Any energy change can be decomposed into contributions from heat and work. This fact is important enough that to be labeled the First Law of Thermodynamics.
Well, I would say ΔU = q + w, probably because I'm using a different sign convention than you are. But yes, the first law of thermodynamics always holds, including for heating liquids.
Yes, the sign of q will be positive when a liquid is heated, because energy is transfered into the system in the form of heat. (But q always shows up with a positive sign in the first law, ΔU = q + w.)
I wonder why the academic channels which explain concepts in depth go underrated on RUclips.
Probably for the same reason that novels sell more copies than textbooks. It takes much more work to follow a lecture than to watch a music video.
You can say that again...
He is one of the best
Dr Stuart is excellent instructor.
YOU EXPLANATION IS AMAMZING .
Thanks!
Sir if we heat an liquid and as a result volume increases.thus we can say that the ∆u=q-w.
Since +q is because of transfer of energy into the liquid.
-w is because of the expansion of liquid when heated.since w=-Pext . (∆v),vf is greater than vi as it is expansion process.so w =-p∆v
Is it correct sir?
Well, I would say ΔU = q + w, probably because I'm using a different sign convention than you are. But yes, the first law of thermodynamics always holds, including for heating liquids.
Yes, the sign of q will be positive when a liquid is heated, because energy is transfered into the system in the form of heat.
(But q always shows up with a positive sign in the first law, ΔU = q + w.)