Hello sir, your videos are so great and helpful. Thankyou so much. Can you please share a question bank as well, from where we can practice. All the questions that you discuss are so of such great quality, getting a question bank too would be so helpful
I m urbiggest fan sir.whatever u r doing is fabulous but i would like to remind u to solve atleast 12 difficut questions on trapezium.so that it can cover all difficult portion trapezium.it is my humble request to u.
Sir, if we us the properties of mid pt theorem,in triangle POK where K is perpendicular on SR, and the height turns out to be 3. Then when we put a perpendicular on SR to O then PK || OJ, so OJ=1/2 PK. will it be wrong
You, yes you who is reading this comment. You can do it and you will do it. 99%ile+ is waiting for you.
You are so sweet❤️
Full power
Likewise brother🤍
76k People saw this video, if everyone is fucking getting 99 toh meh kya halwa
@@friedsugar2701 hahaha...savage reply.
Sir you made a small mistake in the last sum... It's (50+66) /2 ×3√21 = 174 √21
yup
Yeah
Apply BODMAS.
Ye un bacho me se hai jinhe sab aata hota h par fir bhi paper me fail hote hai 🤣
yes
In the last question, during the last part while taking the area you have taken 60 instead of 66.
Hahaha you always wanted the other side to be 60 😂
Yeah.. Nice catch😂😂😂
So truee😂
May be sir's roll number always would be 60 that' why😂
LOL
🤣🤣🤣🤣🤣
Once you say "it's good question", i will stop my way of thinking about solution and continue the video 😂😂
U r "__the__" Ravi Prakash sir no one can explain like u
Ye galtiya nikalne wale yehi karte reh jayenge 😅😅 Brilliant lecture as always sir 🙌🏻🙌🏻
Hello sir, your videos are so great and helpful. Thankyou so much. Can you please share a question bank as well, from where we can practice. All the questions that you discuss are so of such great quality, getting a question bank too would be so helpful
Had u cleared the cat btw i.also preparing for cat 2k24
In the last part. The Area of Trapezium= Have to use 66 instead of 60.And the area comes out to be 174 √21
Yes you are correct.
I m urbiggest fan sir.whatever u r doing is fabulous but i would like to remind u to solve atleast 12 difficut questions on trapezium.so that it can cover all difficult portion trapezium.it is my humble request to u.
where can I get your polygon lectures? I am not able to find it. Please help me out
We can also take y as 16-x. Would be easier to solve the last question.
Thanks sir......
Sir can you please add video for polygons questions too where questions on hexagon is there.. or if you have added recently can anyone share the link?
No video on polygons sir? :/
In last question how come x+y=16?
2nd parallel side was 66.
So 50+x+y=66
X+y=16
Sir,please upload more videos of geometry, and also upload trigonometry.
sir coordinate bhi padha do pls
Happy teacher's day sir
Amazing content sir. Thankyou♥️
Is there video quadrilateral 4. Provide link if there is.
No I guess..
apply the formula of area of general quad
Thank you sir for these questions
At the end in area formula value of parallel sides is wrong it is given 50+60
correct it actual value is 50+66
For area of trapezium in last ques, won't we take the longer parallel side as 66? Instead of 60
In the last question, during the last part while taking the area you have taken 60 instead of 66.
sir in last question, at 13:00 min.
why cant we find height using pythagorus triplet 8,15,17?
because then the height would be 15 for the other triangle as wont sit right with pythagoras theorem
Today trapezium has become clear to me
Sir, if we us the properties of mid pt theorem,in triangle POK where K is perpendicular on SR, and the height turns out to be 3. Then when we put a perpendicular on SR to O then PK || OJ, so OJ=1/2 PK. will it be wrong
Yes because it is not mentioned that J is the mid point so applying this will be wrong
Thank you so much sir.❤❤
thanku sir
Thanku sir
Sir where did 5/9 come from at 4.54
Thank you 🙏
Sir the 2nd side is 66 , but u have written 60 while finding the area
It's a typing mistake by Sir. So neglect that. But your answer is right
I wish the video had the same volume as the ads in between.
Just download it and then watch no ads then!:)
I dont understand why people hates ad on free forum. If you have problem with ads then join some expensive coaching classes to get rid of ads. :-)
ye dislikers kon hn?
Sir what if instead of 15&6 for finding H. If we use 17&10
Same ans , we have find.
The answer will be same (17)*2 - (10)*2 = H*2 i.e H*2 = 289 - 100 ....H = √189