Agreed. I think lack of space for proper working is a frequent problem. But you can ask for more paper during the exam - and I recommend that you do this!
thank you for making these videos, I regretted not dropping addmath and my add math igcse coming in 6/10 and I am failing, any tips for last minute studying?
First, well done for not dropping the subject. I think that one of the major benefits in studying Add Math is that it teaches many students the value of perseverance. So I'm glad that you haven't dropped, even though it is a very demanding subject. Second, since I don't know you, my advice may not be appropriate for you. However, if I had to give advice, I would suggest that you ensure your fundamentals are strong before you do anything else. That means you should aim to be confident in manipulating logarithms, indices, and differentiating and integrating the basic functions (to name just a few). If you need to go through the exercises in your textbook again, then do that. But if your fundamentals are fairly good, then I would recommend doing past paper questions. Doing questions by topic can be helpful if you feel especially weak in that area, but I would suggest you try to attempt full papers under timed conditions as soon as possible. Finally, I'm so glad if you have found these videos helpful, but make sure you have attempted the questions by yourself first before you get help. That will help you to study the most effectively, because you will learn from your mistakes. Good luck with the Oct/Nov papers! I hope you will have the opportunity to flourish.
@@themathmanYT wow thank you for the kind words. Really appreciate that you took your time writing this and uploading the vids. im currently at final year of high school taking ig this nov and from malaysia
@@themathmanYT and I looked at your channel and you only recently started posting 2023 past years which is REALLY helpful cuz other youtubers havent publish yet. May i know why did you suddenly wanted to start?
I started because my students kept asking me to explain the same exam questions to them, so I thought recording videos would be a more efficient way to explain! I'm also in Malaysia, by the way! 🇲🇾
hi, in q7 (b), when the first digit is 5, shouldnt we have 4 ways of choosing the last digit since the number should be > than 500 000 and not equal to it?
Great question. In response, let me ask you this: is 500,001 greater than 500,000? In other words, can a six digit number can start with a 5 and be greater than 500,000?
hi, i find this subject really challenging and i wanted to drop it but i nedd for what i want to study. i am writing the first paper tomorrow, im so scared
OK, I think I understand now. There is a range of values for theta, and I apologise for being a bit lazy about that. Basically, you can take the inequality -pi < phi < pi and substitute into that the substitution phi = (theta + 3pi/4)/2. If you rearrange the inequality, you can then find your range of values in terms of theta.
Sure. I answered a similar question below, so I'll just copy-paste. There is a range of values for theta (my substituted variable), and I apologize for being a bit lazy about not stating that. Basically, you can take the inequality -pi < phi < pi and substitute into that the substitution phi = (theta + 3pi/4)/2. If you rearrange the inequality, you can then find your range of values in terms of theta. This is -2pi - 3pi/4 < theta < 2pi + 3pi/4. Within this range there are four values of theta.
this question may be a bit silly but for question 3b if for example the inequality was to be |5x-2| ≤ 4x+1 instead would you only squre the side with the modulus? And what if both sides do not have a modulus, can you still solve by squaring? and if so, how? Just curious as other methods are pretty confusing which is why I want to see if I can apply this method to all inequality questions that are similar to this
Hi. I've thought a little bit about how to answer this, but I'm afraid I might confuse you further. First, whenever you're dealing with an equation (or an inequality), whatever you do to one side, you must do to the other. If you add 3 to the left, you must add 3 to the right; if you multiply the right by 4, you must multiply the left by 4. This applies to squaring - if you square the left, you must square the right. However, there is a caveat here when it comes to inequalities, because whenever we multiply an inequality by a negative number, we must flip the sign of the inequality. Therefore, if we square a negative number, that means we are multiplying by a negative number, and so the sign must flip. The example below should illustrate this. We know that 2 is greater than -3. 2 > -3 Now, if we squared both sides: 2^2 > (-3)^2 4 > 9 (clearly not right, since 9 is greater than 4!) Why did this happen? Because we multiplied the right by a negative number (-3), and so we should have flipped the inequality sign to give 4 < 9. This is a long-winded way of saying that you need to be careful with your algebra in these questions, and I would caution you against trying to solve them purely with algebraic methods. Instead, if you sketch a graph of your functions, you should be able to see your solutions more clearly (and you can check your algebra). I know that probably doesn't make things simpler for you, but I didn't want to give you a simple answer that was only half true.
@@themathmanYT thank you for the explanation, I think the explanation on when multiplying by a negative number that it flips the sign helps solve most of my confusion as I was always confused on when the sign should be flipped.. will still be sketching out a rough graph just in case
Good question. I could have drawn the negative side (and probably should have done - apologies for that!). However, I only need to find the intersection points for one sine wave in order to know the intersections for all the other waves - whether going forward or backward (i.e. to the negative side). This is because I can either add or subtract 2pi to each solution, since the sine wave repeats every 2pi. So basically, it probably would have been helpful for me to draw the negative side to make things clearer, but it isn't absolutely necessary either. 🙂 Good luck today!
Good question. In the first part of the question it says "it is given that f(x) = f-1(x) has two solutions". Each solution is an intersection point, hence I know the graphs will intersect twice.
Thanks for the response, however I thought "solution" refers to the assignment of values to the unknown variables that makes the equality in the equation true. In most cases the "x" value. So, in this type of question (inverse function) does the word "solution" mean the intersection point?@@themathmanYT
Clicked expecting Batman Begins voiceover. I have never been more disappointed to not be met with my expectations.
I hate to disappoint you further, but life gets a lot more disappointing than that. Have a good day. 😀
bruh then go watch batman movies not to yapping around here
Been watching your videos for less than a week one and I've learnt more from you in these few days than i have during the whole year of school 😭
I'm so glad you've found the videos helpful.
Do you give online tuitions/sessions ??? 😭
Thank you for this video it really help alot
Glad it helped. Good luck with your studies.
Cambridge is really selfish for giving us half a page for question 9b's working
Agreed. I think lack of space for proper working is a frequent problem. But you can ask for more paper during the exam - and I recommend that you do this!
It wasn’t half page there was another page after and written on it was ‘Continuation of working space for Question 9’
thank you for making these videos, I regretted not dropping addmath and my add math igcse coming in 6/10 and I am failing, any tips for last minute studying?
First, well done for not dropping the subject. I think that one of the major benefits in studying Add Math is that it teaches many students the value of perseverance. So I'm glad that you haven't dropped, even though it is a very demanding subject.
Second, since I don't know you, my advice may not be appropriate for you. However, if I had to give advice, I would suggest that you ensure your fundamentals are strong before you do anything else. That means you should aim to be confident in manipulating logarithms, indices, and differentiating and integrating the basic functions (to name just a few). If you need to go through the exercises in your textbook again, then do that.
But if your fundamentals are fairly good, then I would recommend doing past paper questions. Doing questions by topic can be helpful if you feel especially weak in that area, but I would suggest you try to attempt full papers under timed conditions as soon as possible.
Finally, I'm so glad if you have found these videos helpful, but make sure you have attempted the questions by yourself first before you get help. That will help you to study the most effectively, because you will learn from your mistakes.
Good luck with the Oct/Nov papers! I hope you will have the opportunity to flourish.
@@themathmanYT wow thank you for the kind words. Really appreciate that you took your time writing this and uploading the vids. im currently at final year of high school taking ig this nov and from malaysia
@@themathmanYT and I looked at your channel and you only recently started posting 2023 past years which is REALLY helpful cuz other youtubers havent publish yet. May i know why did you suddenly wanted to start?
I started because my students kept asking me to explain the same exam questions to them, so I thought recording videos would be a more efficient way to explain!
I'm also in Malaysia, by the way! 🇲🇾
@@themathmanYT im glad your students kept asking you haha. But you dont sound like a malaysian? are you from other countries?
hi, in q7 (b), when the first digit is 5, shouldnt we have 4 ways of choosing the last digit since the number should be > than 500 000 and not equal to it?
Great question. In response, let me ask you this: is 500,001 greater than 500,000? In other words, can a six digit number can start with a 5 and be greater than 500,000?
@@themathmanYT i get it now, thank you!
Jolly good!!!
hi, i find this subject really challenging and i wanted to drop it but i nedd for what i want to study. i am writing the first paper tomorrow, im so scared
me too! Best of luck to you!!
Good luck! I hope that you do well and can progress to what you want to do next.
@@vivian6481thank you and best of luck to you too
@@themathmanYTthank you
@@vivian6481how was the exam
Hiii i wanted to confirm if there's another questions similar to 3a, i should put a constant always?
Yes, always. It will also remind you that the constant can be negative.
where have you been all my life
thank you g
Most welcome
Hello in the question 6b what happens to the range for both the unknowns?
Hi. I'm so sorry, but I don't quite understand your question. Are you sure you mean Q6b?
@@themathmanYT it is because u subbed theta in is there no range for theta?
OK, I think I understand now. There is a range of values for theta, and I apologise for being a bit lazy about that. Basically, you can take the inequality -pi < phi < pi and substitute into that the substitution phi = (theta + 3pi/4)/2. If you rearrange the inequality, you can then find your range of values in terms of theta.
-2pi - 3pi/4 < theta < 2pi + 3pi/4
@@themathmanYTOKAY thanks man
hi can i know how in question 6b have 4 angles
Sure. I answered a similar question below, so I'll just copy-paste.
There is a range of values for theta (my substituted variable), and I apologize for being a bit lazy about not stating that. Basically, you can take the inequality -pi < phi < pi and substitute into that the substitution phi = (theta + 3pi/4)/2. If you rearrange the inequality, you can then find your range of values in terms of theta. This is -2pi - 3pi/4 < theta < 2pi + 3pi/4. Within this range there are four values of theta.
this question may be a bit silly but for question 3b if for example the inequality was to be |5x-2| ≤ 4x+1 instead would you only squre the side with the modulus? And what if both sides do not have a modulus, can you still solve by squaring? and if so, how? Just curious as other methods are pretty confusing which is why I want to see if I can apply this method to all inequality questions that are similar to this
Hi. I've thought a little bit about how to answer this, but I'm afraid I might confuse you further.
First, whenever you're dealing with an equation (or an inequality), whatever you do to one side, you must do to the other. If you add 3 to the left, you must add 3 to the right; if you multiply the right by 4, you must multiply the left by 4.
This applies to squaring - if you square the left, you must square the right. However, there is a caveat here when it comes to inequalities, because whenever we multiply an inequality by a negative number, we must flip the sign of the inequality. Therefore, if we square a negative number, that means we are multiplying by a negative number, and so the sign must flip. The example below should illustrate this.
We know that 2 is greater than -3.
2 > -3
Now, if we squared both sides:
2^2 > (-3)^2
4 > 9 (clearly not right, since 9 is greater than 4!)
Why did this happen? Because we multiplied the right by a negative number (-3), and so we should have flipped the inequality sign to give 4 < 9.
This is a long-winded way of saying that you need to be careful with your algebra in these questions, and I would caution you against trying to solve them purely with algebraic methods. Instead, if you sketch a graph of your functions, you should be able to see your solutions more clearly (and you can check your algebra).
I know that probably doesn't make things simpler for you, but I didn't want to give you a simple answer that was only half true.
@@themathmanYT thank you for the explanation, I think the explanation on when multiplying by a negative number that it flips the sign helps solve most of my confusion as I was always confused on when the sign should be flipped.. will still be sketching out a rough graph just in case
Great! Good luck next week!
Sir found make more videos on this type of trigonometry
Hi! for question 6b, when drawing the graph, why did you only draw for the positive side? What happened to the negative side?
Good question. I could have drawn the negative side (and probably should have done - apologies for that!). However, I only need to find the intersection points for one sine wave in order to know the intersections for all the other waves - whether going forward or backward (i.e. to the negative side). This is because I can either add or subtract 2pi to each solution, since the sine wave repeats every 2pi.
So basically, it probably would have been helpful for me to draw the negative side to make things clearer, but it isn't absolutely necessary either. 🙂
Good luck today!
heii vivian, are you going to give your igcse in this may?
@@xia_liang i have answered already! 2023 oct/nov
@@vivian6481awww that was unexpected. hoep that went great!!
Teach me bro
i want to be your student
And thank you a lot for the video
Thanks! For tuition inquiries, email themathmanYT@gmail.com
in 8C how do you know if the inverse function and the original will intersect twice?
Good question. In the first part of the question it says "it is given that f(x) = f-1(x) has two solutions". Each solution is an intersection point, hence I know the graphs will intersect twice.
Thanks for the response, however I thought "solution" refers to the assignment of values to the unknown variables that makes the equality in the equation true. In most cases the "x" value. So, in this type of question (inverse function) does the word "solution" mean the intersection point?@@themathmanYT
In question 6a why does x-4 become squared?
Hi. Sorry for the slow reply. You square it because you want to use the identity sec2 = 1 + tan2, hence you need a sec squared.
this is 4037 add maths not 0606
0606 is IGCSE, 4037 is O Level (I think?). They often use very similar exam papers. :-)
@@themathmanYT yes but this specific paper is code 4037 as I gave the exam, I think 0606 has different questions
@@ahnafsaminmizan7314indeed
I've checked this just now. The two papers are identical.
@@themathmanYT what the hell, one Could just practice igcse papers and then get the exact same thing