DCM 20 Swinburnes Test

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  • Опубликовано: 23 янв 2025

Комментарии • 16

  • @surendrakverma555
    @surendrakverma555 2 года назад

    Very good lecture Sir. Thanks 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

  • @roberttshitenda7878
    @roberttshitenda7878 2 года назад

    Good morning can explain how did you get the value of N1,the value of N2 is full load, please

  • @ShivarajKanavi-t4o
    @ShivarajKanavi-t4o Год назад

    Why we use small rating ammeter?

  • @rittikbiswas
    @rittikbiswas 4 года назад

    Swinburne test is applicable for dc motor and dc generator?

  • @raghunandhanreddy5181
    @raghunandhanreddy5181 3 года назад +1

    Sir what is Wc loss

  • @atanudey6507
    @atanudey6507 4 года назад

    Sir since we use it for no load purpose, at that instant the load current is also constant and also the flux is also constant then why it is not used in series motor?

    • @mahesh-xc8tw
      @mahesh-xc8tw 2 года назад

      You can't run series motor in no load

  • @12jodyt29
    @12jodyt29 4 года назад

    Sir output = 20000-1152-1995.5 ?
    How does you get the equation.

    • @12jodyt29
      @12jodyt29 4 года назад

      I got it.

    • @bingisantoshi5238
      @bingisantoshi5238 2 года назад

      Efficiency =( vi-( i2 Ra+pc) ) /vi
      Pc is nothing but total constant losess

  • @gorumutchuspandana4828
    @gorumutchuspandana4828 5 лет назад +1

    Sir. Rac=1.2×Ra whar it means

  • @rohithnv9473
    @rohithnv9473 3 года назад

    Sir please make problem on temperature conditions sir

  • @vasdgod
    @vasdgod 2 года назад

    13:00

  • @raghunandhanreddy5181
    @raghunandhanreddy5181 3 года назад

    We are getting confused in losses

  • @singamsettymuniswamy9502
    @singamsettymuniswamy9502 2 года назад

    🙏🙏🙏🙏🙏