🔥 Anti-log (0.05) ? Ho...
Just memorize log2=0.3010 log3=0.4771 log5=0.699 and log7=0.8451 only.
log(6.1) = log (6+0.1) = log6 + 0.4*0.1/6 = log2 + log3 + 0.0067 = 0.3010+0.4771+0.0067 = 0.7848
what if log(137)=log(140-3)=log2+log7+log10-0.4*3/140 = 0.3010+0.8451+1-0.0086= 2.1375 (approx)
remember: delta x(increment/decrement) should be much more smaller than 'x'
• 💥 Find Log 2300 withou...
how to find perfect log. must watch.
• 💎 How to find Logarith...
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Example 2:
log (0.6) = log (6/10) = log6 - log 10 = log (2*3) - 1 = log2 +log3 -1
=0.3010 +0.4771 -1 = -0.2219
Example 3:
log(737) as log (736) = log (32*23) =log (2^5) +log 23
=5log2 +log (24-1) = 5*0.3010+ log24 - 0.4* 1/24
= 1.505 + log(2*2*2*3)-0.016 6=1.505 +3log2 + log 3 + 0.4771 -0.016; now 1.489 +3*0.3010 + 0.4771 -0.016=2.88 approx
Example 4:
log23.32 = log(2.332*10)= log (2+0.332 ) + 1 =
log 2 + 0.4 *0.332/2 + 1 = 0.3010 + 0.066 +1 =1.367approx
• 💥 Find Log 2300 withou...
note: take approximate nearest number and apply logarithm
example(i) log (49.78999 ) as log(50); (b) log(2.3789) as log(24/10)
(c) log (0.004568) as log(45/10000) (apply log(3) +log3 +log5 -
log 10000 (d) log (23779) as log (24000) (apply log 24 + log 1000
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[@Worldofchemistryclass11and12]

Just memorize log2=0.3010 log3=0.4771 log5=0.699 log7=0.8451
Example 1:
log(6.1) = log (6+0.1) = log6 + 0.4*0.1/6 = log2 + log3 + 0.0067 = 0.3010+0.4771+0.0067 = 0.7848
what if log(137)=log(140-3)=log2+log7+log10-0.4*3/140 = 0.3010+0.8451+1-0.0086= 2.1375 (approx)
Example 2:
log (0.6) = log (6/10) = log6 - log 10 = log (2*3) - 1 = log2 +log3 -1
=0.3010 +0.4771 -1 = -0.2219
Example 3:
log(737) as log (736) = log (32*23) =log (2^5) +log 23
=5log2 +log (24-1) = 5*0.3010+ log24 - 0.4* 1/24
= 1.505 + log(2*2*2*3)-0.016 6=1.505 +3log2 + log 3 + 0.4771 -0.016; now 1.489 +3*0.3010 + 0.4771 -0.016=2.88 approx
Example 4:
log23.32 = log(2.332*10)= log (2+0.332 ) + 1 =
log 2 + 0.4 *0.332/2) + 1 = 0.3010 + 0.066 +1 =1.367approx
ruclips.net/video/eKdOPrWobhw/видео.html
note: take approximate nearest number and apply logarithm
example(i) log (49.78999 ) as log(50); (b) log(2.3789) as log(24/10)
(c) log (0.004568) as log(45/10000) (apply log(3) +log3 +log5 -
log 10000 (d) log (23779) as log (24000) (apply log 24 + log 1000

[@tamilzone994]

Madam we have come over here to remember those values not memorise them . Make us understand not be able to mug up values.

[@eergadhinlasrinivas2708]

Okkk

[@sanjanadongre4610]

Finally!! after watching many videos ,I found this method to be the most convenient one! thank you so much mam .It is very helpful🙏🏻

[@tusharwaghmare4237]

thank you mam it will be really helpful for us to solve numericals fast during our exams

[@anushka71314]

That's Awesome trick ma'am ❤️🔥 You just make it easier 👍 Thank you so much ma'am

[@prakashdeka1834]

Thank you so much ma'am❤ you really made me understand log in just 8 mins. Thank you

[@abhisheksuman7341]

Thank you mam I was really helpful while solving numericals.... U made this look so easy or else I had to waste lot of time in solving sums but now it's so easy to get the accurate answers THANK YOU👍

[@gamingstation4801]

This procedure is really helpful in solving equilibrium and chemical kinetics so much and really easy... Really comes in handy for a competitive exam

[@Worldofchemistryclass11and12]

Happy learning

[@RaghaviSRaj]

Omg....life saving tips..... thank you so much....!

[@mauryaartistshivani6843]

Thank you ma'am. It is very helpful 🙏🙏🙏🙏

[@hornet6036]

Thanks Ma'am It Helped a lot 😊🙏🏻❤️

[@pranavmagdum5495]

Thank you mam for such amazing video👍🏻👍🏻👍🏻👌👌👌

[@dhanamohammed5707]

U are great ma'am. Thank you for your help. Upload more!!!

[@anjolasworld]

Been looking for this for a while now.....Thanks

[@jaatbhai5101]

Mam you are awesome. You study very well. Thanks mam. May God bless you

[@darshankeskar8471]

Thank you mam
It is very impotant in hsc exam
Thaks again and again!!!

[@aaravmishra8984]

I had been searching for this videos since last month...... 😍😍😋thanks mam......

[@jessica.rachna]

You sound like you have cold 😦..still you are teaching so well ..thank you soo much mam for your help♥️

[@zebaagulzebaagul2429]

Wow maa'm kitna accha trick hai
Thanku so much

[@yashgaur3763]

amazing mam thanks it helps us a lot during exam..

[@rajanivaishnav7473]

Thank you maam your trick really helped me ☺️🤗

[@minusingh6915]

Thank you so much mam .
I really understand the concept

[@ujjawalraj6096]

Nice mam it was very helpful
Continue this tricks series

[@poojakhanapure9609]

thanks mam such a easier trick to find the log without log table . thanks for giving us so much good video.thanks

[@ditea3804]

Ty you so much madam,after seeing this video ,solved all my problem

[@takshitharao8083]

Thankyousomuchh ma’am 😍

[@dark3421]

Log 5 can be derived using log a/b= log a- logb,log 10/2=log10-log2 =0.7

[@vishakhushi5603]

Thanku mam...🤗....it is very helpful...✨❣️

[@vinayakvd6359]

Superb explanation

[@bhavanisinghrajput7710]

awesome ma'am

[@nareinparameswaran3042]

Thank you. Maaamm..❤❤

[@vinayvini3585]

Superb madam thnsks for u r tricks..

[@navyaprem5525]

Thanks a lot Ma'am... It helped a lot.

[@chandrashekhargupta2138]

Thanks your very much mame god bless you and help to make your future brighter. Your video lectures are very much helpful for me

[@Worldofchemistryclass11and12]

Thank you so much for your wishes..All the best..

[@nikitapanwar14]

Thank you so much ❤️😘 Ma'am ❣️ after watching so many videos 😊 finally I found your video easy 😁 and simple ❤️🤗Vvvvvvveeeeeerrrrrryyyyyyy helpful 😊

[@Worldofchemistryclass11and12]

Thank you Nikita ..Happy learning

[@bhavanadatar7651]

Helped me a lot. You are great mam

[@CrystalMethSantaClaus]

Thank you so much
God bless you

[@begood2534]

Superb ma'am thanks a lot

[@geethamurugan5779]

Thank u so much 😀😀😀reallly great

[@snayakumari2071]

Thank u so much mam it's really help in medical test

[@ICTHub005]

Brilliant

[@arhamsaifi2469]

Perfect explanation, now no space for more confusion .... Thnxx u so much .. keep.it up ma'am

[@Worldofchemistryclass11and12]

Thank you so much arham

[@anshikhajaiswara8733]

Thank you ma'am 😊❤️👍

[@rameshgennur2999]

thank you very much mam 💖💖💖💖👌🏻👌🏻👌🏻❤️❤️

[@aayushsharma5134]

ma'am prime no.s for example 13 ka log kaise nikale?

[@adstudychannel8493]

Really mam I am grateful to you

[@Worldofchemistryclass11and12]

Happy learning

[@swethaiyer8990]

THANK YOU MAM

[@ruckmanichakravarti.1136]

Thank u mam it is easy to apply in exam

[@veenaramasamy4254]

Thank you so much mam

[@gayatritandale9465]

Thanks mam it is very helpful.......... 👍👍

[@rainbowvlogs8778]

Thank you ❤

[@ruckmanichakravarti.1136]

Good use

[@charukahathurusinghe4656]

Thank you madam 🙏

[@prathvikulkarni9727]

Thank you mam.. ❤❤

[@gitanjalirajput5119]

Thanks a lot mam 😊😊😊😊😊

[@sangeethacdm5667]

Tq it's very use to me tq do much mam

[@praneshrajkumar7074]

thank you mam it was reallhy helpful

[@rithinreddy7023]

Madam in vedio u turned page next log6 means u written log2+log3 then it become log5 Na madam

[@Worldofchemistryclass11and12]

WATCH MY LOG VIDEOS . log(x) + log(y) = log(xy) ruclips.net/p/PL9nSaEI0m9rcmRrloEOMeH-0EslIyoYs0

[@user-uu5ey2je8c]

💯👍🏼 You are the Best teacher mam ur teaching is exllent v very thanks for this video🙏✨️😇👌

[@Worldofchemistryclass11and12]

Thank you so much..Happy learning

[@lekshmyreghunathannaira4090]

Thank you

[@sravyarayala1784]

Thankuuu for your video

[@lakshita_1521]

Thankyou mam😌❤

[@TheblueTTK]

Thanks so much this was so helpful 😊😊😊😊

[@Worldofchemistryclass11and12]

Happy learning

[@greatcreations4830]

Mam! You are using mathematical identity log(a)+log(b)=log(ab), am I right mam?

[@gmssahouli8900]

Woah thanks

[@person17_ro]

Greatest Video of all time 🔥🔥🔥

[@mavwalker8991]

Yesssss

[@ishantsrivastava1399]

Great mam ♥

[@adityailame1193]

Thank-you mam

[@mothereditz...1571]

Thnk u so much mam....

[@raghavmittal9844]

Thank you mam

[@jaswantsiinghania9050]

a BIG thanks mam .But what about logarithmic decimal values.I REQUEST you to make another video on them and also include anti logarithmic values in it because we can not cram whole log table. It would surely treat us in solving our numerical problems . Thank you MAM - one of your student who will be anxiously waiting for your next video.

[@Worldofchemistryclass11and12]

ruclips.net/p/PL9nSaEI0m9rcmRrloEOMeH-0EslIyoYs0

[@suratramehs7510]

Tq mam tq very much 🤩

[@rajbirkaurgill2553]

Thanku mam this is really helpful for me but I face a problem in finding the value of log of decimal no. Mam please also prepare video for that. That will be great help from Ur side please mam.....

[@Worldofchemistryclass11and12]

ruclips.net/video/MXwIDTH-l-g/видео.html

[@venkeyvenkat6211]

mam but for log 6 .. i thought at last u will add log 1 to it bez log( 1+2+3) makes log 6 ... is my understanding crt mam ???

[@Worldofchemistryclass11and12]

Log(2*3) is log 2 + log 3

[@neetians3025]

Awesome mam....❣️🙏

[@user-ls7bb9eh4l]

thnk uh soooo much mam!!!!

[@poojahiremath6795]

Mam there is doubt to me that is when Adding or Multiplying then you were adding in case of multiplying what would happing mam..

[@Worldofchemistryclass11and12]

Basics of logarithms you must know
Log (ab)= log a + log b ( with base 10 or e )

[@vaibhavbhatia1472]

Thank you mam it really helped

[@snehahrsneha3186]

Superb mam tq🙂

[@emykirubarani3213]

Helpful

[@kalpnasharma3307]

Nice ,thanku mam....

[@adogarmichael-co8co]

I am watching from Nigeria
And i found your teaching so helpful.
Thank you for this maam

[@Worldofchemistryclass11and12]

Thank you so much .. Happy learning

[@nikhilnani8570]

Thankyou mam

[@nargisnaharxb]

Thank you ma'am 😢❤

[@Worldofchemistryclass11and12]

Welcome and Happy learning

[@chittaluruankaiah3568]

Osm mam

[@devbhoomiuttrakhand3012]

TQ mam🙏🏼🙏🏼

[@nabanitaghosh3282]

Thankuy

[@kushkanswa7213]

mam then what do we do for log and antilog of decimals

[@Worldofchemistryclass11and12]

For log, convert the decimal number into non decimal number by multiplying and dividing with 10,100 etc.

[@alltech3185]

Is this for neet exam im a PCB student i dont have maths so is it compulsory to learn this?

[@Worldofchemistryclass11and12]

useful for numerical problems

[@mitashabhardwaj7496]

How u did log 6?? U just added log 2 and log 3...but 2 plus 3 is 5....how did u do that?

[@Worldofchemistryclass11and12]

log2 + log3; log(mn) = Log(m) + log(n)

[@GauravKumar-le3nk]

Thanku so much really it is very helpful to us 😘😘

[@Worldofchemistryclass11and12]

Welcome..Happy learning

[@quicktech7450]

Super

[@shivarawat1905]

Thanks

[@rengasami2231]

In log 85,can't I approximate it to log 86 and find answer? Why should I use log 84?

[@Worldofchemistryclass11and12]

you can do

[@jamilawaisijamilawaisi1156]

Mam pls help me find log 1.9, pls pls

[@renuka-ht2yg]

Tqsm mam u r grt 😍😀😁

[@narutosanime.seriesbestani3919]

But mam we can't find log of every type of numbers, like which are in 4 digit or in 5 digit and also the numbers which are in decimals

[@Worldofchemistryclass11and12]

eg 6 digit : log ( 240010) = approximately log (24 * 10^4) = log (24) + 4 = log(2*2*2) + log (3) +4 = 3*.3010 +0.4771 +4 =5.380

[@tiyasachatterjee3664]

Thank you ma'am. It is very helpful to NEET aspirants like me.

[@pareihanbasagapam6500]

Thnk you mam😭

[@telugumoviescenes7871]

Tq mam

[@kritisharma350]

Thanku ❤️ mam🥰