Can You Pass Oxford University's Entrance Exam?
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- Опубликовано: 30 сен 2024
- Solve for a,b,c - integers.
Entrance examination. If you're reading this ❤️.
What do you think about this problem?
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You should have emphasized that x*y=1 is equivalent to x,y = 1 or x, y = -1 only when it is 1 on the right and only when both x and y must be integer. I assume you're targeting not very expert audience (you used 3 lines to put -c out of brackets) and they may wrongly think one can do it for any numbers.
i think the key takeaway of the video is that despite there being possible solutions that aren't x,y = 1 or x,y = -1, the question did not strictly ask to find all solutions. but then again, my gut tells me this kind of question isn't something you'd find on an entrance exam, rather just something to train your versatility of thought and understanding.
a=0, c=2020, b=2021/2020
This is not an Oxbridge entrance exam test. It's written too poorly for a start.
This method only works if you assume that a b and c are integers ❔
eu acho que sim pois encontrei a em função de b e c, b em função de a e c e também c em função de a e b. substituindo c em função de a e b no b em função de c e a resta somente b em função de a se acha a = 1 e b = 1010 +- 12 sqrt(7070) e c = 1010 -+ sqrt(7070)
This should specify a, b, c are natural numbers. Also I find it a bit hard to believe this is an Oxford entrance exam question. They're usually a good deal more difficult than this.
Yeah. In my country, this would be a normal 10th grade question
Well it does not work like that, you know
Two comments. 1. I should have read the small print - a, b and c are integers! (my mistake obviously). 2. You explained your process clearly and nicely. However, why did you adopt that approach. Did you look at the problem and say: "well let's try refactoring to end up with a product of a, b and c equal to some constant"? I find that nearly all of these math problems have the same format - a nice demonstration going from start to solution. BUT NONE of them describe the thought process before starting the process. It would be valuable to know how you think about solving it.
I was progressing pretty well and arrived to the point where everything was nicely factored out just like in the video. TBH I added the equations up for the first try but figured out quite quickly that is a dead-end. So… when I had the two factors I got lost. Apparently did not read the description, so didn’t know all numbers must be integers. You can imagine…😂
Once I saw your comment I knew immediately where I made the mistake.
For the future it might be a good idea to explain all constraints in the video too, as not everybody reading the description.
To be an Oxford university exam is not so difficult, actually with a bit of creativity I' d dare to say that is quite easy 😂
I agree with the answers, but there are infinte amounts of numbers, which multiplied equal to one.
I am not sure, if this question has more answers, since I don't care about a random equation, which even a 9th grader can solve. At least in my country.
Integers are the solution unless the question specifies "real numbers".
@@pedrovargas2181 Ok
Where is the assumption that variables are integers??
There is another way to solve
I am in 10th and this question looked similar to the questions I had in my book...I solved it in 5 minutes😅😅
Is this even for Olympiad🤨🤔
Yeah same, I was thinking this is too easy
a=2021, b=0, c=2020
The answer should be a graph of y= 1/x which is infinite answers
According to WolframAlpha a=0, b=2021/2020, c=2020
a=2021, b=0, c=2021
1/2 x 2 = 1 ?
...wow...I DID IT...figured it out in a few secs without all that math!!!....sorry😐
С такими задачами обычно поступают в математический колледж.
I think i sorta get it, tho do i need to give multiple awnsers?
a=1; b=1; c=2020
Answer to 2024 is Donald J. TRUMP!!
That would be worth 0.
That would get you into Wharton if your rich father made a huuuuuge contribution.
There are three constants but only two equations. Solution not possible.
he meant to say only integer answers
He found 2 solutions
They aren’t unique