Torque and Speed Relationships in Gears | Motor Driving Winch Through Geartrain

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  • Опубликовано: 30 мар 2018
  • LECTURE 06
    Here the relationships are derived for torque and speed between mating gears in terms of radius, diameter, circumference, and numbers of teeth. It is shown that there is a direct ratio between gear size and torque and a negative inverse relationship between gear size and torque. (The negative indicates that the rotational direction changes at each mesh.) The concept of pitch circles is presented as a way of modeling gear action as simple friction rollers. The idea is presented that gears must have the same pitch (number of teeth per unit of circumference or diameter) in order to properly mate. A problem is solved in which a known mass must be lifted at a specified speed by a specified spool diameter using a specified set of gears with specified numbers of teeth. The required torque, speed, and direction of rotation is determined for the motor that drives the geartrain. It is explained that the "lossless" assumption utilized in the example is a good starting point for understanding, but fails to account for torque loss that would happen due to friction in any real geartrain.
    ENGR 122 Playlist (Engineering Problem Solving III):
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    • ENGR 121: Engineering ...
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    This lecture segment was recorded on March 26, 2018. All retainable rights are claimed by Michael Swanbom.
    Please subscribe to my RUclips channel and follow me on Twitter: @TheBom_PE
    Thank you for your support!

Комментарии • 56

  • @abdelrahmanmohammed3561
    @abdelrahmanmohammed3561 3 года назад +2

    Absolutely brilliant. Clear, Simple and directly to the point. Thanks

    • @TheBomPE
      @TheBomPE  3 года назад

      Thanks for the positive feedback! I'm glad you liked it, and thanks for watching!

  • @GeorgeJMcConnell
    @GeorgeJMcConnell 3 года назад +2

    Yes, great instructional video. Can't wait to watch a few more.

    • @TheBomPE
      @TheBomPE  3 года назад

      I'm glad you liked it! Thanks for watching!

  • @Chelsea2009FC
    @Chelsea2009FC 3 года назад +2

    Your voice was very soothing throughout the lecture, good video!

  • @jerichoyang243
    @jerichoyang243 5 лет назад +3

    thanks for uploading this video. one of the best video about gears and speed and torque.

    • @TheBomPE
      @TheBomPE  5 лет назад

      I'm glad you found it useful! Thanks for watching!

  • @jaw9570
    @jaw9570 2 года назад +2

    A simple and clear way to explain, thank you.

    • @TheBomPE
      @TheBomPE  2 года назад

      Glad you liked it! Thanks for watching!

  • @atexnik
    @atexnik 3 года назад +7

    Thank you! I finally understood how small circle turns big circle with ease. It is all thanks to the fact, that they have equal opposite forces on the tangent at the point of contact. If we compare this to a Lever machine, then the small gear is effectively a "pusher" that applies force on a lever of distance r2 and its pivot point at the centre of the big gear.

    • @TheBomPE
      @TheBomPE  3 года назад +2

      I'm glad it helped! Thanks for watching!

  • @prasadakavoor773
    @prasadakavoor773 Год назад

    Loved it. Thanks for this!

  • @CharlieTechie
    @CharlieTechie 5 лет назад +6

    I was having problems with this subject until I saw your fantastic video. Simple and clear explanations. Thank you very much for posting on RUclips and I am surprised that you have such few likes compared to views. You deserve more likes; teachers such as you are had to find. I subscribed to your channel.
    A question: what software program are you using for your whiteboard screen? I really like it.

    • @TheBomPE
      @TheBomPE  5 лет назад +5

      I'm glad it helped! Thanks for the glowing review! My channel is still pretty young, and many of the views are probably students at the university where I teach, so they might not think to click like. Plus, there might not be that big of a slice of the general RUclips population that cares about this kind of thing. (Not enough cats in it.)
      Thanks for subscribing and helping to let others know about the channel. I use Microsoft OneNote to do the inking, and I use Camtasia to capture my screen. Thanks for watching, and I hope you'll check out my other videos too!

  • @ncroc
    @ncroc 4 года назад +1

    Very nice lecture.
    There is one thing that bothered me though. Can we set both the speed and the torque of the motor independently?
    There are those speed - torque curves which show that the amount of torque the motor will provide depends on the speed of the motor or does it? I've always thought once we determined the amount of torque required, we are stuck with whatever speed the motor will give us for that torque. Is that wrong?
    Are you trying to selecting a new motor that can provide the desired torque at the desired speed?

  • @arnaudzodehougan9624
    @arnaudzodehougan9624 3 года назад +1

    this video is fantastic. Which tool do you use to write on your tablet, thank a lot..

  • @mikoajkahl9451
    @mikoajkahl9451 3 года назад +1

    great video!

    • @TheBomPE
      @TheBomPE  3 года назад

      Thanks, I'm glad you liked it! Thanks for watching!

  • @skd5432
    @skd5432 Год назад +1

    wow....... a brilliant head start for any mechanical engineer..... 👍🏼

    • @TheBomPE
      @TheBomPE  Год назад

      I'm glad you liked it! Thanks for the positive review!

  • @zafaniamwando4634
    @zafaniamwando4634 3 года назад +3

    That was perfect especially your accent stay blessed bro

    • @TheBomPE
      @TheBomPE  3 года назад

      I am blessed, and appreciative of your support! Thanks for watching!

  • @BoxerDogs
    @BoxerDogs 3 года назад +1

    1. For a shaft with one gear on it, If you increase the torque applied to the shaft, would that cause the shaft to rotate faster? Why?
    2. If you make a shaft turn faster, would you need to apply more power or more torque?

  • @muhammedbakrkurt9428
    @muhammedbakrkurt9428 2 года назад

    Thank you Sir, for your good teaching. I just have a small question. How can I learn this topic more detaily?

  • @joshuathames1233
    @joshuathames1233 2 года назад +1

    What software/tablet or computer combination are you using to do your presentations so you can draw and things as you go? I’m a first time first year tech school teacher and would appreciate knowing if you didn’t mind sharing. Fantastic job on all your videos!!

    • @user-fh3jy6md3p
      @user-fh3jy6md3p 2 года назад +2

      Microsoft OneNote to do the inking, and Camtasia to capture the screen. Referenced from the first comment's reply.

  • @jogasingh1516
    @jogasingh1516 3 года назад

    Great information. I know this is silly of me asking ,but is there a gearbox were speed and torque increase at the same time.in one to one gear ratio

    • @TheBomPE
      @TheBomPE  3 года назад

      If a gearbox has a 1:1 ratio, then it's input speed will not be different from its output speed. As for torque, it would take an input of energy to have more torque output than is put in. You might think about a power steering system as an example of this.

    • @jogasingh1516
      @jogasingh1516 3 года назад

      @@TheBomPE
      Thank u for your kind input.will look into power steering box for idea

  • @johnboy4687
    @johnboy4687 2 года назад

    Which calculator app are you using Sir ? I am trying to find a similar one on apple app store but with no luck...

  • @husnainhyder6713
    @husnainhyder6713 4 года назад +1

    Dear Sir
    Lecture was great you have cleared a lot but one quick question
    you have shown the force on each gear along tangent line and applied newtons third law but what about Normal force
    won't their be any normal force between two gears
    please help us in this matter
    Thank you

    • @TheBomPE
      @TheBomPE  3 года назад +1

      Real gears do exert normal components of force as they transmit torque. I ignore this component in this lecture because it isn't relevant to computing gear ratios for speed and torque, and I'm teaching freshmen in this video. In my higher-level classes we discuss implications of the normal components of force, such as bearing reactions or shaft flexure. For instance, you might be interested in this video: ruclips.net/video/PSvgn2xVpjU/видео.html
      Thanks for watching!

    • @husnainhyder6713
      @husnainhyder6713 3 года назад

      @@TheBomPE
      Thanks alot
      God bless you

  • @fourseasonsportyli7414
    @fourseasonsportyli7414 3 года назад +1

    the angular speed (rpm) of 15 teeth and 47 teeth are the same as well as the torques on the two?

    • @TheBomPE
      @TheBomPE  3 года назад

      That's correct. They are actually a single body since they are rigidly joined. For this body to be in equilibrium, the torque input has to be the same as the torque output.

  • @negarhosseini6978
    @negarhosseini6978 Год назад +1

    thanks a lot

  • @bowaleadeyemi4642
    @bowaleadeyemi4642 2 года назад

    Thanks alo

  • @gurpreetsingh-ty6gw
    @gurpreetsingh-ty6gw 3 года назад

    If speed increase then friction of gears will be ?? Decrease or increase

  • @daneshmandalmandal765
    @daneshmandalmandal765 2 года назад

    Sir can u clear my doubts that 9.81 standard acceleration?how did u get 2.54cm/100?

  • @michaelswanbom6023
    @michaelswanbom6023 5 лет назад

    If you found this video useful, consider helping me upgrade the old tablet PC I use to create these videos! Thanks!
    www.gofundme.com/help-replace-my-2011-tablet-pc

  • @tomasm2945
    @tomasm2945 4 года назад

    HI, I have a gearing ratio math problem that I would appreciate your assistance. Is there someway I can message you privately as its a project I am working on?

  • @sundayrewire3863
    @sundayrewire3863 Год назад

    Am working on Toyota avensis with 10pin gear not counting the least gear no trouble code found

  • @dr.davidbannerf.e.s.6217
    @dr.davidbannerf.e.s.6217 8 месяцев назад

    What is the total change in forces acting upon two people sitting across from each other on a spinning Marble ride....that is traveling around a Circular Track??
    One person is on the side of the Marble that is forcing them to be spun with the SAME direction of the Ride itself....while at the same time, the other person on the other side of the Marble is being spun OPPOSITE the direction of the Ride itself. The ride itself is moving in Non-Uniform Motion around a Circular Track. The spin speed of the Marble forces the two people to switch positions every 12hours that goes by....
    Every 12hours one of them is being spun WITH the direction of the ride going around it's circular Track, while the other person 180degrees on the other side of the Marble ---- > is being spun the OPPOSITE direction of the ride going around it's circular Track. These are in fact Additions and Subtractions to the total Forces acting upon those Two people, whilst they are on that Spinning Marble Ride.
    The diameter of the Marble is 8,000miles.
    The speed of rotation is 1,000miles in one hour.
    The forward velocity and forced turn Momentum of the Marble ride, attached to the Central Pivoting Arm that the Marble ride is tethered to, forcing it go around in a Circular path ---- > 67,000miles in one hour. The Diameter of the Locked circular Track the Marble ride is going around with a Velocity of 67,000miles in one hour, is 186,000,000miles (93 million mile radius to Central Pivoting FULCRUM Point in the Center of the Sun).

    • @dr.davidbannerf.e.s.6217
      @dr.davidbannerf.e.s.6217 8 месяцев назад

      Now apply Physics and REALITY ---- > And then walk away from the Globespell entirely.

  • @PeterCroughsTongeren
    @PeterCroughsTongeren 2 года назад

    I don't get where the 9.81 m/s² comes from (39 minutes into the video).
    F = m . a
    24 inches is 60.96 cm or 0.61 m (rounded). So it should be 79 kg x 0.61 m/s² = 48,19 N(ewton)
    So in my opinion, your result is wrong.

    • @TheBomPE
      @TheBomPE  2 года назад

      You are welcome to that opinion. I can tell you that it is incorrect.

    • @PeterCroughsTongeren
      @PeterCroughsTongeren 2 года назад

      @@TheBomPE ok fine.. teach me... how do you get your figure?

    • @TheBomPE
      @TheBomPE  2 года назад

      @@PeterCroughsTongeren Weight is the force felt by a massive object due to gravitational acceleration. On earth, gravitational acceleration is roughly 9.81m/s^2. Calculating weight from mass using gravitational acceleration happens so frequently in engineering that after a while it is typically just done without explicit explanation or justification.

    • @PeterCroughsTongeren
      @PeterCroughsTongeren 2 года назад

      @@TheBomPE Thank you for your answer and I'm ashamed not have recognized the freefall velocity. But I still think you're off. The question was (correct me if I'm wrong) "What force do we need to apply to move the weight at a ration of 24 inches per second). When I apply your answer to a = F/m you get of course 9,81 m/s or 981 cm or 386 inches per second. So with your result when a force of 774.99 N is applied to the weight of 79 Kg, the weight has already moved 386 inches after one second and not the 24 inches we were looking for. But probably I must have missed something in the question. Thanks for being a good sport and taking the time to react.

  • @funy0n583
    @funy0n583 3 года назад

    why does he go into such depth about how gears physically interact in the beginning but then he says stuff like "non concurrent force systems"

    • @TheBomPE
      @TheBomPE  3 года назад

      Perhaps he knows about these topics and he enjoys helping others learn as well? As a colleague of his often reminds students: learning doesn't suck. When you are done scoffing you should try it out.

    • @funy0n583
      @funy0n583 3 года назад

      @@TheBomPE im just saying if you know what non concurrent force systems means you probably know how gears interact. im not scoffing at anybody its just this seemed like a pretty simple lecture until i was hit with such an alien series of words

    • @TheBomPE
      @TheBomPE  3 года назад

      I see. If you want to see this lecture in context, you might look at the series of lectures:
      ENGR 122: Engineering Problem Solving III: ruclips.net/p/PL1IHA35xY5H52IKu6TVfFW-BDqAt_aZyg
      You might learn why it is handy to have a shorthand way of saying "an arrangement of forces where the lines of action of the forces do not all intersect at a single point."

    • @funy0n583
      @funy0n583 3 года назад

      @@TheBomPE thank you this is actually very helpful. sorry about the misunderstanding