How is difficult when iam in my Textbook and how is easy when you speak to it, it's what you can't even imagine. thank you so much God bless you and god make you everythings easy as you make us🥰
If im not wrong the conjugate is required only for complex numbers(has both real n imaginary components),the 1st radical one was only sqrt 5i(only imaginary) so no conjugate was needed
@@mr.someone5679 Just so anyone has the same question, I figured I'd put down why (5)i^2 = -5. i = sqrt(-1) sqrt(-1)^2 = -1 Effectively, i^2 = -1 Thus, (5)i^2 (where "i" is sqrt(-1), thus i^2 is -1) = (5)(-1) = -5
The conjugate is the "same" number but you use the opposite sign for the imaginary part. Conjugate of 1+i is 1-i note that the sign is the opposite You only change the sign for the imaginary part. -3i+2 has the conjugate 2+3i NOT -3i-2. This is because -3i+2=2-3i it's just written differently.
I have never seen a person in my entire life write the letter "i" and make it look like the letter c honestly I am not able to take it seriously how hard is it to write a line and a dot
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Find the value of 𝑥 in the equation (5𝑥 − 2)
4
3 = 16
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How is difficult when iam in my Textbook and how is easy when you speak to it, it's what you can't even imagine.
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and god make you everythings easy as you make us🥰
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You can just invert the bottom complex number. Divide it with the magnitude and conjugate it. After that you can multiply them.
This is equivalent to converting the number into polar form, inverting the magnitude, and flipping the phase.
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2:41: What if the 3 was a negative. Would you change that to a positive?
Yes
what if the imaginary number (i) is i^3? Like for example, 4+8i/i^3?
i^3 = i^2*i=-i and then do the same thing as in the video
since i^2 = -1, i^3 simplifies to -1 * i
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Do you know who is this men
Why in the first question he only rationalize with iota and in other questions irrational iota with numbers
why don't you have the conjugate for the root in the first question where you rationalized the root?
If im not wrong the conjugate is required only for complex numbers(has both real n imaginary components),the 1st radical one was only sqrt 5i(only imaginary) so no conjugate was needed
After one week, I have a final Math
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At the 24 seconds mark in this video, how do you make the 5* i squared into -5?
i= root minus one. i squared =-1 5 i squared =-5. Hope that helps bro
@@21alia5 it does! I had missed the imagery number rule :)
5:55
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I dont understand why (5i)*2 is -5
Dont worry now i understand :)
@@mr.someone5679 Just so anyone has the same question, I figured I'd put down why (5)i^2 = -5.
i = sqrt(-1)
sqrt(-1)^2 = -1
Effectively, i^2 = -1
Thus, (5)i^2 (where "i" is sqrt(-1), thus i^2 is -1) = (5)(-1) = -5
Do you heard of conjugate
i don't get what complex conjugate is
The conjugate is the "same" number but you use the opposite sign for the imaginary part.
Conjugate of 1+i is 1-i note that the sign is the opposite
You only change the sign for the imaginary part. -3i+2 has the conjugate 2+3i NOT -3i-2.
This is because -3i+2=2-3i it's just written differently.
3:59 : pardon, of the what? Thank you!
denominator
@@танкист108 Thanks
Einstein 2.0
You have a degreee or phd ?
At 3:28
ruclips.net/video/EfRRpVB62Ko/видео.html
please correct misprint in denominator. That is 9 *minus* 4
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#distributiveproperty
Bruh imma fail pre calc this shit makes no sense
pog
I have never seen a person in my entire life write the letter "i" and make it look like the letter c honestly I am not able to take it seriously how hard is it to write a line and a dot
My math teacher is nothing compared to you
what
No
Mistakes her
You do the easiest variation of each topic very frustrating
Thank u