sir u r awsome and incredible....youtuber like you are the legend for next generation education...this type of video are the revolution in education system...thank you...
i was curious to know about this MATHEMATICAL DESCRIPTION OF SIGNAL WAVEFORM as no textbook (as far as i know ) has taught it exclusively .It is of great help in understanding the other part of signals and systems.GREAT JOB SIR
Veryyy nicee explanation sir ....it's awesome 👏👏 👏 . Your videos are the best I have ever seen...i have understood this concept by seeing your lectures only.pleaseee upload video by taking some complicated examples sir...I am still confusing ....
@@PoluBalaji the slope was from -2 to 0. Thus, you subtract the final slope with the initial slope which is 0 - (-2) = 2. That is why it is 8/4 which is 2.
@@Sharmine_ 2tu(t)-2(t-1)u(t-1)-2u(t-1) Expand the (t-1) by Multiplying... 2tu(t)-2tu(t-1) Last 2 terms are Cancelled. Hence We only Left with 2tu(t)-2tu(t-1).
Sir in this lecture when take the derivative of 2r(t) you write 2tu(t) and the next lecture 2r(t) = 2u(t) I have problem in this part if you could explain it thanks
Sir my question is that -What happened when the slop of ramp become 90 degree.As we know that tan90 is not defined. Please reply sir as soon as possible Thank you
hi I guess it is way too late, but the reason for that is because it is represented as "step" signal beceause there is a discontinuity, and therefore only the level is changing from 16 to 0.
Thank you sir for this clear and nice explanation :), I need to plot the following function: Hw(tau)=H[Cw(t-tau)-r],could you please help me to plot it?Thanks again :)
In the second Example, shouldn't it go down by -17u(t-4) ?? because, if we go down by just 16, then a unit step would begin at t=4, and that will make the value of the signal 1 from t>=4 ?? Please clear the doubt.
@neso academy u askss us to comment in comment section if we hve any doubt but ihve been seeing that you didn't replied to anyone.. and didn't clearer any doubts
please can anybody plot 2nd in matlab? clc close all hold on t=-100:0.01:100; y= t>=0; r=t.*y; r1=(t-4).*y; x2= t-4>=0; p=4*y+3*r+-3*r1-16*x2; plot(t,p,'black') axis ([-5,10,-10,20]) xlabel ('Time,t') ylabel ('Exp. rising signal,sinc(t)') hold on t = -1000:0.01:5000; plot(t.*0,t) hold on t = -1000:0.01:5000; plot(t,t.*0) didn't work
sir u r awsome and incredible....youtuber like you are the legend for next generation education...this type of video are the revolution in education system...thank you...
i was curious to know about this MATHEMATICAL DESCRIPTION OF SIGNAL WAVEFORM as no textbook (as far as i know
) has taught it exclusively .It is of great help in understanding the other part of signals and systems.GREAT JOB SIR
Only Your Video is correct, simplified & short on whole RUclips. I m very happy that now i can apply waveform synthesis 😇.
Ma sha Allah! Lots of prayers for you, respectable sir.
Just great. You don’t know what this means for me. All I can say is thank you, best of luck, and keep it up!✊🏾
I wonder why, at 4:00 we add 2r(t-4) but at 7:38 did not add +4u(t-0) (and also at 9:03 didn't add +1u(t-1) ) ?
I saw to many vid relATED TO RAMp prblm
But ur vid is cleared mY doubt.
Tq so much sir
Wow amazing great superb explained .Saw almost 50 videos but didn't get explaination like this
Hello to everyone in Neso Academy. Your team is great. I am very happy to known you. thanks God. God bless all of your team.
Thank you again. 🌹💙💙💙
Veryyy nicee explanation sir ....it's awesome 👏👏 👏 . Your videos are the best I have ever seen...i have understood this concept by seeing your lectures only.pleaseee upload video by taking some complicated examples sir...I am still confusing ....
at 3:34 , dont u think it should be 2r(t-4) because it is not turning at 0 but at 4?
Thank U so much Sir.... Thanks a lot.... I just can't explain how much I am grateful to u !! Thanks again ...
come teach at my university you worth every penny! good job sir
After long time finally I got the point bz of you sir,thanks alot sir
This is the clearest explanation ever. Thank you so much
Understood everything in this video...???I've doubts can u explain
@@PoluBalaji Yes. Why?
@@juanmarcuslopez3018 I've one doubt can u please explain.??
@@juanmarcuslopez3018 At 4:03 the line passing through x-axis then slope is equals to zero but @neso academy took slope as 8/4 can u explain..?????
@@PoluBalaji the slope was from -2 to 0. Thus, you subtract the final slope with the initial slope which is 0 - (-2) = 2. That is why it is 8/4 which is 2.
Sir, can you please explain the changing of ramp signal to U(t) I could not understand
Excellent work sir,thanks a lot...keep making lectures as you have been
Helped me a lot
Thx from Egypt 💞
Sir,
Please explain step at 10:01. i.e. How does 2tu(t)-2tu(t-1) was obtained from 2tu(t)-2(t-1)u(t-1)-2u(t-1)..?
By opening the bracket of "(t-1)" of second term.
I still don't get it. Can anyone explain it? thanks
@@Sharmine_
2tu(t)-2(t-1)u(t-1)-2u(t-1)
Expand the (t-1) by Multiplying...
2tu(t)-2tu(t-1)
Last 2 terms are Cancelled.
Hence We only Left with 2tu(t)-2tu(t-1).
@@VamsiKrishna-zv1tv Thank you!
ربي يحفظك ويسعدك يادكتور 💚🙏🏻
thank you thank you thank youu very much sir
finally I understand it !!
❤❤
the way of explanation is fantastic Sir...👏👏
You're a blessing 💥❤️
X(t) 3r(t) - 3r(t-4)- 16 U(t-4)
This is answer of problem 2 and topic is mathematical representation
Very nice explanation 👍👍
Amazing work Sir, thank you!
Great and simple representation
Thank you for your explanation,Sir.
Thank you very much ❤
Very well explained .. thank you
Nice content! Go on...
Best explanation ever sir😍
Please explain how to represent an exponential signal by this method?
Sir in this lecture when take the derivative of 2r(t) you write 2tu(t) and the next lecture 2r(t) = 2u(t) I have problem in this part if you could explain it thanks
Super awesome👏✊👍 sir truly ur fan
u r the best👍🏻👍🏻
thank you thank you.............................
Brilliant!
thank you for explaining
Will u plz make a vedio on introduction of micro processor
Sir, please explain how to write signal in terms of the gate signal.
Thank you
Thank you 😀
Excellent
Sir, can you explain what will be the equation if there is trigonometric function , for eg. Sine wave...
Sir my question is that -What happened when the slop of ramp become 90 degree.As we know that tan90 is not defined.
Please reply sir as soon as possible
Thank you
hi I guess it is way too late, but the reason for that is because it is represented as "step" signal beceause there is a discontinuity, and therefore only the level is changing from 16 to 0.
how to cross check the equation?.....by putting values of "t".......for que 1 at t=-1 it comes out 4....but how to know if that's correct or not?
Sir explain on how to obtain the mathematical representation
Thank you sir for this clear and nice explanation :), I need to plot the following function: Hw(tau)=H[Cw(t-tau)-r],could you please help me to plot it?Thanks again :)
In the second Example, shouldn't it go down by -17u(t-4) ?? because, if we go down by just 16, then a unit step would begin at t=4, and that will make the value of the signal 1 from t>=4 ?? Please clear the doubt.
nice work
is there a way to do this by using only the step function?
@neso academy u askss us to comment in comment section if we hve any doubt but ihve been seeing that you didn't replied to anyone.. and didn't clearer any doubts
How are you saying that this one is a unit signal and this one is a ramp....plz reply fast ?
Watch previous video of this topic 74 number
Sir is it true for gate exam we need to know all waveforms mathematical representation?
sir why do we have to settle for constant value?
Answer conversion of ramp to step signal is ok sir, but suppose step to ramp signal conversion how to done sir. .....
sir what is the difference between r and u ?
thanku Sir.
@neso acedemy how u take 8/4r (t-4)...???at t=4 slope is 0 right..???
This is the basics right line passing through x-axis has slope zero…..!!
Thanksva lot sir
please can anybody plot 2nd in matlab?
clc
close all
hold on
t=-100:0.01:100;
y= t>=0;
r=t.*y;
r1=(t-4).*y;
x2= t-4>=0;
p=4*y+3*r+-3*r1-16*x2;
plot(t,p,'black')
axis ([-5,10,-10,20])
xlabel ('Time,t')
ylabel ('Exp. rising signal,sinc(t)')
hold on
t = -1000:0.01:5000;
plot(t.*0,t)
hold on
t = -1000:0.01:5000;
plot(t,t.*0)
didn't work
thumps up!
Sir i didn't get the calculations at the end. Can someone explain
r(t) = t u(t) ; as u(t) = 1 for t>0 & r(t) = t for t>0 , so r(t) = t*1 = t * u(t)......
iam the first
Thanku so much sir
Thank u sir